\(\frac{125^{2^{ }}.5^4}{25^{4^{ }}}\)
\(\frac{81^{2^{ }}.27^3}{9^8}\)
a,\((\frac{32}{81})^2.\left(\frac{-9}{8}\right)^5.\left(-4\right)^3̣\)
b,\(\left(-25\right)^5:125^2:\left(-5\right)^3\)
c,\(\left(\frac{8}{27}\right)^3:\left(\frac{-2}{3}\right)^8\)
LŨY THỪA
Bài 1: Tính
\(1.\frac{16^2}{4^5}\) \(17.\frac{9^3}{81^4}\)
\(2.\frac{4^5}{8^3}\) \(18.\frac{8^4}{4^3}\)
\(3.\frac{16^6}{8^3}\) \(19.\frac{8^4}{2^3}\)
\(4.\frac{32^3}{16^5}\)
\(5.\frac{32^5}{64^6}\)
\(6.\frac{27^5}{9^4}\)
\(7.\frac{9^6}{27^5}\)
\(8.\frac{81^5}{9^6}\)
\(9.\frac{27^4}{81^5}\)
\(10.\frac{81^5}{27^6}\)
\(11.\frac{25^6}{125^3}\)
\(12.\frac{4^7}{8^3}\)
\(13.\frac{8^4}{16^3}\)
\(14.\frac{8^5}{64^3}\)
\(15.\frac{16^6}{8^4}\)
\(16.\frac{8^8}{4^6}\)
bài 2 viết mỗi tích, thương sau dưới dạng luỹ thừa
a) 4^10 x 2^30 b) 9^25 x 27^4 x 81^3 c) 25^50 x 125^5 d) 64^3 x 4^8 x 16^4
e)3^8:3^6 ; 2^10:8^3 ; 12^7 :6^7 ; 31^5 ; 81^3
f) 5^8 : 25^2 ; 4^9:64^2 ; 2^25 : 32^4 ; 125^3 : 25^4
a, 410. 230=220.230=250
b,925.274.813= 350.312.312=374
Tương tự các câu khác....
a, 410.230 = (22)10.230 = 220.230 = 250
b, 925.274.813 = (32)25.(33)4.(34)3 = 350.312.312 = 374
c, 2550.1255 = (52)50.(53)5 = 5100.515 = 5115
d, 643.48.164 = (26)3.(22)8.(24)4 = 218.216.216 = 250
e, 38 : 36 = 32
210 : 83 = 210 : (23)3 = 210 : 29 = 2
127 : 67 = (12 : 6)7 = 27
@Dương Tuyết Mai
Tính:
a) A=\(\frac{3-\frac{1}{2}+\frac{1}{4}}{\frac{2}{3}-\frac{5}{6}+\frac{-3}{4}}\)
b) B=\(\frac{8-\frac{8}{5}+\frac{8}{25}-\frac{8}{125}}{9-\frac{9}{5}+\frac{9}{25}-\frac{9}{125}}:\frac{161616}{151515}\)
Ai nhanh và đúng nhất mk sẽ tick cho
tk mn
Tính giá trị của biểu thức:
\(A\)=\(\frac{4^5.4^6}{2^{21}}\); \(B=\frac{8^5+16^{13}}{4^3}\); \(C=\frac{125^{12}}{5^{13}.25^{10}}\)
\(D=\frac{81^{11}.3^{17}}{27^{10}.9^{15}}\); \(E=\frac{15.3^{11}+4.27^4}{97}\); \(F=\frac{5.2^{13}.4^{11}-16^9}{3.\left(2^{17}\right)^2}\)
Tính:
a) \(A=\frac{\frac{7}{8}+\frac{7}{27}-\frac{7}{49}}{\frac{11}{8}+\frac{11}{27}-\frac{11}{49}}\)
b)\(B=\frac{\frac{8}{9}-\frac{8}{27}-\frac{8}{81}+\frac{8}{243}}{4-\frac{4}{3}-\frac{4}{9}+\frac{4}{27}}\)
c)\(C=\frac{\frac{2}{7}+\frac{2}{5}+\frac{2}{17}-\frac{2}{293}}{\frac{3}{7}+\frac{3}{5}+\frac{3}{17}-\frac{3}{293}}\)
\(c)\) \(C=\frac{\frac{2}{7}+\frac{2}{5}+\frac{2}{17}-\frac{2}{293}}{\frac{3}{7}+\frac{3}{5}+\frac{3}{17}-\frac{3}{293}}\)
\(C=\frac{2\left(\frac{1}{7}+\frac{1}{5}+\frac{1}{17}-\frac{1}{293}\right)}{3\left(\frac{1}{7}+\frac{1}{5}+\frac{1}{17}-\frac{1}{193}\right)}\)
\(C=\frac{2}{3}\)
Bạn Cô nàng Thiên Bình làm đúng hết òi =.=
a=7.[1/8+1/27-1/49]
------------------------
11.[1/8+1/27-1/49]
=7/11
cau b,c tuong tu nha h mk
a)\(A=\frac{\frac{7}{8}+\frac{7}{27}-\frac{7}{49}}{\frac{11}{8}+\frac{11}{27}-\frac{11}{49}}\)
\(A=\frac{7.\left(\frac{1}{8}+\frac{1}{27}-\frac{1}{49}\right)}{11.\left(\frac{1}{8}+\frac{1}{27}-\frac{1}{49}\right)}\).
\(A=\frac{7}{11}\)
b)\(B=\frac{\frac{8}{9}-\frac{8}{27}-\frac{8}{81}+\frac{8}{243}}{4-\frac{4}{3}-\frac{4}{9}+\frac{4}{27}}\)
\(B=\frac{\frac{8}{9}.\left(1-\frac{1}{3}-\frac{1}{9}+\frac{1}{27}\right)}{4.\left(1-\frac{1}{3}-\frac{1}{9}+\frac{1}{27}\right)}\)
\(B=\frac{8}{9}:4=\frac{2}{9}\)
c)\(C=\frac{\frac{2}{7}+\frac{2}{5}+\frac{2}{17}-\frac{2}{293}}{\frac{3}{7}+\frac{3}{5}+\frac{3}{17}-\frac{3}{293}}\)\(C=\frac{2.\left(\frac{1}{7}+\frac{1}{5}+\frac{1}{17}-\frac{1}{239}\right)}{3.\left(\frac{1}{7}+\frac{1}{5}+\frac{1}{17}-\frac{1}{239}\right)}\)
C=\(\frac{2}{3}\)
Thuc hien phep tinh:
a/\(\frac{\frac{1}{9}-\frac{1}{7}-\frac{1}{11}}{\frac{4}{9}-\frac{4}{7}-\frac{4}{11}}\)+ \(\frac{0,6-\frac{3}{25}-\frac{3}{125}-\frac{3}{625}}{\frac{4}{5}-0,16-\frac{4}{125}-\frac{4}{625}}\)
b/ \(\frac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}-\frac{5^{10}.7^3-25^5.49^2}{\left(125.7\right)^3+5^9.14^3}\)
giúp tui với : -8 . 25 . ( -2 ) . ( -25 ) .4 .125
Bài 1 : Tính
a) A = \(\frac{\frac{1}{12}-\frac{2}{9}-1}{\frac{5}{18}-\frac{-3}{4}-\frac{1}{9}}\)
Bài 2 : Tính
a) A = \(\frac{3-\frac{1}{2}+\frac{1}{4}}{\frac{2}{3}-\frac{5}{6}+\frac{-3}{4}}\) b) B = \(\frac{8-\frac{8}{5}+\frac{8}{25}-\frac{8}{125}}{9-\frac{9}{5}+\frac{9}{25}-\frac{9}{125}}\): \(\frac{161616}{151515}\)
A=\(\frac{9}{8}-\frac{8}{9}+\frac{3}{25}+\frac{1}{4}-\frac{5}{16}+\frac{19}{25}-\frac{1}{9}+\frac{2}{25}-\frac{1}{81}\)
GIẢI GIÚP MÌNK NHÉ!
\(A=\frac{9}{8}-\frac{8}{9}+\frac{3}{25}+\frac{1}{4}-\frac{5}{16}+\frac{19}{25}-\frac{1}{9}+\frac{2}{25}-\frac{1}{81}\)
\(A=\left(\frac{9}{8}+\frac{1}{4}-\frac{5}{16}\right)-\left(\frac{8}{9}+\frac{1}{9}-\frac{1}{81}\right)+\left(\frac{3}{25}+\frac{19}{25}+\frac{2}{25}\right)\)
\(A=\frac{17}{16}-\frac{80}{81}+\frac{24}{25}\)
\(A=\frac{33529}{32400}\)