Ta có:

67 - [ 8 + 7 . 3² - 24 : 6 + ( 9 - 7 )³ ] : 15 

= 67 - (8 + 7.9 - 4 + 8) : 15

= 67 - 75 : 15

= 67 - 5

= 62

\(67-\left[8+7.3^2-24:6+\left(9-7\right)^3\right]:15\)

\(67-\left[8+7.9-4+2^3\right]:15\)

\(67-\left[8+63-4+8\right]:15\)

\(67-\left[71-11\right]:15\)

\(67-60:15\)

\(67-4\)

\(=63\)

67-\([8+7\times3^2-24:6+\left(9-7\right)^3]:15\)

\(\Leftrightarrow\)67-\([8+63-4+8]\) : 15 

\(\Leftrightarrow\)(67- 75):15

\(\Leftrightarrow\)-8 : 15

\(\Leftrightarrow\frac{-8}{15}\)

Ghi đầy đủ nha

bn có thể ghi rõ ràng đc ko?

a)\(-\dfrac{3}{7}+\dfrac{5}{13}+\dfrac{3}{7}\) 

=\(\left(-\dfrac{3}{7}+\dfrac{3}{7}\right)+\dfrac{5}{13}\) 

=\(0+\dfrac{5}{13}\) 

=\(\dfrac{5}{13}\)

    \(500-\left\{5\left[409-\left(2^3\cdot3-21\right)^2+10^3\right]\right\}:15\)
\(=500-\left\{5\left[409-9+1000\right]\right\}:15\)
\(=500-\left\{5\cdot1400\right\}:15\)
\(=500-7000:15\)
\(=500-\dfrac{1400}{3}\)
\(=\dfrac{100}{3}\)



    \(67-\left[8+7\cdot3^2-24:6+\left(9-7\right)^2\right]:15\)
\(=67-\left[8+7\cdot9-24:6+4\right]:15\)
\(=67-\left[8+63-4+4\right]:15\)
\(=67-71:15\)
\(=67-\dfrac{71}{15}\)
\(=\dfrac{934}{15}\)

\(PeaGea\)

đổi ra thì ta có:

67-[8+7.9-24:6+(9-7)^3]:15

=67-[8+63-4+2^3]:15

=67-[8+63- 4+8]:15

=67-[71-4+8]:15

=67-75:15

=67-5

=62

67 - [ 8 + 7 . 3² - 24 : 6 + ( 9 - 7 )³ ] : 15

= 67 - [ 8 + 7 . 9 - 4 + 2³ ] : 15

= 67 - [ 8 + 63 - 4 + 8 ] : 15

= 67-[71-4+8]:15

= 67 - [ 67 + 8 ] : 15

= 67 - 75 : 15

= 67 - 5

= 62

\(a)\dfrac{8}{5}+\dfrac{7}{6}+\dfrac{5}{9}+2\)

\(\text{=}\dfrac{144}{90}+\dfrac{105}{90}+\dfrac{50}{90}+\dfrac{180}{90}\)

\(\text{=}\dfrac{144+105+50+180}{90}\)

\(\text{=}\dfrac{497}{90}\)

\(b)3-\dfrac{5}{6}-\dfrac{4}{9}+\dfrac{32}{24}\)

\(\text{=}3-\dfrac{5}{6}-\dfrac{4}{9}+\dfrac{4}{3}\)

\(\text{=}\dfrac{54-15-8+24}{48}\text{=}\dfrac{55}{48}\)

bạn chép lại đề đi, dấu [ ở chỗ nào đấy

67-[8+7.3²-24:6+(9-7)³]:15

=67-[8+7.9-4+8]:15

=67-[8+63-4+8]:15

=67-75:15

=67-5

=62

67-[8+7.9-24:6+2^3:15

=67-[8+63-4+8/15

=67-5

=62