29-(10+29)=x-(27-9)

29-10-29    =x-18

10               =x-18

10+18          =x

28                  =x

(11 / 29 + 2 / 29 + 16 / 29 ) . 9 / 10

1 . 9/10 = 9/10

\(\dfrac{9}{10}\times\left(\dfrac{11}{29}+\dfrac{2}{29}+\dfrac{16}{29}\right)=\dfrac{9}{10}\times\dfrac{29}{29}=\dfrac{9}{10}\times1=\dfrac{9}{10}\)

= 9/10 x ( 11/29 + 2/9 + 16/29 )

= 9/10 x 1

= 9/10

29-(10+29)=x-(27-9)

20-10-9=x-27+9

10-9=x-36

1=x-36

x-36=1

x=1+36

x=37

29-(10+29)=x-(27-9)

-10=x-18

-10+18=x

8=x

=>x=8

mn vô đây xem thằng Phạm Việt Đức chửi tớ nek

Giúp tôi giải toán - Hỏi đáp, thảo luận về toán học - Học toán với OnlineMath

29 - ( 209/10 * x - 80 ) : 2010/29 = 0

( 209/10 * x - 80 ) : 2010/29 = 29 - 0

( 209/10 * x - 80 ) : 2010/29 = 29

( 20,9 * x -80 ) = 29 * 2010/ 29

( 20,9 * x -80 ) = 2010

20,9 * x = 2010 + 80

20,9 * x = 2090

x = 2090 : 20,9

x = 100

HOK TỐT

29 - (\(\frac{209}{10}\)*X - 80 ) : \(\frac{2010}{29}\)=0

giải

(\(\frac{209}{10}\)* X - 80 ) : \(\frac{2010}{29}\)= 29

\(\frac{209}{10}\)* X - 80 )=29 x \(\frac{2010}{29}\)

\(\frac{209}{10}\)* X - 80 = 2010

\(\frac{209}{10}\)* X = 2010 + 80

\(\frac{209}{10}\)* X= 2090

X= 2090 : \(\frac{209}{10}\)

X= 2090 * \(\frac{10}{209}\)

X=100

29 -(209/10*x - 80)* 29/2010=0

29 - (6061/20100*x - 232/201) = 0

29 - 6061/20100*x + 232/201=0

6061/201 - 6061/20100*x = 0

606100 - 6061*x = 0

-6061*x = -606100

x = 100

Sửa đề: \(\dfrac{1}{1.9}\rightarrow\dfrac{9}{9.19}\)

Giải:

\(N=\dfrac{9}{9.19}+\dfrac{9}{19.29}+\dfrac{9}{29.39}+...+\dfrac{9}{2019.2029}\) 

\(N=\dfrac{9}{10}.\left(\dfrac{10}{9.19}+\dfrac{10}{19.29}+\dfrac{10}{29.39}+...+\dfrac{10}{2019.2029}\right)\) 

\(N=\dfrac{9}{10}.\left(\dfrac{1}{9}-\dfrac{1}{19}+\dfrac{1}{19}-\dfrac{1}{29}+\dfrac{1}{29}-\dfrac{1}{39}+...+\dfrac{1}{2019}-\dfrac{1}{2029}\right)\) 

\(N=\dfrac{9}{10}.\left(\dfrac{1}{9}-\dfrac{1}{2029}\right)\) 

\(N=\dfrac{9}{10}.\dfrac{2020}{18261}\) 

\(N=\dfrac{202}{2029}\)

Ta có:\(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)=\(\frac{5.2^{30}.3^{18}-2^2.3^{20}.2^{27}}{5.2^9.2^{19}.3^{19}-7.2^{29}.3^{18}}\)=\(\frac{5.2^{30}.3^{18}-2^2.3^{20}.2^{27}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}\)

=\(\frac{2^{29}.3^{18}.(5.2-9)}{2^{28}.3^{18}.(5.3-7.2)}\)=\(\frac{2^{29}.3^{18}.1}{2^{28}.3^{18}.1}\)=\(\frac{2}{1}\)= 2

đưa máy tính mà tính chứ

bai 1 

cach 1 9(9-3-5)=9.1=9

cach 2 81-27-45=9

bai 2

cách 1 551-337-551+247=-90

c 2 29.6-19.16=-90

a) cách 1 : 

\(81-9\times\left(3+5\right)\)

\(=81-9\times8\)

\(=81-72\)

\(=9\)

cách 2 :

b) \(81-9\times\left(3+5\right)\)

\(=81-\left(9\times3+9\times5\right)\)

\(=81-\left(27+45\right)\)

\(=81-72\)

\(=9\)