\(2^{x+2}\cdot3^{x+1}\cdot5x=10800\)

\(2^x\cdot2^2\cdot3^x\cdot2\cdot5^x=10800\)

\(\left(2\cdot3\cdot5\right)^x\cdot12=10800\)

\(30^x=10800\div12\)

\(30^x=900\)

\(\Leftrightarrow30^{x=}=30^2\Leftrightarrow x=2\)

chả hiểu

bạn nguyễn thu thủy làm sai r nhé 
10800:2=5400
chứ không phải 18000:2=900

<=> 2^x+2*3^x+1*5^x-10800=0

=>x=\(\frac{7079}{1250}\)

\(2^{x+2}.3^{x+1}.5^x=10800\)

\(2^x.2^2.3^x.2.5^x=10800\)

\(\left(2.3.5\right)^x.12=10800\)

\(30^x=10800:12\)

\(30^x=900\)

\(30^x=30^2\Rightarrow x=2\)

ai tích mk h lại

2^x+2.3^x+1.5^x=10800

=>2^x.2².3^x.3.5^x=10800

=>2^x.3^x.5^x=10800:3:2²

=>30^x=900

=>30^x=30²

=>x=2

Ta có : \(10800=2^4.3^3.5^2\)

\(\Rightarrow2^{x+2}.3^{x+1}.5^x=2^4.3^3.5^2\Rightarrow x=2.\)

x=2

100%

2x+2.3x+1.5x=10800

2x.22.3x.2.5x=10800

(2.3.5)x.12=10800

30x=10800:12

30x=900

\(30^{^{ }m}\)\(30^2\Rightarrow x=2\)

\(2^{x+2}.3^{x+1}.5^x=10800\)

\(\Leftrightarrow2^x.2^2.3^x.3.5^x=10800\)

\(\Leftrightarrow30^x.12=10800\)

\(\Leftrightarrow30^x=900\)

\(\Leftrightarrow30^x=30^2\)

\(\Leftrightarrow x=2.\)

\(2^{x+2}.3^{x+1}.5^x=10800\)

\(\Rightarrow4.2^x.3.3^x.5^x=10800\)

\(\Rightarrow\left(2.3.5\right)^x.12=10800\)

\(\Rightarrow30^x=900=30^2\)

Vì \(30\ne-1;30\ne1;30\ne0\) nên \(x=2\).

Chúc bạn học tốt!!!

2^x+2.3^x+1.5^x =10800

⇔2^x.4.3^x.3.5^x =10800

⇔30^x =10800:12=900

⇔30^x =30²

⇒ x=2

CHÚC BN HỌC TỐT ^-^

1. \(A=\left(\frac{3}{2}-\frac{2}{5}+\frac{1}{10}\right):\left(\frac{3}{2}-\frac{2}{3}+\frac{1}{12}\right)=\frac{6}{5}:\frac{11}{12}=\frac{6}{5}.\frac{12}{11}=\frac{72}{55}\)

2. 2^x+2 . 3^x+1 . 5^x = 10800

=> 2^x . 2² . 3^x . 3 . 5^x = 10800

=> ( 2 . 3 . 5 )^x . 12 = 10800

=> 30^x = 900

=> 30^x = 30²

=> x = 2

\(2^{x+2}\cdot3^{x+1}\cdot5^x=10800\)

\(2^x\cdot2^2\cdot3^x\cdot3\cdot5^x=10800\)

\(4\cdot3\cdot2^x\cdot3^x\cdot5^x=10800\)

\(12\cdot\left(2\cdot3\cdot5\right)^x=10800\)

\(12\cdot30^x=10800\)

\(30^x=10800:12\)

\(30^x=900\)

\(30^x=30^2\)

=> x = 2