1) ab + ac = a(b + c)

2) ab - ac + ad = a(b - c + d)

3) ax - bx - cx + dx = x(a - b - c + d)

4) a(b + c) - d(b + c) = (b + c)(a - d)

5) ac - ad + bc - bd = a(c - d) + b(c - d) = (c - d)(a + b)

6) ax + by + bx + ay = (ax + ay) + (bx + by) = a(x + y) + b(x + y) = (x + y)(a + b)

ab + ac = a ( b + c )

ab - ac + ad = a ( b - c + d )

ax - bx - cx + dx = x ( a - b - c + d )

1/ab+ac=a(b+c)

2/ab-ac+ad=a(b-c)+ad=a(b-c+d)

3/ax-bx-cx+dx=x(a-b-c)+xd=x(a-b-c+d)

4/a(b+c)-d(b+c)=(ab+ac)-(bd+cd)=b(a+d)-c(a+d)=a+d(b+c)

5/ac-ad+bc-bd=a(c-d)+b(c-d)=c-d(a+b)

6/ax+by+bx+ay=a(x+y)+b(x+y)=x+y(a+b)

1/ ab+ac=a(b+c)

2/ab-ac+ad=a(b-c+d)

3/ax-bx-cx+dx=x(a-b-c+d)

4/a(b+c)-d(b+c)=(b+c)(a-d)

5/ac-ad+bc-bd=a(c-d)+b(c-d)=(c-d)(a+b)

6/ax+by+bx+ay=a(x+y)+b(y+x)=(y+x)(a+b)

\(1,ab+ac\)

\(=a\left(b+c\right)\)

\(2,ab-ac+ad\)

\(=a\left(b-c+d\right)\)

\(3,ax-bx-cx+dx\)

\(=x\left(a-b-c+d\right)\)

\(4,a\left(b+c\right)-d\left(b+c\right)\)

\(=\left(b+c\right)\left(a-d\right)\)

\(5,ac-ad+bc-bd\)

\(=a\left(c-d\right)+b\left(c-d\right)\)

\(=\left(a+b\right)\left(c-d\right)\)

\(6,ax+by+bx+ay\)

\(=\left(ax+bx\right)+\left(by+ay\right)\)

\(=x\left(a+b\right)+y\left(a+b\right)\)

\(=\left(x+y\right)\left(a+b\right)\)

1? 

a(b+c)

a(b-c+d)

x(a-b-c+d)

(b+c)(a-d)

(c-d)(a+b)

(x+-y)(a+b)

1/ ab+ ac

=a(b+c)

2/ ab - ac + ad

=a(b-c+d)

3/ ax - bx - cx + dx

=x(a-b-c+d)

4/ a(b + c) - d(b + c)

=(a-d)(b+c)

5/ ac - ad + bc - bd

=a(c-d)+b(c-d)

=(a+b)(c-d)

6/ ax + by + bx + ay

=x(a+b)+y(b+a)

=(x+y)(b+a)

A) ab + ac=a.(b+c)

B)ab - ac + ad=a.(b-c+d)

C) ã-bx-cx+dx=x.(a-b-c+d)

D)a(b+c) - d(b+c)=(b+c).(a-d)

E) ac-ad+bc-bd=a.(c-d)+b.(c-d)=(c-d).(a+b)

G) ax+by+bx+ay=x.(a+b)+y.(b+a)=(a+b).((x.y)

1) \(ab+ac=a\left(b+c\right)\)

2) \(ab-ac+ad=a\left(b-c+d\right)\)

3) \(ax-bx-cx+dx=x\left(a-b-c+d\right)\)

4) \(a\left(b+c\right)-d\left(b+c\right)=\left(b+c\right)\left(a-d\right)\)

5) \(ac-ad+bc-bd=a\left(c-d\right)+b\left(c-d\right)=\left(a+d\right)\left(c-d\right)\)

6) \(ax+by+bx+ay=x\left(a+b\right)+y\left(a+b\right)=\left(x+y\right)\left(a+b\right)\)

1 .  a(a+b)

2 .    a(b-c+d)

2   .  x(a-b-c+d)

4  (b+c)(a-d)

5   ac-d) + b(c-d)  = (c-d)(a+b)

6  x(a+b)+y(a+b)= (a+b)(x+y)

1/ a(b+c)

2/ a(b-c+d)

3/ x(a-b-c+d)

4/ (a-d)(b+c)

5/ (a+b)(c-d)

6/ (a+b)(x+y)

ĐẶT NHÂN TỬ CHUNG NHA!

1) ab - ac + ad = a( b- c +d ) 

2) ax - bx - cx + dx = x( a-b-c+d)

3) a.( b + c ) - d . ( b + c )= (b+c)(a-d)

4) ac - ad + bc - bd = a( c-d)  + b( c-d) = (a+b)(c-d)

5) ax + by + bx + ay= a( x+y) + b( x+y) = (a+b)(x+y)

1, a(a+b)

2, a(b-c+d)

3, x(a-b-c+d)

4, (b+x)(a-b)

5, (a+b)(y+x)

~ học tốt nhé @Zin Zin

Bài 17:

1/ a(b + c)

2/ a(b - c - d)

3/ x(a + b - c + d)

4/ (a - d)(b - c)

5/ a(c - d) + b(c - d) = (a + b)(c - d)

6/ a(x + y) + b(x + y) = (a + b)(x + y)

Chúc bạn học tốt!

1) ab + ac

= a ( b + c )

2) ab - ac + ad

= a ( b - a + d )

3) ax - bx - cx + dx

= x ( a - b - c + d )

4) a(b + c) - d(b + c)

= ( a - d ) . (b + c )

5) ac - ad + bc - bd

= a ( c - d ) + b ( c - d )

= ( a + b ) . ( c - d )

6) ax + by + bx + ay

= x . ( a + b ) + y . ( a + b )

= ( x + y ) . ( a + b )

1) ab + ac

\(\Rightarrow a.\left(b+c\right)\)

2) ab - ac + ad

\(\Rightarrow a.\left(b-c+d\right)\)

3) ax - bx - cx + dx

\(\Rightarrow x.\left(a-b-c-d\right)\)

4) a(b + c) - d(b + c)

\(\Rightarrow\left(b+c\right).\left(a-d\right)\)

5) ac - ad + bc - bd

\(\Rightarrow a.\left(c-d\right)+b.\left(c-d\right)\)

\(\Rightarrow\left(c-d\right).\left(a+b\right)\)

6) ax + by + bx + ay

\(\Rightarrow ax+bx+ay+by\)

\(\Rightarrow x.\left(a+b\right)+y.\left(a+b\right)\)

\(\Rightarrow\left(a+b\right).\left(x+y\right)\)

Hà Giang: bài trước tớ lm sai câu 3 á

sorry!!

1) ab + ac

\(\Rightarrow a\left(b+c\right)\)

2) ab - ac + ad

\(\Rightarrow a\left(b-c+d\right)\)

3) ax - bx - cx + dx

\(\Rightarrow x\left(a-b-c+d\right)\)

4) a(b + c) - d(b + c)

\(\Rightarrow\left(b+c\right)\left(a-d\right)\)

5) ac - ad + bc - bd

\(\Rightarrow a\left(c-d\right)+b\left(c-d\right)\)

\(\Rightarrow\left(c-d\right)\left(a+b\right)\)

6) ax + by + bx + ay

\(\Rightarrow ax+bx+ay+bx\)

\(\Rightarrow x\left(a+b\right)+y\left(a+b\right)\)

\(\Rightarrow\left(a+b\right)\left(x+y\right)\)

1)a(b+c)

2)a(b-c+d)

3)x(a-b-c+d)

4)(b+c)(a-d)

5)(c-d)(a+b)

6)(x+y)(a+b)

1/ ab+ac=a.b+a.c=a(b+c)