giúp tớ với

Câu 1: 

a) \(=\frac{42}{5}:\frac{14}{5}\)

\(=3\)

b)

 \(=15-\frac{7}{3}:\left(\frac{4}{9}-\frac{1}{6}\right)\)

\(=15-\frac{7}{3}:\frac{4}{9}+\frac{7}{3}:\frac{1}{6}\)

\(=15-\frac{21}{4}+14\)

\(=29-\frac{21}{4}=29-5-\frac{1}{4}\)

\(=24-\frac{1}{4}=\frac{95}{4}\)

\(Q=\left(\frac{2}{25}-1,008\right):\frac{4}{7}:\left[\left(3\frac{1}{4}-6\frac{5}{9}\right)\cdot2\frac{2}{7}\right]\)

\(Q=\left(\frac{2}{25}-\frac{126}{125}\right):\frac{4}{7}:\frac{-68}{9}\)

\(Q=\frac{-116}{125}:\frac{4}{7}:\frac{-68}{9}\)

\(Q=\frac{-203}{125}:\frac{-68}{9}\)

\(Q=\frac{1827}{8500}\)

\(\left(3-\frac{1}{4}+\frac{2}{3}\right)-\left(5-\frac{1}{3}-\frac{6}{5}\right)-\left(6-\frac{7}{4}+\frac{3}{2}\right)\)

\(=3-\frac{1}{4}+\frac{2}{3}-5+\frac{1}{3}+\frac{6}{5}-6+\frac{7}{4}-\frac{3}{2}\)

\(=\left(3-5-6\right)+\left(\frac{-1}{4}+\frac{7}{4}-\frac{3}{2}\right)+\left(\frac{2}{3}+\frac{1}{3}\right)+\frac{6}{5}\)

\(=-8+\left(\frac{3}{2}-\frac{3}{2}\right)+1+\frac{6}{5}\)

\(=-7+\frac{6}{5}\)

\(=\frac{-35}{5}+\frac{6}{5}=-\frac{29}{5}\)

(1 - 1/2) x (1 - 1/3) x (1 - 1/4) x (1 - 1/5) x (1 - 1/6)

= 1/2 x 2/3 x 3/4 x 4/5 x 5/6

= 1/6 (tử và mẫu triệt tiêu cho nhau)

A= E387E4837

B = 883433

C = UỲUWFHQWURY48E3947

kb lqmb vs mk ko mk là P.A.D8a1

Làm hết thì đã lên " THÁNH "

a, \(\frac{\left(\frac{1}{9}\right)^6\cdot\left(\frac{3}{8}\right)^7}{\left(\frac{1}{3}\right)^{13}\cdot\left(\frac{1}{2}\right)^{22}.3^6}\)

\(=\frac{\left(\frac{1}{\left(3^2\right)^6}\right)\cdot\left(\frac{1}{2}\cdot\frac{1}{2}\cdot\frac{1}{2}\cdot3\right)^7}{\left(\frac{1}{3}\right)^{13}.\left(\frac{1}{2}\right)^{22}.3^6}=\frac{\frac{1}{3^{12}}\cdot\left(\frac{1}{2}\right)^{21}\cdot3^7}{\frac{1}{3^{13}}\cdot\left(\frac{1}{2}\right)^{22}.3^6}\)

                                                              \(=\frac{3}{\frac{1}{3}\cdot\frac{1}{2}}=3\div\frac{1}{6}=3.6=18\)

b, Làm tương tự nha bn 

A) \(\frac{10}{12}\)+\(2\)- /\(\frac{-2}{3}\)/ -\(\frac{3}{4}\)= \(\frac{10}{12}\)+2-\(\frac{2}{3}\)-\(\frac{3}{4}\)= \(\frac{10}{12}\)+\(\frac{24}{12}\)-\(\frac{8}{12}\)-\(\frac{9}{12}\)=\(\frac{17}{12}\)

tương tự bài B= \(\frac{59}{40}\)

mk hk bk ghi dáu GTTĐ nên mk ghi như thế 

bạn tính kết quả trong dấu GT tuyệt đối rồi bạn mở dấu GTTĐ bằng cách cho số đó trở thành số dương là được

chúc bn may mắn

Cách 1 :   

\(A=\left(6-\frac{2}{3}+\frac{1}{2}\right)-\left(5+\frac{5}{3}-\frac{3}{2}\right)-\left(3-\frac{7}{3}+\frac{5}{2}\right)\)

\(\Rightarrow A=6-\frac{2}{3}+\frac{1}{2}-5-\frac{5}{3}+\frac{3}{2}-3+\frac{7}{3}-\frac{5}{2}\)

\(\Rightarrow A=\left(6-5-3\right)+\left(\frac{7}{3}-\frac{2}{3}-\frac{5}{3}\right)+\left(\frac{1}{2}+\frac{3}{2}-\frac{5}{2}\right)\)

\(\Rightarrow A=-2+0+-\frac{1}{2}\)

\(\Rightarrow A=-2+\frac{-1}{2}\)

\(\Rightarrow A=-\frac{5}{2}\)

Cách 2 : 

\(=\left(\frac{36}{6}-\frac{4}{6}+\frac{3}{6}\right)-\left(\frac{30}{6}+\frac{10}{6}-\frac{9}{6}\right)-\left(\frac{18}{6}-\frac{14}{6}+\frac{15}{6}\right)\)

\(=\frac{35}{6}-\frac{31}{6}-\frac{19}{6}\)

\(=-\frac{15}{6}\)

\(=-\frac{5}{2}\)

~ 

a.

\(-\frac{2}{3}-\frac{1}{3}\times\left(2x-5\right)=\frac{3}{2}\)

\(-\frac{2}{3}-\frac{2}{3}x+\frac{5}{3}=\frac{3}{2}\)

\(\left(-\frac{2}{3}+\frac{5}{3}\right)-\frac{2}{3}x=\frac{3}{2}\)

\(\frac{3}{3}-\frac{2}{3}x=\frac{3}{2}\)

\(1-\frac{2}{3}x=\frac{3}{2}\)

\(\frac{2}{3}x=1-\frac{3}{2}\)

\(\frac{2}{3}x=\frac{2}{2}-\frac{3}{2}\)

\(\frac{2}{3}x=-\frac{1}{2}\)

\(x=-\frac{1}{2}\div\frac{2}{3}\)

\(x=-\frac{1}{2}\times\frac{3}{2}\)

\(x=-\frac{3}{4}\)

b.

\(\frac{1}{3}x+\frac{2}{5}\times\left(x-1\right)=0\)

\(\frac{1}{3}x+\frac{2}{5}x-\frac{2}{5}=0\)

\(x\times\left(\frac{1}{3}+\frac{2}{5}\right)=\frac{2}{5}\)

\(x\times\left(\frac{5}{15}+\frac{6}{15}\right)=\frac{2}{5}\)

\(x\times\frac{11}{15}=\frac{2}{5}\)

\(x=\frac{2}{5}\div\frac{11}{15}\)

\(x=\frac{2}{5}\times\frac{15}{11}\)

\(x=\frac{6}{11}\)

Chúc bạn học tốt

a ) \(-\frac{2}{3}-\frac{1}{3}\left(2x-5\right)=\frac{3}{2}\)

                  \(\frac{1}{3}\left(2x-5\right)=-\frac{2}{3}-\frac{3}{2}\)

                   \(\frac{1}{3}\left(2x-5\right)=\frac{-13}{6}\)

                        \(\left(2x-5\right)=-\frac{13}{6}:\frac{1}{3}\)

                         \(\left(2x-5\right)=-\frac{13}{6}.\frac{3}{1}\)

                         \(\left(2x-5\right)=-\frac{13}{2}\)

                           \(2x=-\frac{13}{2}+5\)

                            \(2x=-\frac{3}{2}\)

                              \(\Rightarrow x=-\frac{3}{2}:2\)

                              \(\Rightarrow x=-\frac{3}{2}.\frac{1}{2}\)

                              \(\Rightarrow x=-\frac{3}{4}\)

1)

a)    \(-\frac{2}{3}-\frac{1}{3}\left(2x-5\right)=\frac{3}{2}\)

  \(\Rightarrow-\frac{2}{3}-\frac{2}{3}x-\frac{5}{3}=\frac{3}{2}\)

  \(\Rightarrow1-\frac{2}{3}x=\frac{3}{2}\)

  \(\Rightarrow\frac{2}{3}x=1-\frac{3}{2}\)

  \(\Rightarrow\frac{2}{3}x=-\frac{1}{2}\)

  \(\Rightarrow x=-\frac{1}{2}:\frac{2}{3}\)

  \(\Rightarrow x=-\frac{3}{4}\)

                                   Vậy \(x=-\frac{3}{4}\)

b) 

\(\frac{1}{3}x+\frac{2}{5}\left(x-1\right)=0\)

\(\Rightarrow\frac{1}{3}x+\frac{2}{5}x-\frac{2}{5}=0\)

\(\Rightarrow x.\left(\frac{1}{3}+\frac{2}{5}\right)=\frac{2}{5}\)

\(\Rightarrow x.\left(\frac{5}{15}+\frac{6}{15}\right)=\frac{2}{5}\)

\(\Rightarrow x.\frac{11}{15}=\frac{2}{5}\)

\(\Rightarrow x=\frac{2}{5}:\frac{11}{15}\)