x + 3/4 x 7/10 = 53/40

x + 21/40 = 53/40

x = 53/40 - 21/40

x = 32/40

x = 4/5

34/35 : x = 17/5

x = 34/35 : 17/5

x = 34/35 x 5/17

x = 2/7

x + 3/4 x 7/10 = 53/40

x + ( 3/4 x 7/10 ) = 53/40

x + 21/40 = 53/40 ( tới đây bn cứ lm như bth )

x              = 53/40 - 21/40

x              = 4/5

34/35 : x = 17/5

x             = 34/35 : 17/5

x             = 2/7

\(a,\) \(x+\dfrac{3}{4}\times\dfrac{7}{10}=\dfrac{53}{40}\) 

    \(x+\dfrac{21}{40}=\dfrac{53}{40}\) 

            \(x=\dfrac{53}{40}-\dfrac{21}{40}\) 

            \(x=\dfrac{4}{5}\) 

\(b,\) \(\dfrac{34}{35}:x=\dfrac{17}{5}\) 

            \(x=\dfrac{34}{35}:\dfrac{17}{5}\) 

            \(x=\dfrac{2}{7}\)

làm giúp mk bài này nhá                                                                                                              0+1+2+...+2017  có bao nhiêu số hạng

ghi đề rõ ra đi bạn

B

b

B

Ghi cả cách trình bày nha mọi người

\(a,\dfrac{4}{15}:\dfrac{4}{7}< x< \dfrac{2}{5}\times\dfrac{10}{3}\\ \Leftrightarrow\dfrac{7}{15}< x< \dfrac{4}{3}\\ \Leftrightarrow x=1\)

\(b,\dfrac{3}{5}\times\dfrac{3}{7}+\dfrac{2}{5}\times\dfrac{4}{7}=\dfrac{9}{35}+\dfrac{8}{35}=\dfrac{17}{35}\)

\(a.\frac{19}{5}\cdot\frac{4}{7}+\frac{3}{7}\cdot\frac{19}{5}-\frac{4}{5}\)

\(=\frac{19}{5}\cdot\left(\frac{4}{7}+\frac{3}{7}\right)-\frac{4}{5}\)

\(=\frac{19}{5}\cdot1-\frac{4}{5}\)

\(=\frac{19}{5}-\frac{4}{5}=\frac{15}{5}=3\)

\(b.2\frac{2}{7}\cdot5\frac{2}{5}+\frac{16}{7}\cdot1\frac{3}{5}+\frac{1}{2}\)

\(=\frac{16}{7}\cdot\frac{27}{5}+\frac{16}{7}\cdot\frac{8}{5}+\frac{1}{2}\)

\(=\frac{16}{7}\cdot\left(\frac{27}{5}+\frac{8}{5}\right)+\frac{1}{2}\)

\(=\frac{16}{7}\cdot7+\frac{1}{2}\)

\(=16+\frac{1}{2}=\frac{33}{2}\)

\(c.\frac{3}{7}\cdot3\frac{3}{4}-\frac{3}{7}\cdot\frac{5}{4}-\frac{1}{4}\)

\(=\frac{3}{7}\cdot\frac{15}{4}-\frac{3}{7}\cdot\frac{5}{4}-\frac{1}{4}\)

\(=\frac{3}{7}\cdot\left(\frac{15}{4}-\frac{5}{4}\right)-\frac{1}{4}\)

\(=\frac{3}{7}\cdot\frac{5}{2}-\frac{1}{4}\)

\(=\frac{15}{14}-\frac{1}{4}=\frac{23}{28}\)

Chú ý: \(\cdot:\times\)