a) \(\left(2,4-3x\right).0,5=0,9\)

\(2,4-3x=0,9:0,5\)

\(2,4-3x=1,8\)

\(3x=2,4-1,8\)

\(3x=0,6\)

\(x=0,6:3\)

\(x=0,2\)

b) \(\left(8,8x-50\right):0,4=51\)

\(8,8x-50=51.0,4\)

\(8,8x-50=20,4\)

\(8,8x=20,4+50\)

\(8,8x=70,4\)

\(x=70,4:8,8\)

\(x=8\)

c) \(\left(0,472-x\right):2=1,634\)

\(0,472-x=1,634.2\)

\(0,472-x=3,268\)

\(x=0,472-3,268\)

\(x=-2,796\)

d) \(1,6-\left(x-0,2\right)=6,5\)

\(x-0,2=1,6-6,5\)

\(x-0,2=-4,9\)

\(x=-4,9+0,2\)

\(x=-4.7\)

\(a.2,4-3x=1,8\)

\(3x=0,6\)

\(x=0,2\)

\(b.8,8x-50=20,4\)

\(8,8x=70,4\)

\(x=8\)

\(c.0,472-x=3,268\)

\(x=-2,796\)

\(d.x-0,2=-4,9\)

\(x=-4,7\)

a) \(\left(2,4-3x\right).0,5=0,9\)

\(\Rightarrow\left(2,4.3x\right)=0,9:0,5\)

\(\Rightarrow2,4.3x=0,45\)

\(\Rightarrow3x=0,45:2,4\)

\(\Rightarrow3x=\dfrac{3}{16}\)

\(\Rightarrow x=\dfrac{1}{16}\)

b)\(\left(8,8x-50\right):0,4=51\)

\(\Rightarrow\left(8,8x-50\right)=51.0,4\)

\(\Rightarrow8,8x-50=\dfrac{255}{3}\)

\(\Rightarrow8,8x=135\)

\(\Rightarrow x=135:8,8\)

\(\Rightarrow x=\dfrac{675}{44}\)

\(f\left(x\right)-g\left(x\right)=\left(x^5-3x^2+x^3-x^2-2x+5\right)-\left(x^2-3x+1+x^2-x^4+x^5\right)\)

\(f\left(x\right)-g\left(x\right)=x^5-3x^2+x^3-x^2-2x+5-x^2+3x-1-x^2+x^4-x^5\)

\(f\left(x\right)-g\left(x\right)=\left(x^5-x^5\right)+\left(-3x^2-x^2-x^2-x^2\right)+x^3+\left(-2x+3x\right)+\left(5-1\right)+x^4\)

\(f\left(x\right)-g\left(x\right)=-6x^2+x^3+x+4+x^4\)

\(f\left(x\right)-g\left(x\right)=x^4+x^3-6x^2+x+4\)

Đề:.........

<=> (3x - 9) - 2x(x - 3)

<=> 3(x - 3) - 2x(x - 3)

<=> (x - 3)(3 - 2x)

Ta có f(x) = x(2 - 3x) + 3x² - 5x + 9 

= 2x - 3x² + 3x² - 5x + 9

= 9 - 3x

b) f(x) có nghiệm <=> 9 - 3x = 0 

<=> 9 = 3x

<=> x = 3

Vậy x = 3 là nghiệm của f(x) 

675,4 - X x 2,5 = 0,4
            X x 2,5 = 675,4 - 0,4
            X x 2,5 = 675
                     X = 675 : 2,5
                     X = 27
chúc bạn HT

làm j có