Tim x biet 2(|x-1|+x-4/5)=2x-2/5
Tim x biet
A, |2x + 1|= 5
B, |x-4|= |2 -x|
C, |x - 5|= 2 -x biet x > 5
a, \(\left|2x+1\right|=5\Rightarrow2x+1\in\left\{5;-5\right\}\)
+) Nếu :\(2x+1=5\Rightarrow2x=4\Rightarrow x=4\div2=2\)
+) Nếu : \(2x+1=-5\Rightarrow2x=-6\Rightarrow x=-6\div2=-3\)
Vậy \(x\in\left\{2;-3\right\}\)
b, \(\left|x-4\right|=\left|2-x\right|\)
\(\Rightarrow\left[\begin{matrix}x-4=2-x\\x-4=-\left(2-x\right)\end{matrix}\right.\)
+) Nếu : x - 4 = 2 - x
\(\Rightarrow x+x=2+4\Rightarrow2x=6\Rightarrow x=3\)
+) Nếu : x - 4 = - ( 2 - x )
\(\Rightarrow x-4=-2+x\Rightarrow x-x=-2+4\Rightarrow0=2\) ( loại )
Vậy x = 3 thỏa mãn đề bài
c, \(\left|x-5\right|=2-x\Rightarrow\left|x-5\right|+x=2\)
+) Nếu : \(x< 5\Rightarrow x-5< 5-5\Rightarrow x-5< 0\Rightarrow\left|x-5\right|=-x+5\)
Thay vào đề , ta có :
\(-x+5+x=2\Rightarrow-x+x+5=2\Rightarrow5=2\) ( loại )
+) Nếu : \(x\ge5\Rightarrow x-5\ge5-5\Rightarrow x-5\ge0\Rightarrow\left|x-5\right|=x-5\)
Thay vào đề , ta có :
\(\left(x-5\right)-x=2\Rightarrow x-5-x=2\)
\(\Rightarrow x-x-5=2\Rightarrow-5=2\) ( loại )
Vậy \(x\in\varnothing\)
tim x biet (2x-3)^2-4(x+1)^2=5
bai1.tim x biet:
a,(x+2).(x+3)-(x-2).(x+5)=0
b,(2x+3).(x-4)+(x-5).(x-2)=(3x-5).(x-4)
c,(8x-3).(3x+2)-(4x+7).(x+4)=(2x+1).(5x-1)=33
,(8x-3).(3x+2)-(4x+7).(x+4)=(2x+1).(5x-1)-33 đúng không bạn
tim x biet (2x-3)^2-4.(x+1)^2=5
TA CÓ \(\left(2X-3\right)^2-4.\left(X+1\right)^2=5\)
=>\(\left(2X-3\right)^2-\left(4X+4\right)^2=5\)
=>\(\left(2X-3\right)^2=5;\left(4X+4\right)^2=5\)
=>\(\orbr{\begin{cases}2X-3=5\\4X+4=5\end{cases}}\) =>\(\orbr{\begin{cases}2X=8\\4X=1\end{cases}}\) =>\(\orbr{\begin{cases}X=4\\X=\frac{1}{4}\end{cases}}\)
Tim x biet.
a/x+5+x-7+x-9=x-5+x-2
b/9(2x-3)+5=4(4-1)-8
c/2=-(×-1)^5+34
d/7=-|x-5|+10
1)tim x biet rang:
a)3^x-1=1/243
b)2^x+2^x+3=144
c)81^-2x.27x=9^5
2)tim tiep so ghang thu 5 cua day so sau:-1/a^2;2/a^3;-6/a^4;24/a^5;...
3)tim so tu nhien x biet :
a)4^x+4^x+3=4160
b)2^x-1+5.2^x-2=7/32
Tim x, biet:
a) (-5)-(x+5)=3-(2x-5)
b)2(x-3)-3(x-2)=3(x+1)-5(x-2)
C)4(1-2x)=(-3)-3(2+3x)
Giải ngay nhé, chiều mình đi học rồi.
Tim xthuoc Z biet:
1,|2x-5|-|2x+9|=0
2,|x+1|-|x+2|-|3-x|=7
3,|2x+3|+|3x+2|-|4-x|=10
Tim x, biet :
(x+2)(x^2-2x+4)+x(5-x)(x+5)=0