Ta có: 13/12 = 1/12 + 6/12 + 6/12 = 1/12 + 1/2  + 1/2

Còn Cái Nịt

13/12 = 1/12 + 5/12 + 7/12

5/12 + 7/12 + 1/12 = 13/12 . tick đúng nhé

\(\frac{13}{12}=\frac{1}{12}+\frac{5}{12}+\frac{7}{12}\)

5/12+7/12+1/12=13/12

tick nha ban

$\frac{\mathrm{13/}}{12}=\frac{6}{\mathrm{/12}}+\frac{\mathrm{4/}}{12}+\frac{\mathrm{3/}}{12}=\frac{1}{\mathrm{/2}}+\frac{1}{\mathrm{/3}}+\frac{1}{\mathrm{/4}}$

ok

13/12=1/2+1/3+1/4

câu khó quá

không biết đáp án

\(\frac{7}{12}=\frac{3}{12}+\frac{4}{12}=\frac{1}{4}+\frac{1}{3}\)

\(\frac{13}{27}=\frac{1}{27}+\frac{3}{27}+\frac{9}{27}=\frac{1}{27}+\frac{1}{9}+\frac{1}{3}\)

giúp mình với

7/12=1/12+6/12=1/12=1/2                                                                        = 7/12=2/12+5/12=1/6+5/12                                                                      =7/12=3/12+4/12=1/4+1/3                                                                                  bạn cũng có thể viết nhiều hơn nữa ..

\(\dfrac{7}{12}\) = \(\dfrac{1}{12}\) + \(\dfrac{1}{2}\)        

\(\dfrac{7}{12}\)  = \(\dfrac{1}{6}\) + \(\dfrac{5}{12}\)

\(\dfrac{7}{12}\) = \(\dfrac{1}{4}\) + \(\dfrac{1}{3}\) 

10/27: 1/27+7/27+2/27

13/12: 1/12+7/12+5/12

15/8:7/8+3/8+5/8

10/27 = 1/27+2/27+7/27

13/12 = 1/12+5/12+7/12

15/8 =  3/8+5/8+7/8

ko biết nữa tui gà lắm

\(\dfrac{7}{12}=\dfrac{3}{12}+\dfrac{4}{12}=\dfrac{1}{4}+\dfrac{1}{3}\)

\(\dfrac{13}{27}=\dfrac{9}{27}+\dfrac{4}{27}=\dfrac{1}{3}+\dfrac{4}{27}\)

\(\dfrac{7}{12}\) = \(\dfrac{1+6}{12}\) = \(\dfrac{1}{12}\) + \(\dfrac{6}{12}\) = \(\dfrac{1}{12}\) + \(\dfrac{1}{2}\)

\(\dfrac{7}{12}\) = \(\dfrac{3+4}{12}\) = \(\dfrac{3}{12}\) + \(\dfrac{4}{12}\) = \(\dfrac{1}{4}\) + \(\dfrac{1}{3}\)

\(\dfrac{13}{27}\) = \(\dfrac{1+12}{27}\) = \(\dfrac{1}{27}\) + \(\dfrac{12}{27}\) = \(\dfrac{1}{27}\) + \(\dfrac{4}{9}\)

\(\dfrac{13}{27}\) = \(\dfrac{4+9}{27}\) = \(\dfrac{4}{27}\) + \(\dfrac{9}{27}\) = \(\dfrac{4}{27}\) + \(\dfrac{1}{3}\)

\(\dfrac{13}{27}\) = \(\dfrac{6+7}{27}\) = \(\dfrac{6}{27}\) + \(\dfrac{7}{27}\) = \(\dfrac{2}{9}\) +  \(\dfrac{7}{27}\)

a, \(\dfrac{7}{12}=\dfrac{6+1}{12}=\dfrac{6}{12}+\dfrac{1}{12}=\dfrac{6}{6\times2}+\dfrac{1}{12}=\dfrac{1}{2}+\dfrac{1}{12}\)

b, \(\dfrac{13}{27}=\dfrac{12+1}{27}=\dfrac{12}{27}+\dfrac{1}{27}=\dfrac{3\times4}{3\times9}+\dfrac{1}{27}=\dfrac{4}{9}+\dfrac{1}{27}\)

đây là đáp án của mình ạ.