\(\frac{3^7.16^3}{12^5.27^2}=\frac{3^7.\left(2^4\right)^3}{\left(2^2.3\right)^5.\left(3^3\right)^2}=\frac{3^7.2^{12}}{2^{10}.3^5.3^6}=\frac{3^7.2^{12}}{2^{10}.3^{11}}=\frac{2^2}{3^4}=\frac{4}{81}\)

\(\frac{3^7.16^3}{12^5.27^2}=\frac{3^7.\left(2^4\right)^3}{\left(2^2.3\right)^5.\left(3^3\right)^2}=\frac{3^7.2^{12}}{2^{10}.3^{11}}=\frac{2^2}{3^4}\)

a)\(=\frac{\left(-0,3\right)^7.2^8}{\left(-0,3\right)^7.2^7.\left(-1\right)}\)

\(=\frac{2}{-1}=-2\)

b)\(=\frac{3^7.2^{12}}{2^{10}.3^{11}}\)

\(=\frac{2^2}{3^4}=\frac{4}{81}\)

\(\dfrac{3}{5}.\dfrac{6}{7}+\dfrac{3}{7}:\dfrac{5}{3}-\dfrac{2}{7}:1\dfrac{2}{3}.\)

\(=\dfrac{3}{5}.\dfrac{6}{7}+\dfrac{3}{7}.\dfrac{3}{5}-\dfrac{2}{7}.\dfrac{3}{5}.\)

\(=\dfrac{3}{5}\left(\dfrac{6}{7}+\dfrac{3}{7}-\dfrac{2}{7}\right).\)

\(=\dfrac{3}{5}.1=\dfrac{3}{5}.\)

Vậy.....

\(\dfrac{3^7.16^3}{12^5.27^2}=\dfrac{3^7.\left(2^4\right)^3}{\left(2^2.3\right)^5.\left(3^3\right)^2}.\)

\(=\dfrac{3^7.2^{12}}{\left(2^2\right)^5.3^5.3^6}=\dfrac{3^7.2^{12}}{2^{10}.3^{11}}.\)

\(=\dfrac{2^2}{3^4}=\dfrac{4}{81}.\)

Vậy.....

a)F=-2

b)G=1536

c)H=229582512

\(A=\frac{2^{12}.27^3}{6^7.16^2}=\frac{2^{12}.\left(3^3\right)^3}{2^7.3^7.\left(2^4\right)^2}=\frac{2^{12}.3^9}{2^7.3^7.2^8}=\frac{2^{12}.3^9}{2^{15}.3^7}=\frac{1.3^2}{2^3.1}=\frac{9}{8}\)

\(A=\frac{2^{12}\cdot27^3}{6^7\cdot16^2}\)

\(A=\frac{4096\cdot19683}{279936\cdot256}\)

\(A=\frac{80621568}{71663616}\)

\(A=\frac{2^{12}.27^3}{6^7.16^2}=\frac{4096.19683}{279936.256}=\frac{9}{8}\)

Hay bạn dùng cách tính nhanh bằng cách rút gọn các lũy thừa ở tử sao cho có thể gạch nó ở cả mẫu!

3^7. 16^3=3^7. (2^4)^3       =3^7.2^12            =3^2.2^2=2^2    =4

12^5.21^3=(3.2^2)^5.(7.3)^3=3^5.2^10.7^3.3^3=7^3.3^3=343.3=1029

= 3¹⁴/27³.4²/6⁵

sau đó bạn rút gon đi 

3¹⁴/27³=3¹⁴/3⁹=3⁵         và 4²/6⁵=1/486

 ssau đó: nhân 2 số vs nhau=1/2 hehehehe