Tìm X biết X x 2 x 3 = 1056
Tìm X biết X x 2 x 3 = 1056
Xx2 x3 = 1056
Xx2 = 1056 : 3
Xx2 = 352
X= 352 : 2
X=176
Tìm x, biết
a, 3 mũ x + 2 - 5 . 3 mũ x = 36
b, 7.4 mũ x-1 + 4 mũ x+1 = 23
c, 2.2 mũ 2x + 4 mũ 3 . 4 mũ x = 1056
tìm x, biết x là số tự nhiên
b)2.3^x=162
c)(2x-15)^5=(2x-15)^3
d)3^(x+2) -5.3^x
e)7.4^(x-1)+4(x+1)=23
f)2.2^(2x)+4^3.4^x=1056
10 -{[(x:3+17):10+3.2^4]:10}=5
gấp, mọi ng giúp mình với
`#3107`
b)
`2.3^x = 162`
`\Rightarrow 3^x = 162 \div 2`
`\Rightarrow 3^x = 81`
`\Rightarrow 3^x = 3^4`
`\Rightarrow x = 4`
Vậy, `x = 4`
c)
`(2x - 15)^5 = (2 - 15)^3`
\(\Rightarrow \)`(2x - 15)^5 - (2x - 15)^3 = 0`
\(\Rightarrow \)`(2x - 15)^3 . [ (2x - 15)^2 - 1] = 0`
\(\Rightarrow\left[{}\begin{matrix}\left(2x-15\right)^3=0\\\left(2x-15\right)^2-1=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}2x-15=0\\\left(2x-15\right)^2=1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}2x=15\\\left(2x-15\right)^2=\left(\pm1\right)^2\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{15}{2}\\2x-15=1\\2x-15=-1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{15}{2}\\2x=16\\2x=-14\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{15}{2}\\x=8\\x=-7\end{matrix}\right.\)
Vậy, `x \in`\(\left\{-7;8;\dfrac{15}{2}\right\}.\)
`d)`
\(3^{x+2}-5.3^x=?\) Bạn ghi tiếp đề nhé!
`e)`
\(7\cdot4^{x-1}+4^{x-1}=23?\)
\(4^{x-1}\cdot\left(7+1\right)=23\\ \Rightarrow4^{x-1}\cdot8=23\\ \Rightarrow4^{x-1}=\dfrac{23}{8}\)
Bạn xem lại đề!
`f)`
\(2\cdot2^{2x}+4^3\cdot4^x=1056\)
\(\Rightarrow2\cdot2^{2x}+\left(2^2\right)^3\cdot\left(2^2\right)^x=1056\\ \Rightarrow2\cdot2^{2x}+2^6\cdot2^{2x}=1056\\ \Rightarrow2^{2x}\cdot\left(2+2^6\right)=1056\\ \Rightarrow2^{2x}\cdot66=1056\\ \Rightarrow2^{2x}=1056\div66\\ \Rightarrow2^{2x}=16\\ \Rightarrow2^{2x}=2^4\\ \Rightarrow2x=4\\ \Rightarrow x=2\)
Vậy, `x = 2`
_____
\(10 -{[(x \div 3+17) \div 10+3.2^4] \div 10}=5\)
\(\Rightarrow\left[\left(x\div3+17\right)\div10+48\right]\div10=10-5\)
\(\Rightarrow\left[\left(x\div3+17\right)\div10+48\right]\div10=5\)
\(\Rightarrow\left(x\div3+17\right)\div10+48=50\)
\(\Rightarrow\left(x\div3+17\right)\div10=2\)
\(\Rightarrow x\div3+17=20\)
\(\Rightarrow x\div3=3\\ \Rightarrow x=9\)
Vậy, `x = 9.`
X x 2 x 3 = 1056 khi đó x =
x*2*3 = 1056
x*(2*3) = 1056
x*6 = 1056
x = 1056 : 6
x = 176
X x 2 x 3 = 1056
x = 1056 : 3 : 2
x = 176
X x 2 x 3 = 1056
X x 6 = 1056
X = 1056 : 6
X = 176
Vậy X x 2 x 3 = 1056 thì khi đó X = 176
:D
Tìm x thuộc n
x^6 : x^3 =125
(2x-15)^4=(2x-15)^3
3^x+2-5.3^x=36
2.2^2x+4^3.4^x=1056
7.4^x-1+4^x+1=23
x6:x3=125
x6-3=125
x3=125
x3=53
x=5
vậy x=5
x*2*3=1056 khi đó x=
x*2*3=1056
x*(2*3) = 1056
x*6 = 1056
x = 1056 : 6
x = 176
vậy x = 176
x*2*3=1056
x*6=1056
x=1056:6
x=176
vậy x=176
Tìm x
2.22x+43.4x=1056
2.22x + 43.4x = 1056
=> 2.4x + 43.4x = 1056
=> 4x [2 + 43] = 1056
=> 4x . 66 = 1056
=> 4x = 16
=> x = 2
X x 2 x 3 = 1056
X x 2 x 4 =1960
X x 5 + 148 = 1338
500 + X x 4 =940
X x 2 x 3 = 1056
X x 6 = 1056
X=1056:6
X=176
X x 2 x 4 =1960
Xx6=1906
x=1906:6
x=953/3
X x 5 + 148 = 1338
Xx5=1338-148
Xx5=1190
X=1190:5
X=238
500 + X x 4 =940
X x4=940-500
Xx4=440
X=440:4
X=110
1.X * 2 * 3 = 1056
X =1056 : 3 : 2
X=176
2.X*2*4=1960
=1960 : 4 :2
=245
3.X * 5 + 148=1338
=(1338 - 148):5
=238
4.500 + X * 4 = 940
500 + X = 940 : 4
500 + X =235
X =235 - 500
X = -265
X x 2 x 3 = 1056
X x 6 = 1056
X = 1056 :6
X = 176
X x 2 x 4 = 1960
X x 8 = 1960
X = 1960 :8
X = 245
X x 5 + 148 = 1338
X x 5 = 1338 - 148
X x 5 = 1190
X = 1190 : 5
X = 292
500 + X x 4 = 940
X x 4 = 940 - 500
X x 4 = 440
X = 440 : 4
X = 110
tìm x thuộc N ai giải được mình tick cho
2.22x+43.4x=1056
7.4x-1+4x+1=23
3x+2-5.3x=36
\(=>2\cdot4^x+64\cdot4^x=1056\)
\(=>4^x\cdot\left(2+64\right)=1056\)
\(=>4^x=1056:66=16\)
\(=>4^x=4^2\)
\(=>x=2\)
ti ck nha
2.22x + 43.4x = 1056
=> 2.4x + 43.4x = 1056
=> (2 + 64).4x = 1056
=> 66.4x = 1056
=> 4x = 1056 : 66
=> 4x = 16
=> 4x = 42
=> x = 2
7.4x - 1 + 4x + 1 = 23
=> 7.4x.1/4 + 4x.4 = 23
=> (7/4 + 4).4x = 23
=> 23/4.4x = 23
=> 4x = 23 : 23/4
=> 4x = 4
=> x = 1
3x + 2 - 5.3x = 36
=> 3x.9 - 5.3x = 36
=> 3x.(9 - 5) = 36
=> 3x.4 = 36
=> 3x = 36 : 4
=> 3x = 9 = 32
=> 3x = 2
\(7\cdot4^{x-1}+4^{x+1}=23\)
\(=>7\cdot4^x:4+4^x\cdot4=23\)
\(=>\frac{7}{4}\cdot4^x+4^x\cdot4=23\)
\(=>4^x\cdot\left(\frac{7}{4}+4\right)=23\)
\(=>4^x=23:\frac{23}{4}=4\)
\(=>4^x=4^1\)
\(=>x=1\)