4/3*6 + 4/6*9 + 4/9*11 + 4/12*15
Can cach trinh bay nha
Can gap nha
Những câu hỏi liên quan
1-2+3-4+5-6+7-8+9 trinh bay cach lam gium con voi
Thuc hien phep tinh bang cach tinh nhanh :
a) 4/9 + 3/2 + 6/36.
b) 2/7 x 5/17 + 12/7 x 15/17.
c) 2,34 + 5,18 + 7,66.
d) 7/11 : 3/4 + 7/11 : 1/4.
GIUP MINH MINH DANG CAN GAP.
6/5/12:2/3/4+11/1/4 x(1/3-1/5)
Giup minh nha minh can gap ngay bay gio
mk viết đáp án rồi bn tự giải nha
=169/15
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Tinh bang 2 cach: Can gap nha
a) 7/15 x 4/9 + 4/9 x 11/12 = ?
Cach 1:
Cach 2:
Cách \(1:\)\(\frac{7}{15}x\frac{4}{9}+\frac{4}{9}x\frac{11}{12}\)
\(=\frac{28}{135}+\frac{11}{27}\)
\(=\frac{28}{135}+\frac{11}{27}\)
\(=\frac{28}{135}+\frac{55}{135}\)
\(=\frac{83}{135}\)
Cách \(2:\)\(\frac{7}{15}x\frac{4}{9}+\frac{4}{9}x\frac{11}{12}\)
\(=\frac{4}{9}x\left(\frac{7}{15}+\frac{11}{12}\right)\)
\(=\frac{4}{9}x\left(\frac{84}{180}+\frac{165}{180}\right)\)
\(=\frac{4}{9}x\frac{83}{60}\)
\(=\frac{83}{165}\)
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\(\frac{7}{15}x\frac{4}{9}+\frac{4}{9}x\frac{11}{12}\)
C1 = \(\left(\frac{7}{15}+\frac{11}{12}\right)x\frac{4}{9}\)
= \(\frac{83}{60}x\frac{4}{9}\)
= \(\frac{332}{540}\)
C2 \(\frac{7}{15}x\frac{4}{9}+\frac{4}{9}x\frac{11}{12}\)
= \(\frac{28}{135}+\frac{44}{108}\)
= \(\frac{332}{540}\)
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Người ta quét vôi bên tronggồm chung quanhvà trần.M
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1> Tính
a) 3/11 + 5/-9 + 4/11 - 4/9 + 3/17 + 15/11
b) M = -3 * 4 - 6 * 8 - 9 * 12 - 12 * 16 - 16 * 20 / -1 * 2 - 2 * 4 - 3 * 6 - 4 * 8 - 6 * 10
c) N = 5/7 - 5/9 - 5/11 / 15/7 + 15/9 + 15/11
d) 4 + 4/73 * 1/23 / 5 + 5/73 * 1/23
nhanh lên nha mk đang cần gấp
thanks nha
a; \(\dfrac{3}{11}\) + \(\dfrac{5}{-9}\) + \(\dfrac{4}{11}\) - \(\dfrac{4}{9}\) + \(\dfrac{3}{17}\) + \(\dfrac{15}{11}\)
= (\(\dfrac{3}{11}\) + \(\dfrac{4}{11}\) + \(\dfrac{15}{11}\)) - (\(\dfrac{5}{9}\) + \(\dfrac{4}{9}\)) + \(\dfrac{3}{17}\)
= 2 - 1 + \(\dfrac{3}{17}\)
= 1 + \(\dfrac{3}{17}\)
= \(\dfrac{20}{17}\)
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c; N = \(\dfrac{\dfrac{5}{7}-\dfrac{5}{9}-\dfrac{5}{11}}{\dfrac{15}{7}+\dfrac{15}{9}+\dfrac{15}{11}}\)
Phải là - \(\dfrac{5}{7}\) chỗ tử số mới đúng em nhé!
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d; \(\dfrac{4+\dfrac{4}{73}\times\dfrac{1}{23}}{5+\dfrac{5}{73}\times\dfrac{1}{23}}\)
= \(\dfrac{4\times\left(1+\dfrac{1}{73\times23}\right)}{5\times\left(1+\dfrac{1}{73\times23}\right)}\)
= \(\dfrac{4}{5}\)
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tinh nhanh (viet ho minh luon cach lam nha)
a=1-3+5-7+9 -11+...+49-51
b=-1+4-5+8-9+12-...-53+56
c=1+3-5-7+9+11-...-397-399
d=1-2-3+4+5-6-7+...+97-98-99+100
làm hộ tui câu này 2/3+1/3.(-4/9+5/6):5/12 nhơ nêu cach làm ra nha
= 2/3 + 1/3 . 7/18 : 5/12
= 2/3 + 7/54 : 5/12
= 2/3 + 14/45
= 44/45
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bài 1 : tính
1) 5/8 . 7/3 - 5/2 . 1/8 2) 21/10 . 3/4 - 21/10 - 3/4 3) -4 / 11 : -6/11 4) 2/7 . 14/3 -1 5) 4/7 : ( 1/5 . 4/7 ) 6) 12/7 . 7/4 + 35/11 : 245/121
7) ( 4/3 + 8/3 ) . ( 7/4 - 6/4 ) : ( 6/5 + 12/5 + 1/5 ) 8) ( 1/4 - 1/4 + 1/9 / 1/9 ) : ( 2/3 + 7/15 / 2/5 - 1/6 )
9) ( ( 2/193 - 3/389 ) . 193/17 + 33/34 ) : (( 7/1931 - 11 / 3862 ) . 1931 / 25 + 9/2 )
chú ý :
/ là phần nha , nếu có 2 cái (( là sẽ có ngoặc vuông nha ! nhanh nha mình đang gấp lắm
Đọc tiếp
bài 1 : tính
1) 5/8 . 7/3 - 5/2 . 1/8 2) 21/10 . 3/4 - 21/10 - 3/4 3) -4 / 11 : -6/11 4) 2/7 . 14/3 -1 5) 4/7 : ( 1/5 . 4/7 ) 6) 12/7 . 7/4 + 35/11 : 245/121
7) ( 4/3 + 8/3 ) . ( 7/4 - 6/4 ) : ( 6/5 + 12/5 + 1/5 ) 8) ( 1/4 - 1/4 + 1/9 / 1/9 ) : ( 2/3 + 7/15 / 2/5 - 1/6 )
9) ( ( 2/193 - 3/389 ) . 193/17 + 33/34 ) : (( 7/1931 - 11 / 3862 ) . 1931 / 25 + 9/2 )
chú ý :
/ là phần nha , nếu có 2 cái (( là sẽ có ngoặc vuông nha ! nhanh nha mình đang gấp lắm
Bài 1: Tính
\(\text{1)}\) \(\dfrac{5}{8}.\dfrac{7}{30}-\dfrac{5}{2}.\dfrac{1}{8}\)
\(=\dfrac{5}{8}.\dfrac{7}{30}-\dfrac{5}{8}.\dfrac{1}{2}\)
\(=\dfrac{5}{8}.\left(\dfrac{7}{30}-\dfrac{1}{2}\right)\)
\(=\dfrac{5}{8}.\dfrac{-4}{15}\)
\(=\dfrac{-1}{6}\)
\(\text{2)}\) \(\dfrac{21}{10}.\dfrac{3}{4}-\dfrac{21}{10}-\dfrac{3}{4}\)
\(=\dfrac{63}{40}-\dfrac{21}{10}-\dfrac{3}{4}\)
\(=\dfrac{-21}{40}-\dfrac{3}{4}\)
\(=\dfrac{-51}{40}\)
\(\text{3)}\) \(\dfrac{-4}{11}:\dfrac{-6}{11}\)
\(=\dfrac{-4}{11}.\dfrac{11}{-6}\)
\(=\dfrac{4}{6}\)
\(\text{4)}\) \(\dfrac{2}{7}.\dfrac{14}{3}-1\)
\(=\dfrac{4}{3}-1\)
\(=\dfrac{1}{3}\)
\(\text{5)}\) \(\dfrac{4}{7}:\left(\dfrac{1}{5}.\dfrac{4}{7}\right)\)
\(=\dfrac{4}{7}:\dfrac{1}{5}:\dfrac{4}{7}\)
\(=1:\dfrac{1}{5}\)
\(=5\)
\(\text{6)}\) \(\dfrac{12}{7}.\dfrac{7}{4}+\dfrac{35}{11}:\dfrac{245}{121}\)
\(=3+\dfrac{35}{11}.\dfrac{121}{245}\)
\(=3+\dfrac{11}{7}\)
\(=3\dfrac{11}{7}=\dfrac{32}{7}\)
\(\text{7)}\) \(\left(\dfrac{4}{3}+\dfrac{8}{3}\right).\left(\dfrac{7}{4}-\dfrac{6}{4}\right):\left(\dfrac{6}{5}+\dfrac{12}{5}+\dfrac{1}{5}\right)\)
\(=4.\left(\dfrac{7}{4}-\dfrac{6}{4}\right):\left(\dfrac{6}{5}+\dfrac{12}{5}+\dfrac{1}{5}\right)\)
\(=4.\dfrac{1}{4}:\left(\dfrac{6}{5}+\dfrac{12}{5}+\dfrac{1}{5}\right)\)
\(=4.\dfrac{1}{4}:\dfrac{19}{5}\)
\(=1:\dfrac{19}{5}\)
\(=\dfrac{5}{19}\)
\(\text{8)}\) \(\left(\dfrac{1}{4}-\dfrac{1}{4}+\dfrac{\dfrac{1}{9}}{\dfrac{1}{9}}\right):\left(\dfrac{2}{3}+\dfrac{\dfrac{7}{15}}{\dfrac{2}{5}}-\dfrac{1}{6}\right)\)
\(=\left(0+1\right):\left(\dfrac{2}{3}+\dfrac{7}{15}:\dfrac{2}{5}-\dfrac{1}{6}\right)\)
\(=1:\left(\dfrac{2}{3}+\dfrac{7}{6}-\dfrac{1}{6}\right)\)
\(=1:\left(\dfrac{2}{3}+1\right)\)
\(=1:\dfrac{5}{3}\)
\(=\dfrac{3}{5}\)
\(\text{9)}\)
\(\left[\left(\dfrac{2}{193}-\dfrac{3}{389}\right).\dfrac{193}{17}+\dfrac{33}{34}\right]:\left[\left(\dfrac{7}{1931}-\dfrac{11}{3862}\right).\dfrac{1931}{25}+\dfrac{9}{2}\right]\)
\(=\left[\dfrac{199}{75077}.\dfrac{193}{17}+\dfrac{33}{34}\right]:\left[\left(\dfrac{7}{1931}-\dfrac{11}{3862}\right).\dfrac{1931}{25}+\dfrac{9}{2}\right]\)
\(=\left[\dfrac{199}{6613}+\dfrac{33}{34}\right]:\left[\left(\dfrac{7}{1931}-\dfrac{11}{3862}\right).\dfrac{1931}{25}+\dfrac{9}{2}\right]\)
\(=\dfrac{13235}{13226}:\left[\left(\dfrac{7}{1931}-\dfrac{11}{3862}\right).\dfrac{1931}{25}+\dfrac{9}{2}\right]\)
\(=\dfrac{13235}{13226}:\left[\dfrac{3}{3862}.\dfrac{1931}{25}+\dfrac{9}{2}\right]\)
\(=\dfrac{13235}{13226}:\left[\dfrac{3}{50}+\dfrac{9}{2}\right]\)
\(=\dfrac{13235}{13226}:\dfrac{114}{25}\)
\(=\dfrac{330875}{1507764}\)
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1+(-2)+3+(-4)+5+(-6)+7+(-8)+9+(-10)+11+(-12)=
-1+2+(-3)+4+(-5)+6+(-7)+8+(-9)+10+(-11)+12=
(-1)+(-2)+(-3)+(-4)+.......+(-99)+(-100)=
(-1)+2+(-3)+4+.......+(-99)+100=
1+(-2)+3+(-4)+........+99+(-100)=
lam la co tick nha
1+(-2)+3+(-4)+5+(-6)+7+(-8)+9+(-10)+11+(-12)
=(1+3+5+7+9+11)+[(-2)+(-4)+(-6)+(-8)+(-10)+(-12)]
= 36+-42
=-6
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(-1)+2+(-3)+4+(-5)+6+(-7)+8+(-9)+10+(-11)+12
=[(-1)+(-3)+(-5)+(-7)+(-9)+(-11)]+(2+4+6+8+10+12)
=(-36)+42
=6
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