bài 1
b, \(\left(x-1\right)^3=-125\)
c,\(2^{4-x}=32\)
d, \(\frac{1}{4}.2^x+2.2^x=9.2^6\)
giúp mik với ~~~
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Tìm x nếu
\(a,3^4:3^x=27\)
\(b,4^x.\frac{1}{3}+4^x.3=\frac{5}{3}.2^7\)
\(c,2^x.\frac{1}{4}+2.2^x=9.2^6\)
\(d,\left(8x-1\right)^{2x+1}=7^{2x+1}\)
\(a,3^4:3^x=3^3\)
\(3^{4-x}=3^3\)
=> 4 -x = 3
=> x = 1
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a, Ta có \(3^4:3^x=27\)
\(\Rightarrow3^4:3^x=3^3\Rightarrow3^x=3^4:3^3\Rightarrow3^x=3\Rightarrow x=1\)
Vậy x = 1
b, \(4^x.\frac{1}{3}+4^x.3=\frac{5}{3}.2^7\)
\(\Rightarrow4^x.\left(\frac{1}{3}+3\right)=\frac{5}{3}.2.4^3\)
\(\Rightarrow4^x.\frac{10}{3}=\frac{10}{3}.4^3\)
\(\Rightarrow4^x=4^3\)
\(\Rightarrow x=3\)
c,\(2^x.\frac{1}{4}+2.2^x=9.2^6\)
\(\Rightarrow2^x.\left(\frac{1}{4}+2\right)=9.2^6\)
\(\Rightarrow2^x.\frac{9}{2}=\frac{9}{2}.2^7\)
\(\Rightarrow2^x=2^7\)
\(\Rightarrow x=7\)
d,\(\left(8x-1\right)^{2x+1}=7^{2x+1}\)
\(\Rightarrow8x-1=7\)
\(\Rightarrow8x=8\)
\(\Rightarrow x=1\)
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Bài 1: Tìm n1/4*2/6*3/8*4/10*5/12*.....* 30/62*31/642^nBài 2: Tínha) frac{left(-5right)^{60}cdot30^5}{15^5cdot5^{61}} b)2^3+3cdotleft(frac{1}{3}right)^0-2^{-2}cdot4+left[left(-2right)^3:frac{1}{2}right]cdot8(GỢI Ý CÂU B:^{2^{-2}frac{1}{2^2}}Bài 3: Tìm xa)^{2^x16}b)^{left(frac{x}{13}right)^2frac{49}{169}}c)left(frac{-1}{5}right)^xleft(frac{-1}{125}right)^3cdot x^4frac{-16}{625}d)^{6^{4-x}216}Bài 4:Tìm na)3^ncdot3^{-2}3^5b)Tìm x:1)frac{2^{4-x}}{16^5}32^62)^{9cdot5^x6cdot5^6+3cdot5^6}3)frac{2^3}{2...
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Bài 1: Tìm n
1/4*2/6*3/8*4/10*5/12*.....* 30/62*31/64=2^n
Bài 2: Tính
a) \(\frac{\left(-5\right)^{60}\cdot30^5}{15^5\cdot5^{61}}\)
b)\(2^3+3\cdot\left(\frac{1}{3}\right)^0-2^{-2}\cdot4+\left[\left(-2\right)^3:\frac{1}{2}\right]\cdot8\)
(GỢI Ý CÂU B:\(^{2^{-2}=\frac{1}{2^2}}\)
Bài 3: Tìm x
a)\(^{2^x=16}\)
b)\(^{\left(\frac{x}{13}\right)^2=\frac{49}{169}}\)
c)\(\left(\frac{-1}{5}\right)^x=\left(\frac{-1}{125}\right)^3\cdot x^4=\frac{-16}{625}\)
d)\(^{6^{4-x}=216}\)
Bài 4:Tìm n
a)\(3^n\cdot3^{-2}=3^5\)
b)Tìm x:
1)\(\frac{2^{4-x}}{16^5}=32^6\)
2)\(^{9\cdot5^x=6\cdot5^6+3\cdot5^6}\)
3)\(\frac{2^3}{2^x}=4^5\)
Các bạn giúp mik!!!Mik sắp kiểm tra 45p r
Tìm x, biết:
b)3/x+4/-/2x+1/-5/x+3/+/x-9/=5
c)\(\left|\frac{11}{5}-x\right|+\left|x-\frac{1}{5}\right|+\frac{41}{5}=1,2\)
d)\(2\left|x+\frac{7}{2}\right|+\left|x\right|-\frac{7}{2}=\left|\frac{11}{5}-x\right|\)
CÁC BẠN GIÚP GIÚP MIK GIẢI BÀI NÀY VỚI, MI ĐANG GẤP LẮM!!!
MIK SẼ TICK CHO...PLEASE!!!
bài1: tìm x:a)8 2^x 2^9.2^5b)27 81^3:3^x 243c)left(frac{2}{5}right)^xleft(frac{5}{2}right)^{-3}.left(frac{-2}{5}right)^2d)left(5x+1right)^2frac{36}{49}e)left(x-frac{2}{9}right)^3left(frac{2}{3}right)^6 f)left(8x-1right)^{2n+1}5^{2n+1}(n thuộc N)bài 2:tìm x,y biết:a)x^2+left(y-frac{1}{10}right)^40b)left(frac{1}{2}x-5right)^{20}+left(y^2-frac{1}{4}right)^{10} 6c)left(x-7right)^{x+1}-left(x-yright)^{x+11}0bài 3:tìm giá trị nhỏ nhất:Aleft(2x+frac{1}{3}right)^2-1tìm Gía...
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bài1: tìm x:
a)\(8< 2^x< =2^9.2^5\)
b)\(27< 81^3:3^x< 243\)
c)\(\left(\frac{2}{5}\right)^x\left(\frac{5}{2}\right)^{-3}.\left(\frac{-2}{5}\right)^2\)
d)\(\left(5x+1\right)^2=\frac{36}{49}\)
e)\(\left(x-\frac{2}{9}\right)^3=\left(\frac{2}{3}\right)^6\) f)\(\left(8x-1\right)^{2n+1}=5^{2n+1}\)(n thuộc N)
bài 2:tìm x,y biết:
a)\(x^2+\left(y-\frac{1}{10}\right)^4=0\)
b)\(\left(\frac{1}{2}x-5\right)^{20}+\left(y^2-\frac{1}{4}\right)^{10}< =6\)
c)\(\left(x-7\right)^{x+1}-\left(x-y\right)^{x+11}=0\)
bài 3:tìm giá trị nhỏ nhất:
\(A=\left(2x+\frac{1}{3}\right)^2-1\)
tìm Gía trị lớn nhất :\(B=-\left(\frac{4}{9}x-\frac{2}{15}\right)^6+3\)
baif4: tìm x,y:
\(x.\left(x-y\right)=\frac{1}{10}\) \(\)
giúp mình với nhé
1.
a) \(x\in\left\{4;5;6;7;8;9;10;11;12;13\right\}\)
b) x=0
d) \(x=\frac{-1}{35}\) hoặc \(x=\frac{-13}{35}\)
e) \(x=\frac{2}{3}\)
Bài 1: Tính hợp lí (nếu có thể) Bài 2:Tìm x biết
a, left(4frac{2}{3}-1frac{1}{6}right):left(1,75+1frac{1}{2}right) a, frac{4}{9}+xfrac{-5}{3}
b, frac{11}{53}+left(frac{32}{47}+frac{-10}{53}right)+frac{-64}{94}+frac{1}{-53}+frac{1}{3} b, 2,4:left(frac{1}{2}.x-frac{3}{4}right)frac{3}{10}
c, 125% -7frac{1}{2}+0,5:frac{4}{3} c, frac{x+1}{-8}frac{-2}{x+1}...
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Bài 1: Tính hợp lí (nếu có thể) Bài 2:Tìm x biết
a, \(\left(4\frac{2}{3}-1\frac{1}{6}\right):\left(1,75+1\frac{1}{2}\right)\) a, \(\frac{4}{9}+x=\frac{-5}{3}\)
b, \(\frac{11}{53}+\left(\frac{32}{47}+\frac{-10}{53}\right)+\frac{-64}{94}+\frac{1}{-53}+\frac{1}{3}\) b, 2,4:\(\left(\frac{1}{2}.x-\frac{3}{4}\right)=\frac{3}{10}\)
c, 125% -7\(\frac{1}{2}+0,5:\frac{4}{3}\) c, \(\frac{x+1}{-8}=\frac{-2}{x+1}\)
d, 1\(\frac{1}{20}.\left(\frac{-2}{3}\right)^2+\left(0,8-\frac{8}{15}\right):\frac{-4}{17}\) d, \(\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{97.99}\right)-x=\frac{-100}{99}\)
Bài 2:
a) \(\frac{4}{9}+x=\frac{-5}{3}\)
\(\Leftrightarrow x=\frac{-5}{3}-\frac{4}{9}\)
\(\Leftrightarrow x=\frac{-15}{9}-\frac{4}{9}\)\(=\frac{-19}{9}\)
Vậy: \(x=\frac{-19}{9}\)
b) \(2,4:\left(\frac{1}{2}.x-\frac{3}{4}\right)=\frac{3}{10}\)
\(\Leftrightarrow\frac{24}{10}:\left(\frac{1}{2}x-\frac{3}{4}\right)=\frac{3}{10}\)
\(\Leftrightarrow\frac{1}{2}x-\frac{3}{4}=\frac{24}{10}:\frac{3}{10}=\frac{24}{10}.\frac{10}{3}\)\(=8\)
\(\Leftrightarrow\frac{1}{2}x=8+\frac{3}{4}=\frac{35}{4}\)
\(\Leftrightarrow x=\frac{35}{4}:\frac{1}{2}=\frac{35}{4}.2=\frac{35}{2}\)
c) \(\frac{x+1}{-8}=\frac{-2}{x+1}\)
\(\Rightarrow\left(x+1\right).\left(x+1\right)=\left(-2\right).\left(-8\right)\)
\(\Leftrightarrow\left(x+1\right)^2=16=4^2=\left(-4\right)^2\)
\(\Rightarrow\left[{}\begin{matrix}x+1=4\\x+1=-4\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-5\end{matrix}\right.\)
Vậy: \(x\in\left\{3;-5\right\}\)
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Bài 1:a. frac{15^3.left(-5right)^4}{left(-3right)^5.5^6}b. frac{6^3.2.left(-3right)^2}{left(-2right)^9.3^7}c. frac{3^6.7^2-3^7.7}{3^7.21}Bài 2:a. left(x-1,2right)^24
b.left(x+1right)^3-125c. left(x-5right)^32^6d. left(2x+1right)^{x+1}5^{x+1}e. left(5-xright)^2+left(5-xright)^50f. left(1-2xright)^4-left(1-2xright)^60g. 3^{4-x}+126h. left(7x+2right)^{-1}3^{-2}
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Bài 1:
a. \(\frac{15^3.\left(-5\right)^4}{\left(-3\right)^5.5^6}\)
b. \(\frac{6^3.2.\left(-3\right)^2}{\left(-2\right)^9.3^7}\)
c. \(\frac{3^6.7^2-3^7.7}{3^7.21}\)
Bài 2:
a. \(\left(x-1,2\right)^2=4
\)
b.\(\left(x+1\right)^3=-125\)
c. \(\left(x-5\right)^3=2^6\)
d. \(\left(2x+1\right)^{x+1}=5^{x+1}\)
e. \(\left(5-x\right)^2+\left(5-x\right)^5=0\)
f. \(\left(1-2x\right)^4-\left(1-2x\right)^6=0\)
g. \(3^{4-x}+1=26\)
h. \(\left(7x+2\right)^{-1}=3^{-2}\)
\(a,\frac{15^3.\left(-5\right)^4}{\left(-3\right)^5.5^6}\)\(=\frac{3^3.5^3}{\left(-3\right)^5.5^2}\)\(=-\frac{5}{\left(3\right)^2}=-\frac{5}{9}\)
\(b,\frac{6^3.2.\left(-3\right)^2}{\left(-2\right)^9.3^7}\)\(=-\frac{6^3}{2^8.3^5}\)\(=-\frac{2^3.3^3}{2^8.3^5}\)\(=-\frac{1}{2^5.3^2}=-\frac{1}{288}\)
\(c,\frac{3^6.7^2-3^7.7}{3^7.21}\)\(=\frac{3^6.7\left(7-3\right)}{3^7.21}\)\(=\frac{3^6.7.4}{3^7.7.3}\)\(=\frac{4}{3.3}=\frac{4}{9}\)
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\(a,\left(x-1,2\right)^2=4\)
\(\Rightarrow x-1,2=2\)
\(\Rightarrow x=3,2\)
\(b,\left(x+1\right)^3=-125\)
\(\Rightarrow\left(x+1\right)^3=\left(-5\right)^3\)
\(\Rightarrow x+1=-5\Rightarrow x=-6\)
\(c,\left(x-5\right)^3=2^6\)
\(\Rightarrow\left(x-5\right)^3=4^3\)
\(\Rightarrow x-5=4\Rightarrow x=9\)
\(d,\left(2x+1\right)^{x+1}=5^{x+1}\)
\(\Rightarrow2x+1=5\Rightarrow x=2\)
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\(e,\left(5-x\right)^2+\left(5-x\right)^5=0\)
\(\Rightarrow\left(5-x\right)^2\left(1+\left(5-x\right)^3\right)=0\)
\(\Rightarrow\orbr{\begin{cases}\left(5-x\right)^2=0\\1+\left(5-x\right)^3=0\end{cases}\Rightarrow}\orbr{\begin{cases}5-x=0\\5-x=-1\end{cases}\Rightarrow\orbr{\begin{cases}x=5\\x=6\end{cases}}}\)
\(f,\left(1-2x\right)^4-\left(1-2x\right)^6=0\)
\(\Rightarrow\left(1-2x\right)^4\left(1-\left(1-2x\right)^2\right)=0\)
\(\Rightarrow\orbr{\begin{cases}1-2x=0\\1-2x=1\end{cases}\Rightarrow}\orbr{\begin{cases}x=\frac{1}{2}\\0\end{cases}}\)
\(g,3^{4-x}-1=26\)
\(\Rightarrow3^{4-x}=27\Rightarrow3^{4-x}=3^3\Rightarrow4-x=3\Rightarrow x=1\)
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Nhờ mn giúp mik với ạ
Tìm GTNN
A= \(\left(x-3y\right)^2+\left(2x-1\right)^4\)
B= \(\left|x-2\right|+\left|3x-2y\right|-4\)
C= \(\dfrac{-4}{\left|x+1\right|\left|y-3\right|+2}\)
D=\(\left|x-5\right|+\left|x-1\right|+7\)
Rút gọn: a)\(\frac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}.12^{10}}\)
b)\(\frac{\left(-\frac{1}{2}\right)^3-\left(\frac{3}{4}\right)^3.\left(-2\right)^2}{2.\left(-1\right)^5+\left(\frac{3}{4}\right)^2-\frac{3}{8}}\)
Tìm x
a)\(3^{x+1}=9^x\)
b)\(2^{3x+2}=4^{x+5}\)
c)\(3^{2x-1}=243\)
Bài 1 giải các phương trình sau
a, frac{5left(1-2xright)}{3}+frac{x}{2}frac{3left(x-5right)}{4}-2
b, left(x+2right)^2+left(x-1right)left(x+3right)2left(x-4right)left(x+4right)
c, frac{3}{x-1}frac{3x+2}{1-x^2}-frac{4}{x+1}
d, frac{1}{x+1}+frac{2x^2+1}{x^3+1}+frac{2x^3-2x^2}{x^2-x+1}2x
Bài 2 : Giải phương trình x^4+3x^3+6x+40
các bạn ơi ! giúp mik với đi ! mai kt rồi
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Bài 1 giải các phương trình sau
a, \(\frac{5\left(1-2x\right)}{3}+\frac{x}{2}=\frac{3\left(x-5\right)}{4}-2\)
b, \(\left(x+2\right)^2+\left(x-1\right)\left(x+3\right)=2\left(x-4\right)\left(x+4\right)\)
c, \(\frac{3}{x-1}=\frac{3x+2}{1-x^2}-\frac{4}{x+1}\)
d, \(\frac{1}{x+1}+\frac{2x^2+1}{x^3+1}+\frac{2x^3-2x^2}{x^2-x+1}=2x\)
Bài 2 : Giải phương trình \(x^4+3x^3+6x+4=0\)
các bạn ơi ! giúp mik với đi ! mai kt rồi
a,<=>\(\frac{20\left(1-2x\right)+6x}{12}\)=\(\frac{9\left(x-5\right)-24}{12}\)
=> 20-40x+6x = 9x-45-24
<=> -40x+6x-9x = -20-45-24
<=> -43x = -89
<=> x = \(\frac{89}{43}\)
c,ĐKXĐ :x\(\ne\pm1\)
<=>\(\frac{3\left(x+1\right)}{x^2+1}\) = -\(\frac{3x+2}{x^2+1}\) - \(\frac{4\left(x-1\right)}{x^2+1}\)
=> 3x+1 = -3x-2-4x+4
<=>3x+3x+4x = -1-2+4
<=> 10x = 1
<=> x =\(\frac{1}{10}\)(TMĐK)
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