tim cac so tu nhien n de cac phan so sau la phan so toi gian a) 2n+3:4n+1 b) 3n+2:7n+1 c) 2n+7:5n+2
Tim cac so tu nhien n de cac phan so sau la phan so toi gian:
a)2n+3/4n+1 b) 3n+2/7n+1 c)2n+7/5n+2
Mình xin lỗi , mình xin chịu lúc nào mình nghĩ ra thì mình sẽ giúp cậu
tim cac so tu nhien n de cac phan so sau la phan so toi gian
2n+3 tren 4n+1
tim cac so tu nhien n khac 0 de cac phan so sau la phan so toi gian
7/n-3
n+7/n+2
2n+16/n+5
3n+4/n3
a) đe 7/n-3 là phân số tối giản.
\(\Leftrightarrow\)U(7)= { 1;7}
\(\Leftrightarrow\)n - 3 = 7 \(\Leftrightarrow\)n = 7+ 3 = 10
\(\Leftrightarrow\)n - 3 = 1 \(\Leftrightarrow\)n = 1 + 3 = 4
Tìm n đẻ cac phan so sau toi gian
3n+2/7n+1
2n+7/5n+2
8n+193/4n+3
6n+99/3n+4
Cau 1: Chung minh rang cac phan so sau la phan so toi gian voi moi so nguyen?
a, 8n + 5 phan 6n + 4 b, n + 1 phan 2n + 3 c, 2n + 3 phan 3n + 5
Cau 2: Tim tat ca cac so tu nhien n de phan so sau la toi gian
a, n + 13 phan n - 2. b, 18n + 3 phan 21n + 7
Ai giai day du va nhanh thi mk se tick cho
Tim so tu nhien n de phan so A=\(\frac{2n+1}{n-3}+\frac{3n-5}{n-3}-\frac{4n-5}{n-3}\)
a/Tim n de A nhan gia tri nguyen
b/Tim n de A la phan so toi gian
Cho n thuoc N, chung to cac phan so sau la toi gian :
a, 2n+1/5n+2
b, 5n+2/3n+1
c, 5n+2/(3n+1).(2n+1)
a, gọi d là ƯCLN(2n+1, 5n+2 )
\(\Rightarrow\hept{\begin{cases}2n+1⋮d\\5n+2⋮d\end{cases}}\Rightarrow\hept{\begin{cases}5\left(2n+1\right)⋮d\\2\left(5n+2\right)⋮d\end{cases}}\Rightarrow\hept{\begin{cases}10n+5⋮d\\10+4⋮d\end{cases}}\)
\(\Rightarrow\left(10+5\right)-\left(10+4\right)⋮d\)
\(\Rightarrow10+5-10-4⋮d\)
\(\Rightarrow1⋮d\)
\(\Rightarrow d=\left\{-1;1\right\}\)
vậy...............
CMR: Neu phan so 7n^2+1/6 la so tu nhien voi n thuoc N thi cac phan so n/2 va n/3 la cac phan so toi gian
tim tat ca cac so tu nhien n de phan so n+3/n -12 la phan so toi gian
Ta có: n+3 chia hết n-12
=> n-12+15 chia hết n-12
mà n-12 chia hết n-12
=> 15 chia hết n-12
=> n-12 thuộc Ư(15)={1; -1; 3; -3; 5; -5; 15; -15}
=> n thuộc {3; 11; 15; 9; 17; 7; 27; -3}