3^x=3^2x3^2

3^x=3^4

Suy ra x =4

Giải 1 phần thui mệt was

a) 3^x = 3² . 9

3^x = 3² . 3²

3^x = 3⁴

=> x = 4

b) ( 21 + x ) : 9 = 9⁵ : 9⁴

(21 + x ) : 9 = 9

21 + x  = 9 . 9

21 + x = 81

x = 81 - 21

x = 60

c) 5^x + 1 - 13 = 613

5^x = 613 + 13 - 1

5^x = 625

5^x = 5⁴

=> x = 4

a)\(3^x=3^{^{ }}^2.9\)

\(3^x=3^2.3^2\)

\(3^x=3^{2+2}=3^4\)

\(\Rightarrow x=4\)

b)\(\left(21+x_{ }\right):9=9^5:9^4\)

\(\left(21+x\right):9=9^{5-4}=9\)

\(21+x=9.9\)

\(x=81-21=60\)

c)\(5^x-1-13=613\)

\(5^x-\left(1+13\right)=613\)

\(5^x=613+14=625\)

\(5x=5^4\)

\(\Rightarrow x=4\)

1234567

Tìm x thuoc z:

1) \(26-\left|x+9\right|=-13\)

\(\Leftrightarrow\left|x+9\right|=26-\left(-13\right)\)

\(\Leftrightarrow\left|x+9\right|=39\)

\(\Leftrightarrow\left[{}\begin{matrix}x+9=39\\x+9=-39\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=39-9=30\\x=-39-9=-48\end{matrix}\right.\)

Vậy: \(x\in\left\{30;-48\right\}\)

2) \(\left|x+7\right|-13=25\)

\(\Leftrightarrow\left|x+7\right|=25+13=38\)

\(\Leftrightarrow x+7\in\left\{38;-38\right\}\)

\(\Leftrightarrow x\in\left\{31;-45\right\}\)

Vậy:.................

tim x biet

\(1)123-3.\left(x+4\right)=23\)

\(\Leftrightarrow3\left(x+4\right)=123-23\)

\(\Leftrightarrow3\left(x+4\right)=100\)

\(\Leftrightarrow x+4=\frac{100}{3}\)

\(\Leftrightarrow x=\frac{100}{3}-4=\frac{100-12}{3}=\frac{88}{3}\)

Vậy:................

2) Tương tự

_Mấy bác cứ thik đăng nhiều :v , nhìn mak ko muốn lm . E lm bài 1 thôi :v còn các bài còn lại bác tự lm ( nó cx dễ thôi mà ) _

Bài 1 :

\(a) 2x-13=25+6x\)

\(\Rightarrow2x-6x=25+13\)

\(\Rightarrow-4x=38\)

\(\Rightarrow x=-\dfrac{19}{2}\)

Vậy .......

\(b) 12-x=3x+6\)

\(\Rightarrow-x-3x=6-12\)

\(\Rightarrow-4x=-6\)

\(\Rightarrow x=\dfrac{3}{2}\)

Vậy .....

\(c) 40-(25-2x)=x\)

\(\Rightarrow40-25+2x=x\)

\(\Rightarrow15+2x=x\)

\(\Rightarrow2x-x=-15\)

\(\Rightarrow x=-15\)

Vậy ......

\(d) |x-3|=5\)

\(\Rightarrow\left[{}\begin{matrix}x-3=5\\x-3=-5\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=8\\x=-2\end{matrix}\right.\)

Vậy ....

e) \(|x-3|+(x+2)+(x+1)=12\)

\(\Rightarrow\left|x-3\right|+x+2+x+1=12\)

\(\Rightarrow\left|x-3\right|+2x+3=12\)

\(\Rightarrow\left|x-13\right|+2x=9\)

\(\Rightarrow\left[{}\begin{matrix}x-3+2x=9\\-\left(x-3\right)+2x=9\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=4\\x=6\end{matrix}\right.\) \(( x = 6 \) ko thỏa mãn điều kiện )

Vậy ....

khó quá mình bó tay

\(\left(\frac{3}{5}-x\right)+\frac{13}{20}=\frac{5}{6}\)

\(\frac{3}{5}-x=\frac{5}{6}-\frac{13}{20}\)

\(\frac{3}{5}-x=\frac{11}{60}\)

\(x=\frac{3}{5}-\frac{11}{60}\)

\(x=\frac{5}{12}\)

\(\left(x-\frac{1}{2}\right)\cdot\frac{5}{3}=\frac{7}{4}-\frac{1}{2}\)

\(\left(x-\frac{1}{2}\right)\cdot\frac{5}{3}=\frac{5}{4}\)

\(x-\frac{1}{2}=\frac{5}{4}:\frac{5}{3}\)

\(x-\frac{1}{2}=\frac{3}{4}\)

\(x=\frac{3}{4}+\frac{1}{2}\)

\(x=\frac{5}{4}\)

( 3/5 - x ) + 13/20 = 5/6

  3/5 - x                = 5/6 - 13/20

  3/5 - x                = 89/60

          x                = 3/5 - 89/60

          x                = 25/12

( x - 1/2 ) x 5/3 = 7/4 - 1/2

( x - 1/2 ) x 5/3 = 5/4

 x - 1/2             = 5/4 : 5/3

 x - 1/2             = 35/12

 x                     = 35/12 + 1/2

 x                     = 41/12

  (3/5-x)+13/20=5/6

3/5-x              =5/6-13/20

3/5-x              =11/60

      x              =3/5-11/60

      x              =5/12

Vậy x = 5/12

(x-1/2)x5/3=7/4-1/2

(x-1/2)x5/3=5/4

 x-1/2        =5/4:5/3

 x-1/2        =3/4

 x              =3/4+1/2

 x              =5/4

Vậy x=5/4

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