\(\frac{\left(-4\right)^6.9^5-\left(-6\right)^9.120.1^{2015}}{8^4.3^{12}-6^{11}.2016^0}=\frac{\left(2^2\right)^6.\left(3^2\right)^5+\left(2.3\right)^9.2^3.3.5.1}{\left(2^3\right)^4.3^{12}-\left(2.3\right)^{11}.1}=\frac{2^{12}.3^{10}+2^{12}.3^{10}.5}{2^{12}.3^{12}-2^{11}.3^{11}}\)

\(=\frac{2^{12}.3^{10}.\left(1+5\right)}{2^{11}.3^{11}.\left(2.3-1\right)}=\frac{2.6}{3.5}=\frac{4}{5}\)

\(\frac{\left(-4\right)^6.9^5-\left(-6\right)^9.120.1^{2015}}{8^4.3^{12}-6^{11}.2016^0}=\frac{\left(-2\right)^{12}.3^{10}+2^{12}.3^{10}.5}{2^{12}.3^{12}-2^{11}.3^{11}}=\frac{2^{12}.3^{10}.\left(1+5\right)}{2^{11}.3^{11}.\left(2.3-1\right)}=\frac{2.6}{3.5}=\frac{4}{5}\)

133+625+27.19-25.15

133+625+513-375

625-375+133+513

250+133+513

383+513=896

b,-624-611-35

=-1270

chúc bạn học tốt

a) 27.(-17)+(-17).73

= -17 ( 27+73)

= -17 . 100

= -1700

b) 512 . ( 2- 128) -128. (-512)

= 512.(2-128) - (-128).512

= 512(2-128+128)

= 512 . 2

= 1024

Phan Bá Cường đúng rồi đó Nguyễn Thị Hồng.

a. -1700

b.1024

Phép tính đâu bạn nhỉ?

minhmoi hoc lop 5 thui

a)2100
b)64
c)700

vào chtt đó bạn

\(\text{ -(-23) + (-36) + |57| - (-29)}\)

\(23+\left(-36\right)+57+29\)

\(=\left(23+57\right)+\left(\left(-36\right)+29\right)\)

\(=100+\left(-7\right)\)

\(=93\)

học tốt

a) 67.(-18) + (-33).18

= 67.(-18) + 33.(-18)

= (-18).(67 + 33)

= (-18).100

= (-1800)

b) 34.(-53) - (-66).53 - 68.(-53)

= (-34).53 + 66.53 - (-68).53

= (-34).53 + 66.53  + 68.53

= 53. (-34 + 66 + 68)

= 53.100

= 5300

a) 67.(-18) + (-33).18

= 67.(-18) + 33.(-18)

= (-18).(67 + 33)

= (-18).100

= (-1800)

b) 34.(-53) - (-66).53 - 68.(-53)

= (-34).53 + 66.53 - (-68).53

= (-34).53 + 66.53  + 68.53

= 53. (-34 + 66 + 68)

= 53.100

= 5300

chúc bạn học tốt nhé

\(a,\frac{-7}{25}.\frac{11}{13}+\frac{-7}{25}.\frac{2}{13}-\frac{18}{25}\)

\(=\frac{-7}{25}.\left(\frac{11}{13}+\frac{2}{13}\right)-\frac{18}{25}=\frac{-7}{25}-\frac{18}{25}=-1\)

\(b,\frac{5}{7}.\frac{1}{3}-\frac{5}{7}.\frac{1}{4}-\frac{5}{7}.\frac{1}{12}=\frac{5}{7}.\left(\frac{1}{3}-\frac{1}{4}-\frac{1}{12}\right)=\frac{5}{7}.\left(\frac{4}{12}-\frac{3}{12}-\frac{1}{12}\right)\)

\(=\frac{5}{7}.0=0\)

c)\(5\frac{2}{5}.4\frac{2}{7}+5\frac{5}{7}.5\frac{2}{5}=\frac{27}{5}.\frac{30}{7}+\frac{40}{7}.\frac{27}{5}=\frac{27}{5}.\left(\frac{30}{7}+\frac{40}{7}\right)\)

\(=\frac{27}{5}.10=27.2=54\)

\(d,75\%-1\frac{1}{2}+0,5:\frac{5}{12}-\left(\frac{-1}{2}\right)^2=\frac{3}{4}-\frac{3}{2}+\frac{1}{2}.\frac{12}{5}-\frac{1}{4}\)

\(=\left(\frac{3}{4}-\frac{1}{4}\right)-\frac{3}{2}+\frac{6}{5}=\frac{1}{2}-\frac{3}{2}+\frac{6}{5}=-1+\frac{6}{5}=\frac{-5}{5}+\frac{6}{5}=\frac{1}{5}\)

cho mk hỏi, bn có thể lm thêm c d dc ko