(1/2+1/4+1/8+1/16):x=1/2+1/6+1/12+...+1/132
giúp mình với mình đang cần gấp !!! O^O
16/ 1/2.x+1/6.x(x-2)=3/4-2.x
19/ 5/12.x+3=1/3-7/12.x
20/ 1/2.x+5/2=7/2.x-3/4
Mọi người giúp mình với mình đang cần gấp!!!
<1/2+1/4+1/8+1/16> x y =1/2+1/6+1/12+1/20+........+1/132
mình đang cần liền ai nhanh mình tick
1/2 + 1/4 + 1/8 + 1/16 + ... + 1/128
giúp mình với mình đang cần gấp
1/2 + 1/4 + 1/8 + … + 1/128
= 1 - 1/2 + 1/2 - 1/4 + 1/4 - 1/8 + … + 1/64 - 1/128
= 1 - 1/128
= 128/128 - 1/128
= 127/128
Chúc bạn học tốt.
😁😁😁
cảm ơn nguyễn phú tài
khoanh vào chữ cái đặt trước 3 PS bằng nhau
A. 1/3,2/6,3/6.
B.2/4,4/8,8/32.
C. 4/3, 8/6, 16/6.
D. 4/16, 2/8, 3/12.
ai giúp mình với mình đang cần gấp!
`->D`
vì : `4/16=(4:4)/(16:4)=1/4`
`2/8=(2:2)/(8:2)=1/4`
`3/12=(3:3)/(12:3)=1/4`
1 +1/2+1/4+1/8+1/16+1/32+1/64+1/128
giúp mình với mình đang cần gấp lắm
A = 1 + \(\dfrac{1}{2}\) + \(\dfrac{1}{4}\) + \(\dfrac{1}{8}\)+ \(\dfrac{1}{16}\) + \(\dfrac{1}{32}\)+ \(\dfrac{1}{64}\)+ \(\dfrac{1}{128}\)
A\(\times\)2 = 2 + 1 + \(\dfrac{1}{2}\) + \(\dfrac{1}{4}\) + \(\dfrac{1}{8}\) + \(\dfrac{1}{16}\) + \(\dfrac{1}{32}\) + \(\dfrac{1}{64}\)
A \(\times\) 2 - A = 2 - \(\dfrac{1}{128}\)
A \(\times\)( 2-1) = \(\dfrac{255}{128}\)
A = \(\dfrac{255}{128}\)
Gọi \(1+\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}+\dfrac{1}{32}+\dfrac{1}{64}+\dfrac{1}{128}\) là T
\(T=1+\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}+\dfrac{1}{32}+\dfrac{1}{64}+\dfrac{1}{128}\)
\(2T=2+1+\dfrac{1}{2}+\dfrac{1}{4}+....+\dfrac{1}{64}\)
\(2T-T=\left(2+1+\dfrac{1}{2}+\dfrac{1}{4}+....+\dfrac{1}{64}\right)-\left(1+\dfrac{1}{2}+....+\dfrac{1}{64}+\dfrac{1}{128}\right)\)
\(T=2+\left(1-1\right)+\left(\dfrac{1}{2}-\dfrac{1}{2}\right)+....+\left(\dfrac{1}{64}-\dfrac{1}{64}\right)-\dfrac{1}{128}\)
\(T=2+0+0+...-\dfrac{1}{128}\)
\(T=\dfrac{256}{128}-\dfrac{1}{128}\)
\(T=\dfrac{255}{128}\)
tính nhanh:
a) (8^2+2^3).(8+13).5
b) 6.(-1/4)^3-3.(-1/4)^2-2.(-1/3)+1
tính:
a) 8^16+7^5:8^12+16,7
b) 7,32 .3^13:7,32 .9^8
Mình đang cần gấp
what your name? I can't speak vietnamese
Bài 1: Tính
a, 2/3+1/2+1/6
b, 5/12+5/6-3/4
c, 1/3*3/5*2/5
d, 15/16 : 3/8 *3/4
giúp mình nha đang cần gấp
a, 2/3+1/2+1/6
=4/6+3/6+1/6
=4/3
b, 5/12+5/6-3/4
=10/24+20/24-18/24
=1/2
c, 1/3*3/5*2/5
=(1*3*2)/(3*5*5)
=2/25
d, 15/16:3/8*3/4
= 15/16*8/3*3/4
= 15/8
a) \(\frac{2}{3}\)+\(\frac{1}{2}\)+\(\frac{1}{6}\) = \(\frac{4}{6}\)+\(\frac{3}{6}\)+\(\frac{1}{6}\) =\(\frac{8}{6}\) =\(\frac{4}{3}\)
b)\(\frac{5}{12}+\frac{5}{6}-\frac{3}{4}\)=\(\frac{5}{12}+\frac{10}{12}-\frac{9}{12}\)=\(\frac{6}{12}\)= \(\frac{1}{2}\)
c) \(\frac{1}{3}\cdot\frac{3}{5}\cdot\frac{2}{5}\) =\(\frac{6}{75}\)=\(\frac{2}{25}\)
a,2/3+1/2+1/6=1.33
b,5/12+5/6-3/4=0.5
c,1/3x3/5x2/5=0.08
d,15/16:3/8x3/4=1.875
1/
cho x^2+y^2= 20 và xy=8. tính giá trị của (x+y)^2
2/rút gọn biểu thức
M= (2^2+1) (2^4+1) (2^8+1) (2^16+1)
N= 16 (7^2+1) (7^4+1) (7^8+1) (7^16+1)
Nhờ các bạn giúp mình với, chiều chủ nhật 31/6 mình cần gấp
1) ta có \(\left(x+y\right)^2=x^2+2xy+y^2.\)
\(=\left(x^2+y^2\right)+2xy\)
\(=20+2.8\)(theo giả thiết x^2+y^2=20 , xy=8)
\(=36\)
Vậy với x^2+y^2=20, xy=8 thì (x+y)^2=36
2) \(M=\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(\Rightarrow3M=3\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(\Leftrightarrow3M=\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(\Leftrightarrow3M=\left[\left(2^2\right)^2-1^2\right]\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(\Leftrightarrow3M=\left(2^4-1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(\Leftrightarrow3M=\left[\left(2^4\right)^2-1^2\right]\left(2^8+1\right)\left(2^{16}+1\right)\)
\(\Leftrightarrow3M=\left(2^8-1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(\Leftrightarrow3M=\left[\left(2^8\right)^2-1^2\right]\left(2^{16}+1\right)\)
\(\Leftrightarrow3M=\left(2^{16}-1\right)\left(2^{16}+1\right)\)
\(\Leftrightarrow3M=\left(2^{16}\right)^2-1^2\)
\(\Leftrightarrow3M=2^{32}-1\)
\(\Rightarrow M=\frac{2^{32}-1}{3}\)
RÚT GỌN BIỂU THỨC N BẠN LÀM TƯƠNG TỰ NHA
\(N=16\left(7^2+1\right)\left(7^4+1\right)\left(7^8+1\right)\left(7^{16}+1\right)\)
\(\Rightarrow3N=48\left(7^2+1\right)\left(7^4+1\right)\left(7^8+1\right)\left(7^{16}+1\right)\)
\(\Leftrightarrow3N=\left(7^2-1\right)\left(7^2+1\right)\left(7^4+1\right)\left(7^8+1\right)\left(7^{16}+1\right)\)
\(...\)
\(...\)
Kết quả rút gọn \(N=\frac{7^{32}-1}{3}\)
thực hiện phép tính sau 1 cách hợp lí
a.(10^2+11^2+12^2):(13^2+14^2)
b.1*2*3*...*9-1*2*...*8-1*2*3*...*7*8^2
c.(3*4*2^16)^2/11*2^13*4^11-16^9
d.13-12+11+10-9+8-7-6+5-4+3+2-1
đang cần gấp
nhanh mình tick cho