Tìm x € Z , biết :
a) 14 - (40 - x) = -27
b) 2 (5 - x) - 7 (x - 2) = -3
c) (x : 3) + 2^3 ) . 3^2 = -90
tìm x biết
a)(x+3)(x^2-3x+9)-x(x-2)^2=27
b) (x-1)(x-5)=3
a) \(\left(x+3\right)\left(x^2-3x+9\right)-x\left(x-2\right)^2=27.\)
\(\Leftrightarrow x^3+27-x\left(x^2-4x+4\right)-27=0.\)
\(\Leftrightarrow x^3-x^3+4x^2-4x=0.\)
\(\Leftrightarrow4x\left(x-1\right)=0.\)
\(\Leftrightarrow\left[{}\begin{matrix}4x=0.\\x-1=0.\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0.\\x=1.\end{matrix}\right.\)
Vậy \(S=\left\{0;1\right\}.\)
bài 3 tìm x :
A ) x + 4/9 = 5/27
b ) x - 4/11= 7/33
c ) 8/5 - x = 1/3 x 2/5
d ) x - 3/4 = 1/2 + 2/6
a) \(x+\dfrac{4}{9}=\dfrac{5}{27}\)
\(x=\dfrac{5}{27}-\dfrac{4}{9}\)
\(x=-\dfrac{7}{27}\)
b) \(x-\dfrac{4}{11}=\dfrac{7}{33}\)
\(x=\dfrac{7}{33}+\dfrac{4}{11}\)
\(x=\dfrac{19}{33}\)
c) \(\dfrac{8}{5}-x=\dfrac{1}{3}\times\dfrac{2}{5}\)
\(\dfrac{8}{5}-x=\dfrac{2}{15}\)
\(x=\dfrac{8}{5}-\dfrac{2}{15}\)
\(x=\dfrac{22}{15}\)
d) \(x-\dfrac{3}{4}=\dfrac{1}{2}+\dfrac{2}{6}\)
\(x-\dfrac{3}{4}=\dfrac{5}{6}\)
\(x=\dfrac{5}{6}+\dfrac{3}{4}\)
\(z=\dfrac{19}{12}\)
tìm x thuộc z ,biết
a,2.(x-5)-3.(x+7)=14
b,5.(x-6)-2.(x+3)=12
c,-5.(2-x)+4.(x-3)=10.x-15
d,-7.(3x-5)+2.(7.x-14)=28
e,5.(4-x)-7.(-x+2)=4-9+3
f,-4.(2.x+1)+8.(3-2.x)=24
\(a,2.\left(x-5\right)-3.\left(x+7\right)=14\)
\(2x-10-3x-21=14\)
\(-x-31=14\)
\(x=-31-14\)
\(x=-45\)
\(b,5.\left(x-6\right)-2\left(x+3\right)=12\)
\(5x-30-2x-6=12\)
\(3x-36=12\)
\(3x=12+36\)
\(3x=48\)
\(x=16\)
\(c,-5.\left(2-x\right)+4.\left(x-3\right)=10.x-15\)
\(-10+5x+4x-12=10x-15\)
\(-6x-22=10x-15\)
\(-6x-10x=-15+22\)
\(-16x=7\)
\(x=-\frac{7}{16}\)
Câu d , e f tương tự nha
Tìm x,y,z biết
3 /x/+5/3=3 /y/-1/5=3-z/7 và 2/x/+7/y/+3/z/=-14
1 tìm x thuộc Z
-2x-40=(5-x)-(-15+60)
2.(x-5)-3(x+7)=14
-7.(5-x)-2(x-10)=15
x+18=2-2x
-2x - 40 = (5 - x) - (-15 + 60)
-2x - 40 = (5 - x) - 45
-2x - 40 = -40 - x
-2x - x = 40 - 40
-3x = 0
x = 0
2(x - 4) - 3(x + 7) = 14
2x - 8 - 3x - 21 = 14
-x - 29 = 14
-x = 14 + 29
-x = 43
x = -43
-7(5 - x) - 2(x - 10) = 15
-35 + 7x - 2x + 20 = 15
-15 + 5x = 15
5x = 15 + 15
5x = 30
x = 6
\(-2x-40=\left(5-x\right)-\left(-15+60\right)\)
\(\Leftrightarrow\)\(-2x-40=5-x+15-60\)
\(\Leftrightarrow\)\(-2x-40=-x-40\)
\(\Leftrightarrow\)\(-2x+x=40-40\)
\(\Leftrightarrow\)\(x=0\)
Vậy....
\(x+18=2-2x\)
\(2x+x=2-18\)
\(3x=-20\)
\(x=-20:3\)
\(x=\frac{-20}{3}\)
Tìm x biết:
5. ( x-1 ) - 7.( x-2 ) = 2x -39
Tìm x thuộc Z biết:
x - 3 - 14.( x-2 )= -3x -3
\(3x+7⋮x-2\)
5 ( x - 1 ) - 7 ( x - 2 ) = 2x - 39
<=> 5x - 5 - 7x + 14 = 2x - 39
<=> 5x - 7x - 2x = -39 + 5 - 14
<=> -4x = -48
<=> x = 12
x - 3 - 14.( x-2 )= -3x -3\(\Rightarrow\chi-3-28-14\chi-28=-3\chi-3\)
\(\Rightarrow\chi-3-28+3=-3\chi-3\)
\(\Rightarrow\chi-28=11\chi\)
\(\Rightarrow\chi-11\chi=28\)
\(\Rightarrow10\chi=28\Rightarrow\chi=2,8\left(kot.m\chi\inℤ\right)\)
HTDT-sai-rùi
x-3-14(x-2)=-3x-3
x-3+28-14x=-3x-3
-13x+35=-3x-3
-13x+3x=-3-35
-10x=-38
x=38/10=19/5
1) Tìm x biết
a) 4.(2-x)+3.(x-5)=14
b) 7.(x-9)-5.(6-x)=-6+11x
c) -7(3x-5).2(7x-144)=28
2) Tìm x,ythuôc Z biết
(2x+3).(2y-1)=-5
Tìm x
a) (-12) .x -14 = -2
b)(-8).x= (-5).(-7) -3
c) (-9) .x + 3 = (-2) . (-7) + 16
a.\(\left(-12\right)x-14=-2\)
\(\left(-12\right)x=-2+14\)
\(\left(-12\right)x=12\)
\(x=12:\left(-12\right)\)
\(x=-1\)
\(b,\left(-8\right)x=\left(-5\right)\left(-7\right)-3\)
\(\left(-8\right)x=35-3\)
\(\left(-8\right)x=32\)
\(x=32:\left(-8\right)\)
\(x=-4\)
\(c,\left(-9\right)x+3=\left(-2\right)\left(-7\right)+16\)
\(\left(-9\right)x+3=14+16\)
\(\left(-9\right)x+3=30\)
\(\left(-9\right)x=30-3\)
\(\left(-9\right)x=27\)
\(x=27:\left(-9\right)\)
\(x=-3\)
a)\(\frac{x}{5}=\frac{y}{7}=\frac{z}{3}\) và x2+y2+z2=585
b)\(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}\) và x-2y+3z=14
tìm x, y, z
cho biết kết quả thui cũng được nhanh giúp mình
a,
\(\frac{x}{5}=\frac{y}{7}=\frac{z}{3}\)
Mà : x2+y2+z2=585
=> \(\frac{x^2}{25}=\frac{y^2}{49}=\frac{z^2}{9}\)
\(\Rightarrow\frac{x^2+y^2+z^2}{25+49+9}=\frac{585}{93}=\frac{195}{31}\)
=> x=195/31.5
=> y=195/31.7
=> z=195/31.3
Xong :)