\(42-2\left(32-2^{x+1}\right)=10\)

\(\Leftrightarrow2\left(32-2^{x+1}\right)=42-10=32\)

\(\Leftrightarrow32-2^{x+1}=16\)

\(\Leftrightarrow2^{x+1}=32-16=16\)

\(\Leftrightarrow2^{x+1}=2^4\)

\(\Leftrightarrow x+1=4\)

\(\Rightarrow x=3\)

\(42-2\left(32-2^{x+1}\right)=10\)

\(\Leftrightarrow2^{x+1}=16\)

\(\Leftrightarrow2^{x+1}=2^4\)

=> x = 4

\(42-2.\left(32-2^{x+1}\right)=10\)

\(2.\left(32-2^{x+1}\right)=42-10\)

\(2.\left(32-2^{x+1}\right)=32\)

\(32-2^{x+1}=32:2\)

\(32-2^{x+1}=16\)

\(2^{x+1}=32-16\)

\(2^{x+1}=16\)

\(2^{x+1}=2^4\)

\(x+1=4\)

\(x=4-1\)

\(x=3\)

Làm lại :< 

\(42-2\left(32-2^{x+1}\right)=10\)

\(\Leftrightarrow2^{x+1}=16\)

\(\Leftrightarrow x^{x+1}=2^4\)

\(\Leftrightarrow x=4-1\)

<=> x = 3

=>m>x

cam on cac ban nhieu minh se ket ban tung ban

x = 64 - 32 = 32

m = 168 - 42 = 126

Vì m = 126

    x  = 32  

=> m > x

 Tìm x: (3.x + 11) – 17 = 30

a, x - 108 × 42 = 2378

=> x - 4536 = 2378

=> x = 6914

vậy_

b,1337 + 13 × x = 6745

=> 10 × x = 5408

=> x = 540,8

vậy_

c, x × 10 + 16 × x = 972

=> x × (10 + 16) = 972

=> x× 26 = 972

=> x = \(\frac{486}{13}\)

vậy_

d, 25 × x - x  = 59904 : 32

=> x × (25 - 1) = 1872

=> x × 24 = 1872

=> x = 78

vậy_

\(x-108.42=2378\)

\(x-4536=2378\)

\(x=6914\)

\(2,\)

\(a,20-\left[4^2+\left(x-6\right)\right]=90\)

\(\Rightarrow20-16-x+6=90\)

\(\Rightarrow10-x=90\)

\(\Rightarrow x=-80\)

Vậy: \(x=-80\)

\(b,\left(x+3\right)\left(2x-4\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x+3=0\\2x-4=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=-3\\x=2\end{matrix}\right.\)

Vậy: \(x\in\left\{-3;2\right\}\)

\(c,1000:\left[30+\left(2^x-6\right)\right]=3^2+4^2\left(x\in N\right)\)

\(\Rightarrow1000:\left(30+2^x-6\right)=25\)

\(\Rightarrow24+2^x=40\)

\(\Rightarrow2^x=16\)

\(\Rightarrow x=4\)

Vậy: \(x=4\)

:))))