500 + 2345 - 123 + 10 * 10 *20 * 1212 : 20 + 179 - 20 =
1111 x 2345 x 20 : 10 - 567 +1+1+1-3+3+3+4+4+5+5+6+6+7+7+8+8+0+9+90-123+1234567890:10x1:12=
Bài toán dành cho những người IQ có 1
15498118,75
Tính máy tính là ra
10+20+500+50+20+400=?
10+20+500+50+20+400
=(10+20+20+50)+500+400
=100+500+400=1000
123+123-246+10-5+20+15=............................................................................................
123+123-246+10-5+20+15
=246-246+10-5+20+15
=0+10-5+20+15
=10-5+20+15
=5+20+15
=25+15
=40
tick cho mk nha bạn
Tính:
A= 7/4.(3333/1212+3333/2020+3333/3030+3333/4242)
So sánh
A=(2^10+1)/(2^10-1) và B =(20^10-3)
ko hieu tai sao co the dat ra mot cau hoi vo li nhu vay?
deo hieuluon
Bài 1. Tính giá trị của biểu thức sau:
A=\(\frac{7}{4}.\left(\frac{3333}{1212}+\frac{3333}{2020}+\frac{3333}{3030}+\frac{3333}{4242}\right)\)
Bài 2. So sánh
A=\(\frac{20^{10}+1}{20^{10}-1}\)
B=\(\frac{20^{10}-1}{20^{10}-3}\)
Bài 3.Tính nhanh
P=\(\frac{\frac{2}{3}-\frac{1}{4}+\frac{5}{11}}{\frac{5}{12}+1-\frac{7}{11}}\)
Bài 1:
\(A=\frac{3333}{101}\left(\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}\right)=\frac{3333}{101}\left(\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}\right)\)
\(A=\frac{3333}{101}\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}\right)\)
\(A=\frac{3333}{101}\left(\frac{1}{3}-\frac{1}{7}\right)=\frac{3333}{101}.\frac{4}{21}=\frac{1111.4}{101.7}=\frac{4444}{707}\)
Bài 2
\(A=\frac{2^{10}+1}{2^{10}-1}=\frac{2^{10}-1+2}{2^{10}-1}=1+\frac{2}{2^{10}-1}\)
\(B=\frac{2^{10}-1}{2^{10}-3}=\frac{2^{10}-3+4}{2^{10}-3}=1+\frac{4}{2^{10}-3}\)
Ta thấy \(2^{10}-1>2^{10}-3\Rightarrow\frac{2}{2^{10}-1}< \frac{2}{2^{10}-3}< \frac{4}{2^{10}-3}\)
Từ đó \(\Rightarrow1+\frac{2}{2^{10}-1}< 1+\frac{4}{2^{10}-3}\Rightarrow A< B\)
Bài 3\(P=\frac{\left(\frac{2}{3}-\frac{1}{4}\right)+\frac{5}{11}}{\frac{5}{12}+\left(1-\frac{7}{11}\right)}=\frac{\frac{5}{12}+\frac{5}{11}}{\frac{5}{12}+\frac{4}{11}}=\frac{\frac{55+60}{11.12}}{\frac{55+48}{12.11}}=\frac{115}{103}\)
5+10+15+20+...+500
Bài 7 :
a, ( x + 5) - 20 = 123
b, -18 + ( 3 - x ) = 25
c, 4 . ( x - 2 ) + 11 = -13
d, ( x + 10 ) : ( - 20 ) = 6
Lời giải:
a. $(x+5)-20=123$
$x+5=123+20=143$
$x=143-5=138$
b.
$-18+(3-x)=25$
$3-x=25+18=43$
$x=3-43=-404
c. $4(x-2)+11=-13$
$4(x-2)=-13-11$
$4(x-2)=-24$
$x-2=-24:4=-6$
$x=-6+2=-4$
d.
$(x+10):(-20)=6$
$x+10=6(-20)=-120$
$x=-120-10=-130$
a)(x+5)-20=123
(x+5)=123+20
x+5=143
x=143-5
x=138
b)-18 + (3-x)=25
(3-x)=25-(-18)
3-X=43
x=3-43
x=-40
c)4.(x-2):(-20)=6
4.(x-2)=6.(-20)
4.(x-2)=-120
x-2=(-120):4
x-2=-30
x=(-30)+2
x=-28
d)
( x + 10 ) : ( - 20 ) = 6
x+10=6.(-20)
x+10=-120
x=(-120)-10
x=-130
2345*55+2345+2345*20+2345*24
`2345 xx 55 + 2345 + 2345 xx 20 + 2345 xx 24`
`= 2345 xx ( 55 + 1 + 20 + 24 )`
`= 2345 xx 100`
`= 234500`
10 + 500 + 20 + 200 + 100 = ?
\(100+500+20+200+100=920\)
Ủng hộ nhé
10+500+20+200+100
=510+20+200+100
=530+200+100
=730+100
=830