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\(\frac{4}{3.7}+\frac{4}{7.11}+\frac{4}{11.15}+...+\frac{4}{a\left(a+4\right)}\)

\(=\frac{1}{3}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+\frac{1}{11}-\frac{1}{15}+...+\frac{1}{a}-\frac{1}{a+4}\)

\(=\frac{1}{3}-\frac{1}{a+4}\)

7/11 .4/15 +11/15 . 7/11

\(S=\frac{4}{3\times7}+\frac{4}{7\times11}+\frac{4}{11\times15}+...+\frac{4}{\left(4x-1\right)\times\left(4x+3\right)}\)

\(=\frac{7-3}{3\times7}+\frac{11-4}{7\times11}+\frac{15-11}{11\times15}+...+\frac{\left(4x+3\right)-\left(4x-1\right)}{\left(4x-1\right)\times\left(4x+3\right)}\)

\(=\frac{1}{3}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+\frac{1}{11}-\frac{1}{15}+...+\frac{1}{4x-1}-\frac{1}{4x+3}\)

\(=\frac{1}{3}-\frac{1}{4x+3}=\frac{664}{1995}\)

\(\Leftrightarrow\frac{1}{4x+3}=\frac{1}{1995}\)

\(\Leftrightarrow4x+3=1995\)

\(\Leftrightarrow x=498\).

Số hạng cuối cùng của dãy \(S\)là: \(\frac{1}{1991\times1995}\).

Tổng \(S\)có \(498\)số hạng. 

a) 5 – 4 – 3 – 2 – 1 + 11 + 12 + 13 + 14 + 15

= (5 + 15) + (14 – 4) + (13 – 3) + (12 – 2) + (11 – 1)

= 20 + 10 + 10 + 10 + 10

= 60 

b) 1 – 2 + 3 – 4 + 5 – 6 + 7 – 8 + 9 – 10 +11

= (1 + 3 + 5 + 7 + 9 + 11) – 2 – 4 – 8 – 10

= 36 – 24

= 12