rút gọn các phân số sau
a, 2^3 . 3^4/ 2^2 . 3^2 . 5
b, 2^4 . 5^2 . 11^2 .7 / 2^3 . 5^3 . 7^2 .11
c, 1998.1990+3978 / 1992 . 1991 - 3984
rút gọn các phân số sau
a, 2^3 . 3^4/ 2^2 . 3^2 . 5
b, 2^4 . 5^2 . 11^2 .7 / 2^3 . 5^3 . 7^2 .11
c, 1998.1990+3978 / 1992 . 1991 - 3984
Chúc học tốt!!!!
a,\(\frac{2^3.3^4}{2^2.3^2.5}=\frac{2.3^2}{5}=\frac{2.9}{5}=\frac{18}{5}\)
b, \(\frac{2^4.5^2.11^2.7}{2^3.5^3.7^2.11}=\frac{2.11}{5.7}=\frac{22}{35}\)
c,\(\frac{1998.1990+3978}{1992.1991-3984}=\frac{18.111.1990+18.221}{24.83.1991-166.24}\)
\(=\frac{18.\left(111.1990+221\right)}{24.\left(83.1991-166\right)}\)
\(=\frac{3.221111}{4.165087}=\frac{221111}{4.55029}=\frac{221111}{220116}\)
\(\)
a) 2^3 . 3^4/2^2 . 3^2 . 5
= 8 . 81/4 . 9 . 5
=7290
c) \(\frac{1998.1990+3978}{1992.1991-3984}\)
= \(\frac{1998.1990+1998.2}{1992.1991-1992.2}\)
=\(\frac{1998.\left(1990+2\right)}{1992.\left(1991-2\right)}\)
= \(\frac{1998.1992}{1992.1989}\)
= \(\frac{1998}{1989}\)
a)121×75×130×169/39×60×11×198
b)2^4×5^2×11^2×7/2^3×5^3×7^2×11
c)1998×1990+3968/1992×1991-3984
Rút gọn
Rút gọn các pso sau:
a, 1989 . 1990 + 3978/1992 . 1991 - 3984
b,125 . 216/64.45
c, 5^11 . 7^12 + 5^11 . 7^11/5^12 . 7^12 + 9 . 5^11 . 7^11
d, 7/10^2 + 6 . 10^2
e, 6 . 9 - 2 . 17/63 . 3 - 119
g, 11. 12 + 22 . 24 + 44 . 48/33 . 36 + 66 . 72 + 132 . 144
h, 8 . 5 - 8 . 2
giúp mình với mọi người ơi, mình cần gấp :(
Rút gọn phân số 23.34/22.32.5;24.52.112.7/23.53.72.11
121.75.130.169/39.60.11.198
1998.1990+3978/1992.1991-3984
Bạn nào làm nhanh mà đúng nhất mình like cho nhé!
Còn dấu . là dấu nhân nhé!
1) Rút gọn phân số :
1) 1989 . 1990 + 3978 / 1992 . 1991 - 3984
2) 310 . (-5) 21 / (-5 ) 10. 312
3) -115 . 137 / 115 . 138
4) 210 . 3 10 - 210 . 34 / 29 . 310
5) 511 . 711 + 58 . 710 / 510 . 710 + 9 . 511 . 711
trình byaf chi tiết giúp mình nha! cảm ơn mọi người.
Rút gọn các phân số sau:
a, 23 . 34/22.32.5
b, 24.52.112.7/23.53.72.11
c, 121.75.130.69/39.60.11.198
a) \(\frac{2^3.3^4}{2^2.3^2.5}=\frac{2.3^2}{5}\)
b) \(\frac{2^4.5^2.11^2.7}{2^3.5^3.7^2.11}=\frac{2.11}{5.7}\)
c) \(\frac{121.75.130.69}{39.60.11.198}=\frac{11^2.3.5^2.2.5.13.23.3}{13.3.2^3.3.5.11.11.3^2.2}\)
\(=\frac{11^2.3^2.5^3.2.13.23}{13.3^4.2^4.5.11^2}=\frac{5^2.23}{3^2.2^3}\)
a,\(\frac{2^3.3^4}{2^2.3^2.5}=\frac{2^2.2.3^2.3^2}{2^2.3^2.5}\)\(=\frac{2.3^2}{5}\)
b,\(\frac{2^4.5^2.11^2.7}{2^3.5^3.7^2.11}=\frac{2^3.2.5^2.11.11.7}{2^3.5^2.5.7.7.11}=\frac{2.11}{5.7}\)
Rút gọn phân số:
a)\(\frac{2.\left(-13\right).9.10}{\left(-3\right).4.\left(-5\right).26}\)
b)\(\frac{2^3.3^4}{2^2.3^2.5};\frac{2^4.5^2.11^2.7}{2^3.5^3.7^2.11}\)
c)\(\frac{121.75.130.169}{39.60.11.198}\)
d)\(\frac{1998.1990+3978}{1992.1991-3984}\)
\(a.\frac{2\cdot\left(-13\right)\cdot9\cdot10}{\left(-3\right)\cdot4\cdot\left(-5\right)\cdot26}\)
\(=\frac{2\cdot\left(-13\right)\cdot3\cdot3\cdot2\cdot5}{\left(-3\right)\cdot2\cdot2\cdot\left(-5\right)\cdot13\cdot2}\)
\(=-\frac{3}{2}\)
b) \(\frac{2^3\cdot3^4}{2^2\cdot3^2\cdot5}=\frac{2\cdot3^2}{5}=\frac{2\cdot9}{5}=\frac{18}{5}\)
\(\frac{2^4\cdot5^2\cdot11^2\cdot7}{2^3\cdot5^3\cdot7^2\cdot11}=\frac{2\cdot1\cdot11\cdot1}{1\cdot5\cdot7\cdot1}=\frac{22}{35}\)
c) \(\frac{121\cdot75\cdot130\cdot169}{39\cdot60\cdot11\cdot198}=\frac{11\cdot11\cdot13\cdot10\cdot169}{13\cdot3\cdot6\cdot10\cdot11\cdot11\cdot6\cdot3}\)
\(=\frac{169}{3\cdot6\cdot6\cdot3}=\frac{169}{324}\)
d) \(\frac{1998\cdot1990+3978}{1992\cdot1991-3984}\)
Rút gọn phân số sau
\(\frac{1989.1990+3978}{1992.1991+3984}\)
\(\frac{3^{10}.\left(-5\right)^{21}}{\left(-5\right)^{20}.3^{12}}\) \(\frac{-11^5.13^7}{11^5.13^8}\)
\(\frac{2^{10}.3^{10}-2^{10}.3^9}{2^9.3^{10}}\)
\(\left(-\right)\frac{1989\cdot1990+3970}{1992\cdot1991+3984}=\frac{1989\cdot\left(1990+2\right)}{1992\cdot\left(1991+2\right)}=\frac{1989}{1993}\)
\(\left(-\right)\frac{3^{10}\cdot\left(-5\right)^{21}}{\left(-5\right)^{20}\cdot3^{12}}=\frac{3^{10}\cdot\left(-5\right)^{20}\cdot\left(-5\right)}{3^{10}\cdot\left(-5\right)^{20}\cdot3^2}=-\frac{5}{9}\)
\(\left(-\right)\frac{\left(-11\right)^5\cdot13^7}{11^5\cdot13^8}=\frac{11^5\cdot13^7\cdot\left(-1\right)}{11^5\cdot13^7\cdot13}=-\frac{1}{13}\)
\(\left(-\right)\frac{2^{10}\cdot3^{10}-2^{10}\cdot3^9}{2^9\cdot3^{10}}=\frac{2^{10}\cdot3^9\left(3-1\right)}{2^9\cdot3^{10}}=\frac{2^{11}\cdot3^9}{2^9\cdot3^{10}}=\frac{4}{3}\)