\(\frac{1}{3}+\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+\frac{1}{48}+\frac{1}{96}\)

\(=\frac{1}{2}+\frac{1}{8}+\frac{1}{32}\)

\(=\frac{5}{8}+\frac{1}{32}\)

\(=\frac{21}{32}\)

21/32

3/4 nha bạn đúng thì k mk nha

c=21/32

\(=2\left(\frac{1}{3}+\frac{1}{6}+...+\frac{1}{192}\right)\)

\(=2\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{6}+...+\frac{1}{96}-\frac{1}{192}\right)\)

\(=2\left(1-\frac{1}{192}\right)\)

\(=2\times\frac{191}{192}\)

\(=\frac{191}{96}\)

21/32

21/32

A= 1/3+1/6+1/12+1/24+1/48+1/96

  = (1/3+1/6)+(1/12+1/24)+(1/48+1/96)

  = (2/6+1/6)+(2/24+1/24)+(2/96+1/96)

  = 1/2+1/8+1/32

  = 16/32+4/32+1/32
  = 21/32

Vậy A=21/32

Giải:

A=1/3+1/6+1/12+1/24+1/48+1/96

A=1/3+(1/2.3+1/3.4)+(1/4.6+1/6.8)+1/96

A=1/3+(1/2-1/3+1/3-1/4)+[1/2.(2/4.6+2/6.8)]+1/96

A=1/3+(1/2-1/4)+[1/2.(1/4-1/6+1/6-1/8)]+1/96

A=1/3+1/4+[1/2.(1/4-1/8)]+1/96

A=1/3+1/4+[1/2.1/8]+1/96

A=1/3+1/4+1/16+1/96

A=7/12+7/96

A=21/32

21/32

\(\frac{1}{3}+\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+\frac{1}{48}+\frac{1}{96}\)

\(=\left(\frac{1}{3}+\frac{1}{6}\right)+\left(\frac{1}{12}+\frac{1}{24}\right)+\left(\frac{1}{48}+\frac{1}{96}\right)\)

\(=\frac{1}{2}+\frac{1}{8}+\frac{1}{32}\)

\(=\frac{21}{32}\)

Đáp án là :\(\frac{21}{32}\)

1/3 +1/6+1/12+1/24 +1/48 + 1/96

= 1/3 + 1/3 – 1/6 + 1/6 – 1/12+1/12 – 1/24 +1/24 – 1/48+1/48 -1/96

=2/3 – 1/96

= 21/32

là 21/32 nha

nhớ k cho mình nhé

21/32