Find the value of x such that \(\frac{x-7}{6}+\frac{x-11}{10}=\frac{x-8}{7}+\frac{x-10}{9}\)
.
Answer: .x=..
Find the value of x, such that:
\(\frac{x-7}{6}+\frac{x-11}{10}=\frac{x-8}{7}+\frac{x-10}{9}\)
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\(\frac{x-7}{6}+\frac{x-11}{10}=\frac{x-8}{7}+\frac{x-10}{9}\)
\(\Rightarrow\left(\frac{x-7}{6}+1\right)+\left(\frac{x-11}{10}+1\right)=\left(\frac{x-8}{7}+1\right)+\left(\frac{x-10}{9}+1\right)\)
\(\Rightarrow\frac{x-1}{6}+\frac{x-1}{10}-\frac{x-1}{7}-\frac{x-1}{9}=0\)
\(\left(x-1\right).\left(\frac{1}{6}+\frac{1}{10}-\frac{1}{7}-\frac{1}{9}\right)=0\)
\(\Rightarrow x-1=0\Rightarrow x=1\)
Find the value of x such that: \(\frac{3\left(x+2\right)}{2x+3}=\frac{7}{8},\left(x\ne-\frac{3}{2}\right)\) . Answer: x = ...
( write your answer by decimal in simplest form )
Find the value of x such that .\(\frac{x+3}{7}=\frac{2-x}{3}\)
Answer: .x=.....
(write your answer by decimal in simplest form)
=>3(x+3)=7.(2-x)
=>3x+9=14-2x
=>3x+2x=14-9
=>5x=5=>x=1
The value of such that \(3.\left(\frac{1}{7}-\frac{3}{21}+\frac{7}{3}\right)<\frac{x}{2}<\frac{13}{8}.\left(\frac{1}{2}-\frac{1}{6}\right)\)
Answer: x =
Find the value of x such that:\(\frac{3}{2x+7}=\frac{5}{3x+9}\)
\(x\ne-\frac{7}{2};x\ne-3\)
\(\Rightarrow3\left(3x+9\right)=5\left(2x+7\right)\)
\(\Rightarrow9x+27=10x+35\)
\(\Rightarrow10x-9x=27-35\)
\(\Rightarrow x=-8\)
Find the value of x such that: \(\frac{5}{7-2x}=\frac{3}{x-3}\)
Find the value of x such that
\(\frac{x+7}{\left(a+1\right)\left(a+7\right)}=\frac{1}{a+1}-\frac{1}{a+7}\)
(a\(\ne\)-7;-1 )
Answer: x=
find the value of x such that (Tìm x biết ) : \(\frac{x+7}{\left(a+1\right)\left(a+7\right)}=\frac{1}{a+1}-\frac{1}{a+7}\)
( a khác -1; -7 )
\(\frac{1}{a+1}-\frac{1}{a+7}=\frac{a+7}{\left(a+1\right)\left(a+7\right)}-\frac{a+1}{\left(a+1\right)\left(a+7\right)}=\frac{6}{\left(a+1\right)\left(a+7\right)}\)
=>x+7=6
=>x=6-7
=>x=-1
vậy x=-1
\(\frac{1}{a+1}-\frac{1}{a+7}=\frac{\left(a+7\right)-\left(a+1\right)}{\left(a+1\right)\left(a+7\right)}=\frac{6}{\left(a+1\right)\left(a+7\right)}\)=> x + 7 = 6 => x = -1
\(\frac{X-6}{7}+\frac{X-7}{8}+\frac{X-8}{9}=\frac{X-9}{10}+\frac{X-10}{11}+\frac{X-11}{12}\)
\(\frac{x}{10}=\frac{y}{6}=\frac{z}{21}\)và \(5x+y-2z=28\)