S = -( -a + b + c ) + ( -c - b - a ) - ( a - b )

S = a - b - c - c - b - a - a + b

S = - a - b - 2c 

\(S=-\left(-a+b+c\right)+\left(-c-b-a\right)-\left(a-b\right)\)

\(S=a-b-c-c-b-a-a+b\)

\(S=-2c-a-b\)

\(S=-2c-\left(a+b\right)\)

\(S=-2c-2020\)

hok tốt!!

\(a^{2020}+b^{2020}+c^{2020}=a^{1010}b^{1010}+b^{1010}c^{1010}+c^{1010}a^{1010}\)

\(\Leftrightarrow a^{2020}+b^{2020}+c^{2020}-a^{1010}b^{1010}-b^{1010}c^{1010}-c^{1010}a^{1010}=0\)

\(\Leftrightarrow2a^{2020}+2b^{2020}+2c^{2020}-2a^{1010}b^{1010}-2b^{1010}c^{1010}-2a^{1010}c^{1010}=0\)

\(\Leftrightarrow\left(a^{2020}-2a^{1010}b^{1010}+b^{2020}\right)+\left(b^{2020}-2b^{1010}c^{1010}+c^{2020}\right)+\left(c^{2020}-2a^{1010}c^{1010}+a^{2020}\right)=0\)

\(\Leftrightarrow\left(a^{1010}-b^{1010}\right)^2+\left(b^{1010}-c^{1010}\right)^2+\left(c^{1010}-a^{1010}\right)^2=0\)

\(\Leftrightarrow\hept{\begin{cases}\left(a^{1010}-b^{1010}\right)=0\\b^{1010}-c^{1010}=0\\c^{1010}-a^{1010}=0\end{cases}}\Leftrightarrow a^{1010}=b^{1010}=c^{1010}\Leftrightarrow\pm a=\pm b=\pm c\)

Rồi thay :> Còn thay kiểu nào thì mình cũng hong biết :">

Trả lời nhanh giúp mik đi. Mình cần gấp :((

CTL

A=100 nha

Bạn giải chi tiết cho mik dc không

S = a + b + c - c + b + a - a - b = a + b

\(a^2+b^2+c^2=1\Rightarrow-1\le a,b,c\le1;a^3-a^2+b^3-b^2+c^3-c^2\)

\(=a^2\left(a-1\right)+b^2\left(b-1\right)+c^2\left(c-1\right)=0\Rightarrow a^2\left(a-1\right)=0;b^2\left(b-1\right)=0;c^2\left(c-1\right)=0\)

\(\text{kết hợp với:}a^3+b^3+c^3=1\Rightarrow\text{có 2 số bằng 0; 1 số bằng 1}\Rightarrow S=1\)

S = - a + b + c - c + b + a - a - b

S = - a

Vì a = 1 => S = -1

S = -(a - b - c) + (-c + b + a) - (a + b)

= -a + b + c - c + b + a - a - b

= (-a + a - a) + (b + b - b) + (c - c)

= -a + b

= -1 + b = b - 1

ai đúng đây ta

S=-(a-b-c)+(-c+b+a)-(a+b)

=-a+b+c-c+b+a-a-b

=-a+b+c+(-c)+b+a+(-a)+(-b)

=[(-a)+a+(-a)]+[b+b+(-b)]+[c+(-c)]

=-a+b

vì a>b nên |S|=a-b

vậy...

k mình nha. kb nữa...^_^...