CÂU16

a,5[-8]2[-3] b,3[-5]²+2[-5]-20 c,34[15-10]-15[34-10]

=5.2{-8.[-3]} =3. 25+{[-10]-20} =34.15-340-15. 34-150

=10. 24 =75+[-30] =0+[-340-150]

=2400 =45 =-490

d,27[-17]+[-17]73 e, 512[2-128]-128[-512]

=-17[27+73] =512. [-126]-128[-512]

=-17. 100 =-64512- [-65536]

-1700 =1024

CÂU 17

a,5-[10-x]=7 b, [4x-2][x+5]=0 c,2x-9=-8-9

5-10+x=7 ⇒4x-2 hoặc x+5=0 2x-9=-17

x=7-5+10 TH1:4x-2=0 TH2 x+5=0 2x=-17+9

x=12 4x=0+2 x=0-5 2x=-8

4x=2 x=-5 x=-8:2

x=2:4 x=-4

x=2/4 ko thỏa mãn vì x∈Z

Vậy x=-5

d,3[x-1]-27=0 e,5[3x+8]-7[2x+3]=16

3[x-1]=0+27 15x+40-14x+21=16

3[x-1]=27 15x-14x=16-21-40

[x-1]=27-3 x=-15

[x-1]=24

⇒x-1 =24 hoặc -24

TH1:x-1 =24 TH2 :x-1 =-24

x=24+1 x=-24+1

x=25 x=-23

Vậy x=25 hoặc -23

ĐƠN GIẢN THÔI

NHỚ TICK CHO MÌNH NHA

a) |2x - 1| - 3 = 5 

=> |2x - 1| = 8

Có 2 TH xảy ra:

TH1 : 2x - 1 = 8 => 2x = 9 => x = 9/2 (ko thỏa mãn x thuộc Z)

TH2 : -(2x - 1) = 8 => -2x + 1 = 8 => -2x = 9 => x = -9/2 (ko thỏa mãn x thuộc Z)

b) |3x - 5| = 4

Có 2 TH xảy ra :

TH1 : 3x - 5 = 4 => 3x = 9 => x = 3

TH2 : -(3x - 5) = 4 => -3x + 5 = 4 => -3x = -1 => x = 1/3 (ko thỏa mãn x thuộc Z)

c) |5x - 1| = |-3 - 3x| 

Có 2 TH xảy ra :

TH1 : 5x - 1 = -3 - 3x => 5x + 3x = -3 + 1 => 8x = -2 => x = -1/4 (ko thỏa mãn x thuộc Z)

TH2 : 5x - 1 = -(-3 - 3x) => 5x - 1 = 3 + 3x => 5x - 3x = 3 +1 => 2x = 4 => x = 2

d) |4x - 8| = |x + 1|

Có 2 TH xảy ra :

TH1 : 4x - 8 = x + 1 => 4x - x = 1 + 8 => 3x = 9 => x = 3

TH2 : 4x - 8 = -(x + 10) => 4x - 8 = -x - 10 => 4x + x = -10 + 8 => 5x = -2 => x = -2/5 (ko thỏa mãn x thuộc Z)

e) |3x - 5| - |4x + 9| = 0

=> |3x - 5| = |4x + 9|

Có 2 TH xảy ra :

TH1 : 3x - 5 = 4x + 9 => 3x - 4x = 9 + 5 => -x = 14 => x = -14

TH2 : 3x - 5 = -(4x + 9) => 3x - 5 = -4x - 9 => 3x + 4x = -9 + 5 => 7x = -4 => x = -4/7 (ko thỏa mãn x thuộc Z)

a) 2x + 5 = x - 7

    2x -x   = -7 - 5

    x         = -12

b) | x | = | 8 |

    | x | = 8

=> x = 8

   hoặc x = -8

c) | 2x-1 | = | -13 |

    | 2x-1 | = 13

=> 2x-1   = 13

     2x      = 13 + 1

     2x      = 14

     x        = 14:2

     x        = 7

hoặc 2x-1 = -13

        2x     = -13 + 1

        2x     = -12

         x      = -12 : 2

         x      = -6

a) ( 3x + 2 )( x - 1 ) - ( x + 2 )( 3x + 1 ) = 7

<=> 3x² - x - 2 - ( 3x² + 7x + 2 ) = 7

<=> 3x² - x - 2 - 3x² - 7x - 2 = 7

<=> -8x - 4 = 7

<=> -8x = 11

<=> x = -11/8

b) ( 6x + 5 )( 2x + 3 ) - ( 4x + 3 )( 3x - 2 ) = 8

<=> 12x² + 28x + 15 - ( 12x² + x - 6 ) = 8

<=> 12x² + 28x + 15 - 12x² - x + 6 = 8

<=> 27x + 21 = 8

<=> 27x = -13

<=> x = -13/27 

c) 2x( x + 3 ) - ( x + 1 )( 2x + 1 ) - 5 = 9

<=> 2x² + 6x - ( 2x² + 3x + 1 ) - 5 = 9

<=> 2x² + 6x - 2x² - 3x - 1 - 5 = 9

<=> 3x - 6 = 9

<=> 3x = 15

<=> x = 5

d) ( 5x + 3 )( 4x - 7 ) - ( 10x + 9 )( 2x - 3 ) = 10

<=> 20x² - 23x - 21 - ( 20x² - 12x - 27 ) = 10

<=> 20x² - 23x - 21 - 20x² + 12x + 27 = 10

<=> -11x + 6 = 10

<=> -11x = 4

<=> x = -4/11

a, \(\left(3x+2\right)\left(x-1\right)-\left(x+2\right)\left(3x+1\right)=7\Leftrightarrow-8x-4=7\Leftrightarrow x=-\frac{11}{8}\)

b, \(\left(6x+5\right)\left(2x+3\right)-\left(4x+3\right)\left(3x-2\right)=8\Leftrightarrow27x+21=8\Leftrightarrow x=-\frac{13}{27}\)

c, \(2x\left(x+3\right)-\left(x+1\right)\left(2x+1\right)-5=9\Leftrightarrow3x-6=9\Leftrightarrow x=5\)

d, \(\left(5x+3\right)\left(4x-7\right)-\left(10x+9\right)\left(2x-3\right)=10\Leftrightarrow-11x+6=10\Leftrightarrow x=-\frac{4}{11}\)

\(a)5-\left(10-x\right)=7\\ \Leftrightarrow5-10+x=7\\ \Leftrightarrow x=7-5+10\\ \Leftrightarrow x=12\)

\(b)\left(4x-2\right)\left(x-5\right)=0\)

\(\Leftrightarrow\)\(4x-2\) hoặc \(x-5\) bằng 0

TH1: \(\left(4x-2\right)\left(x-5\right)=0\\ \Leftrightarrow4x-2=\frac{0}{x-5}\\ \Leftrightarrow4x=0+2\\ \Leftrightarrow4x=2\\ \Leftrightarrow x=\frac{2}{4}=\frac{1}{2}\)

TH2: \(\left(4x-2\right)\left(x-5\right)=0\\ \Leftrightarrow x-5=\frac{0}{4x-2}\\ \Leftrightarrow x=0+5\\ \Leftrightarrow x=5\)

Vậy \(x=\frac{1}{2}\) hoặc \(x=5\)

\(c)2x-9=-8-9\\ \Leftrightarrow2x=-8-9+9\\ \Leftrightarrow2x=-8-\left(9-9\right)\\ \Leftrightarrow2x=-8\\ \Leftrightarrow x=-\frac{8}{2}\\ \Leftrightarrow x=-4\)

\(d)3\cdot\left|x-1\right|-27=0\\ \Leftrightarrow3\cdot\left|x-1\right|=0+27\\ \Leftrightarrow3\cdot\left|x-1\right|=27\\ \Leftrightarrow\left|x-1\right|=\frac{27}{3}\\ \Leftrightarrow\left|x-1\right|=9\\ \Leftrightarrow x-1=\pm9\)

TH1; \(x-1=9\\ \Leftrightarrow x=9+1=10\)

TH2: \(x-1=-9\\ \Leftrightarrow x=-9+1=8\)

\(e)5\cdot\left(3x+8\right)-7\left(2x+3\right)=16\\ \Leftrightarrow\left(15x+40\right)-\left(14x+21\right)=16\\ \Leftrightarrow15x+40-14x-21=16\\ \Leftrightarrow\left(15x-14x\right)+\left(40-21\right)=16\\ \Leftrightarrow x+19=16\\ \Leftrightarrow x=16-19=-3\)

\(a,\left(\frac{3}{8}+-\frac{3}{4}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)

   =  \(\left(-\frac{3}{8}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)

    = \(\frac{5}{24}:\frac{5}{6}+\frac{1}{2}\)

     = \(\frac{1}{4}+\frac{1}{2}\)

      =  \(\frac{3}{4}\)

b)\(-\frac{7}{3}.\frac{5}{9}+\frac{4}{9}.\left(-\frac{3}{7}\right)+\frac{17}{7}\)

    =\(-\frac{35}{27}+\left(-\frac{4}{21}\right)+\frac{17}{7}\)

   = \(-\frac{35}{27}+\frac{47}{21}\)

   =        \(\frac{178}{189}\)

c) \(\frac{117}{13}-\left(\frac{2}{5}+\frac{57}{13}\right)\)

  = \(\frac{117}{13}-\frac{311}{65}\)

 =       \(\frac{274}{65}\)

d) \(\frac{2}{3}-0,25:\frac{3}{4}+\frac{5}{8}.4\)

= \(\frac{2}{3}-\frac{1}{4}:\frac{3}{4}+\frac{5}{8}.4\)

= \(\frac{2}{3}-\frac{1}{3}+\frac{5}{2}\)

=     \(\frac{1}{3}+\frac{5}{2}\)

=         \(\frac{17}{6}\)