Bài làm :

Ta có :

\(\frac{2^{15}.9^4}{6^7.8^3}=\frac{2^{15}.\left(3^2\right)^4}{\left(2.3\right)^7.\left(2^3\right)^3}=\frac{2^{15}.3^8}{2^7.3^72^9}=\frac{3}{2}\)

Bài làm :

\(\frac{2^{15}.9^4}{6^7.8^3}\)

\(=\frac{2^{15}.\left(3^2\right)^4}{\left(2.3\right)^7.\left(2^3\right)^3}\)

\(=\frac{2^{15}.3^8}{2^7.3^7.2^9}\)

\(=\frac{3}{2}\)

Học tốt nhé

\(\frac{2^{15}.9^4}{6^7.8^3}\)\(=\frac{2^{15}.\left(3^2\right)^4}{\left(2.3\right)^7.\left(2^3\right)^3}\)\(=\frac{2^{15}.3^8}{2^7.3^7.2^9}\)\(=\frac{2^{15}.3^8}{2^{16}.3^7}\)\(=\frac{1.3^1}{2^1.1}\)\(=\frac{3}{2}\)

CHÚC BẠN HỌC TỐT

=-(2.3^3.5^3.7.2^3)/3.2^3.3.5^3.2.7

=-(2^4.3^3.5^3.7)/3^2.2^4.5^3.7

=-(1.3.1.1)/1.1.1.1

=-3/1=-3

Ta có : 

\(\frac{7^5.6^8.\left(-3\right)^7}{9^2.7^4.6^9}\)\(=\frac{7^4.7.6^8.\left(-1.3\right)^7}{\left(3^2\right)^2.7^4.6^8.6}=\frac{7^4.7.6^8\left(-1\right)^7.3^4.3^3}{3^4.7^4.6^8.6}=\frac{7.\left(-1\right).27}{6}=-\frac{7.27}{6}=-\frac{189}{6}=-\frac{63}{2}\)

Ủng hộ mk nha !!! ^_^

\(A=\frac{\left(-2\right)^3.3^3.5^3.7.8}{3.2^4.5^3.14}=\frac{\left(-8\right).3^2.3.5^3.7.8}{3.2^3.2.5^3.2.7}=\frac{\left(-8\right).9}{2.2}=\frac{-72}{4}=-18\)

C.ơn bạn nhiều nha ... nha ... nha

a.

\(\frac{11^4\times6-11^5}{11^4-11^5}=\frac{11^4\times\left(6-11\right)}{11^4\times\left(1-11\right)}=\frac{-5}{-10}=\frac{1}{2}\)

b.

\(\frac{9^8\times3-3^{18}}{9^8\times5+9^8\times7}=\frac{9^8\times3-\left(3^2\right)^9}{9^8\times\left(5+7\right)}=\frac{9^8\times3-9^9}{9^8\times12}=\frac{9^8\times\left(3-9\right)}{9^8\times12}=-\frac{6}{12}=-\frac{1}{2}\)

c.

\(\frac{10^5-10^5\times3}{10^5\times11}=\frac{10^5\times\left(1-3\right)}{10^5\times11}=-\frac{2}{11}\)

Chúc bạn học tốt

\(\frac{\left(-2\right)^3.3^3.5^3.7.8}{3.2^4.5^3.14}=\frac{\left(-2\right)^3.3^3.5^3.7.2^3}{3.2^4.5^3.2.7}=\)\(\frac{\left(-2\right)^6.3^3.5^3.7}{3.2^5.5^3.7}=\frac{-2.3^2}{1}=-18\)

~~~ học tốt ~~~

-18/125

Chúc bn hok tốt!

Giải chi tiết nha m.n

Mấy bn help mk vs nha !!!!!!!!!!!!!!!1

Bằng -16322,21709

00000000000

\(A=\frac{3600-75}{8400-175}=\frac{3525}{8225}=\frac{3}{7}\)

\(B=\frac{9^{14}.25^7.8^7}{18^{12}.625^3.24^3}=\frac{\left(3^2\right)^{14}.\left(5^2\right)^7.\left(2^3\right)^7}{\left(2.3^2\right)^{12}.\left(5^4\right)^3.\left(2^3.3\right)^3}=\frac{3^{28}.5^{14}.2^{21}}{2^{12}.3^{24}.5^{12}.2^9.3^3}=\frac{3^{28}.5^{14}.2^{21}}{2^{21}.3^{27}.5^{12}}=3.5^2=3.25=75\)

\(C=\frac{1+3+5+...+19}{21+23+25+...+39}=\frac{\left(19+1\right).10:2}{\left(39+21\right).10:2}=\frac{100}{300}=\frac{1}{3}\)

\(D=\frac{71.52+53}{530.71-180}=\frac{3745}{37450}=\frac{1}{10}\).