\(\frac{292929-404}{4.797979+909}\)
Rút gọn phân số:
\(\frac{292929-404}{4.797979+909}\)
\(\frac{292929-404}{4.797979+909}\)=\(\frac{292525}{4798888}\)=\(\frac{11701}{599861}\)
Tối giản phân số:
\(\frac{292929-404}{4.797979+909}\)
\(\left(\frac{505}{707}+\frac{222}{333}\right)x=\frac{404}{909}\)
x = 28 / 87
Kết quả bằng 28 / 87
\(\left(\frac{505}{707}+\frac{222}{333}\right)\)x=\(\frac{404}{909}\)
\(\left(\frac{5}{7}+\frac{2}{3}\right)\)x=\(\frac{4}{9}\)
\(\left(\frac{15}{21}+\frac{14}{21}\right)\)x=\(\frac{4}{9}\)
\(\frac{29}{21}\)x=\(\frac{4}{9}\)
x=\(\frac{4}{9}:\frac{29}{21}\)
x=\(\frac{4}{9}.\frac{21}{29}\)
x=\(\frac{28}{87}\)
Vậy x=\(\frac{28}{87}\)
k mình nha bạn
( 505 / 707 + 222 / 333 ) . x = 404 / 909
\(\left(\frac{505}{707}+\frac{222}{333}\right)\cdot x=\frac{404}{909}\)
=> \(\left(\frac{5}{7}+\frac{2}{3}\right)\cdot x=\frac{4}{9}\)
=> \(\frac{29}{21}\cdot x=\frac{4}{9}\)
=> \(x=\frac{4}{9}:\frac{29}{21}\)
=> \(x=\frac{28}{87}\)
TK mk nha!
( 505/707+ 222/333) . x = 404/ 909
29/21 . x = 4/9
x= 4/9 : 29/21
x= 4/9 . 21/29
x= 28/87
Vậy x= 28/87
chứng minh hai phân số \(\frac{1717}{2929}=\frac{171717}{292929}\)
\(\frac{1717}{2929}=\frac{17.101}{29.101}=\frac{17}{29}\left(1\right)\)
\(\frac{171717}{292929}=\frac{17.10101}{29.10101}=\frac{17}{29}\left(2\right)\)
từ (1) và (2) => đpcm
1717/2929 = 17,101/29,101,= 17 /29
A=\(\frac{65+891+135+909}{731-47+69-253}\)
Tính nhanh
\(A=\frac{595959}{454545}-\frac{14141414}{15151515}\)
\(B=\frac{65+891+135+909}{731-47+69-253}\)
\(A=\frac{595959}{454545}-\frac{14141414}{15151515}\)
\(A=\frac{595959:10101}{454545:10101}-\frac{14141414:1010101}{15151515:1010101}\)
\(A=\frac{59}{45}-\frac{14}{15}\)
\(A=\frac{59}{45}-\frac{42}{45}=\frac{17}{45}\)
\(B=\frac{65+891+135+909}{731-47+69-253}\)
\(B=\frac{\left(65+135\right)+\left(891+909\right)}{\left(731+69\right)-\left(47+253\right)}\)
\(B=\frac{200+1800}{800-300}=\frac{2000}{500}=4\)
\(A=\frac{595959}{454545}-\frac{14141414}{15151515}\\ A=\frac{595959:10101}{454545:10101}-\frac{14141414:1010101}{15151515:1010101}\\ A=\frac{59}{45}-\frac{14}{15}=\frac{17}{45}\)
\(B=\frac{65+891+135+909}{731-47+69-253}=\frac{\left(65+135\right)+\left(891+909\right)}{\left(731+69\right)-\left(47-253\right)}=\frac{200+1800}{731+69-47+253}=\frac{200+1800}{500}=\frac{2000}{500}=4\)
Tính (-909) + 909
A. 1818
B. 1
C. 0
D. -1818
Tính ( - 909) + 909.
A. 1818
B. 1
C. 0
D. −1818
Đáp án cần chọn là: C
Ta thấy 909 và (−909) là hai số đối nhau.
Ta có (−909)+909=0.