A=2011/1.2+2011/3.4+2011/4.5+...+2011/1999.2000
B=2012/1001+2012/1002+2012/1003+...+2012/2000
So sánh A và B
Giúp Mk cho tick lun Thx
So sánh
A=2011/1.2+ 2011/3.4+2011/5.6+...+2011/1999.2000
B=2012/1001+2012/1002+2012/1003+...+2012/2000
Giups mk với mk cần gấp lắm
$A=\frac{2011}{1.2}+\frac{2011}{3.4}+\frac{2011}{5.6}+...+\frac{2011}{1999.2000}$
$B=\frac{2012}{1001}+\frac{2012}{1002}+\frac{2012}{1003}+...\frac{2012}{2000}$
So sánh A với B:
a:A=-2012/4025;B=-1999/3997
b:A=2011/1.2+2011/3.4+.....+2011/1999.2000; B=2012/1001+2012+1002+...+2012/2000
so sánh A = 2011/1.2 +2011/3.4 +...+2011/1999.2000 ; B = 2012/1001 +2012/1002 +...+2012/2000
\(B=\dfrac{2011}{1.2}+\dfrac{2011}{3.4}+\dfrac{2011}{5.6}+...+\dfrac{2011}{1999.2000}\)
\(C=\dfrac{2012}{1001}+\dfrac{2012}{1002}+\dfrac{2012}{1003}+...+\dfrac{2012}{2000}\)
Hãy tính b và c giúp mình nhé
So sánh A và B trong những trường hợp sau:
a) A = \(\frac{-2012}{4025}\); B = \(\frac{-1999}{3997}\)
b) A = \(\frac{2011}{1.2}+\frac{2011}{3.4}+...+\frac{2011}{1999.2000}\); B = \(\frac{2012}{1001}+\frac{2012}{1002}+...+\frac{2012}{2000}\)
Ta có:
A=-2012/4025=>-2012/4025x2=-4024/4025
B=-1999/3997=>-1999/3997x2=-3998/3997
Ta có: 4024/4025<1<3998/3997
=>4024/4025<3998/3997
=>-4024/4025>-3998/3997
=>-2012/4025>-1999/3997
Có ai biết làm câu b) ko vậy, mình ko biết làm, giúp mình với!!
so sánh A=2011/1.2 +2011/3.4+2011/5.6 +..........+2011/1999.2000
B=2012/1001+2012/1002+.........+2012/2000
giúp vs các bn
theo bài ra ta có:
\(A=\dfrac{2011}{1.2}+\dfrac{2011}{3.4}+...+\dfrac{2011}{1999.2000}\)
\(\Rightarrow\dfrac{A}{2011}=\dfrac{1}{1.2}+\dfrac{1}{3.4}+...+\dfrac{1}{1999.2000}\)
\(\Rightarrow\dfrac{A}{2011}=\dfrac{1}{1}-\dfrac{1}{2}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{1999}-\dfrac{1}{2000}\)
\(\Rightarrow\dfrac{A}{2011}=\left(\dfrac{1}{1}+\dfrac{1}{3}+...+\dfrac{1}{1999}\right)-\left(\dfrac{1}{2}+\dfrac{1}{4}+...+\dfrac{1}{2000}\right)\)
\(\Rightarrow\dfrac{A}{2011}=\left(\dfrac{1}{1}+\dfrac{1}{2}+...+\dfrac{1}{2000}\right)-\left(\dfrac{1}{2}+\dfrac{1}{4}+...+\dfrac{1}{2000}\right)-\left(\dfrac{1}{2}+\dfrac{1}{4}+...+\dfrac{1}{2000}\right)\) \(\Rightarrow\dfrac{A}{2011}=\left(\dfrac{1}{1}+\dfrac{1}{2}+...+\dfrac{1}{2000}\right)-2\left(\dfrac{1}{2}+\dfrac{1}{4}+...+\dfrac{1}{2000}\right)\) \(\Rightarrow\dfrac{A}{2011}=\left(\dfrac{1}{1}+\dfrac{1}{2}+...+\dfrac{1}{2000}\right)-\left(\dfrac{1}{1}+\dfrac{1}{2}+...+\dfrac{1}{1000}\right)\) \(\Rightarrow\dfrac{A}{2011}=\dfrac{1}{1001}+\dfrac{1}{1002}+...+\dfrac{1}{2000}\)
\(\Rightarrow A=2011\left(\dfrac{1}{1001}+\dfrac{1}{1002}+...+\dfrac{1}{2000}\right)\left(1\right)\)
ta lại có:
\(B=\dfrac{2012}{1001}+\dfrac{2012}{1002}+...+\dfrac{2012}{2000}\\ \Rightarrow B=2012\left(\dfrac{1}{1001}+\dfrac{1}{1002}+...+\dfrac{1}{2000}\right)\left(2\right)\)
Từ 1 và 2 => A < B\
vậy A < B
1. Tinh a \(\left(6^9.2^{10}+12^{10}\right)+\left(2^{19}.27^3+15.4^9.9^4\right)\)
2. So sanh A va B.
a) \(A=\frac{-2012}{4025};B=\frac{-1999}{3997}\)
b) \(A=3^{21};B=2^{31}\)
c) \(A=\frac{2011}{1.2}+\frac{2011}{3.4}+\frac{2011}{5.6}+....+\frac{2011}{1999.2000};\)\(B=\frac{2012}{1001}+\frac{2012}{1002}+\frac{2012}{1003}+....+\frac{2012}{2000}\)
1/ (69.210+1210)+(219.273+15.49.94) = 29.39.210+310.220+219.39+5.3.218.38 = 219.39+310.220+219.39+5.218.39
= 218.39(2+3.22+5)=19.218.39
sao bạn lại nhắn vớ va vớ vậy PHẠM ĐỨC PHÚC
1/ (69
.210+1210
)+(219
.273+15.49
.94
) = 29
.39
.210+310
.220+219
.39+5.3.218
.38
= 219
.39+310
.220+219
.39+5.218
.39
= 2
18
.39
(2+3.22+5)=19.218
.39
So sánh :A= 2011^2012+ 4 / 2011^2012-1 và B=2011^2012+1/2011^2012-4