b, \(\left(x^2+2015\right).\left(x-2016\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x^2+2015=0\\x-2016=0\end{cases}}\)\(\Leftrightarrow\orbr{\begin{cases}x^2==-2015\\x=2016\end{cases}}\)( \(x^2=-2015\)loại do \(x^2\ge0\))

Vậy x= 2016

a, \(xy+3x-7y=21\)

\(\Leftrightarrow x.\left(y+3\right)-7y-21=0\)

\(\Leftrightarrow x.\left(y+3\right)-7.\left(y+3\right)=0\)

\(\Leftrightarrow\left(y+3\right).\left(x-7\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}\hept{\begin{cases}y+3=0\\x-7\in Z\end{cases}}\\\hept{\begin{cases}x-7=0\\y+3\in Z\end{cases}}\end{cases}}\Leftrightarrow\orbr{\begin{cases}\hept{\begin{cases}y=-3\\x-7\in Z\end{cases}}\\\hept{\begin{cases}x=7\\y+3\in Z\end{cases}}\end{cases}}\)\(\orbr{\begin{cases}\hept{\begin{cases}y+3=0\\x-7\in Z\end{cases}}\\\hept{\begin{cases}x-7=0\\y+3\in Z\end{cases}}\end{cases}}\Leftrightarrow\orbr{\begin{cases}\hept{\begin{cases}y=-7\\x-7\in Z\end{cases}}\\\hept{\begin{cases}x=7\\y+3\in Z\end{cases}}\end{cases}}\)\(\Leftrightarrow\orbr{\begin{cases}\hept{\begin{cases}y+3=0\\x-7\in Z\end{cases}}\\\hept{\begin{cases}x-7=0\\y+3\in Z\end{cases}}\end{cases}}\Leftrightarrow\orbr{\begin{cases}\hept{\begin{cases}y=-3\\x-7\in Z\end{cases}}\\\hept{\begin{cases}x=7\\y+3\in Z\end{cases}}\end{cases}}\)

a, xy + 3x - 7y = 21

=> x(y + 3) - 7y - 21 = 21 - 21

=> x(y + 3) - (7y + 21) = 0

=> x(y + 3) - 7(y + 3) = 0

=> (x - 7)(y + 3) = 0

=> \(\orbr{\begin{cases}x-7=0\\x+3=0\end{cases}\Rightarrow\orbr{\begin{cases}x=7\\x=-3\end{cases}}}\)

Vậy x = {7;-3}

b, (x² + 2015)(x - 2016) = 0

\(\Rightarrow\orbr{\begin{cases}x^2+2015=0\\x-2016=0\end{cases}\Rightarrow\orbr{\begin{cases}x^2=2015\left(loại\right)\\x=2016\end{cases}}}\)

Vậy x = 2016

a. (9x + 2).3 = 60

<=> 9x + 2 = 20

<=> 9x = 18

<=> x = 2

b. 71 + (26 - 3x):5 = 75

<=> (26 - 3x) : 5 = 4

<=> 26 - 3x = 4/5

<=> 3x = 26 - 4/5 

<=> x = 42/5

c. 2^x = 32

<=> 2^x = 2⁵

<=> x = 5

d. (x - 6)² = 9

<=> x - 6 = 3

<=> x = 9

a) \(\left(9x+2\right)\times3=60\)

\(\Rightarrow9x+2=60:3\)

\(\Rightarrow9x+2=20\)

\(\Rightarrow9x=20-2\)

\(\Rightarrow9x=18\)

\(\Rightarrow x=18:9\)

\(\Rightarrow x=2\)

Vậy x = 2

b) \(71+\left(26-3x\right):5=75\)

\(\Rightarrow\left(26-3x\right):5=75-71\)

\(\Rightarrow\left(26-3x\right):5=4\)

\(\Rightarrow26-3x=4\times5\)

\(\Rightarrow26-3x=20\)

\(\Rightarrow3x=26-20\)

\(\Rightarrow3x=6\)

\(\Rightarrow x=6:3\)

\(\Rightarrow x=2\)

Vậy x = 2

c) \(2^x=32\)

\(\Rightarrow2^x=2^5\)

\(\Rightarrow x=5\)

Vậy x = 5

d) \(\left(x-6\right)^2=9\)

\(\Rightarrow\orbr{\begin{cases}x-6=3\\x-6=-3\end{cases}}\Rightarrow\orbr{\begin{cases}x=9\\x=3\end{cases}}\)

Vậy x = 9 hoặc x = 3

_Chúc bạn học tốt_

a) (9x+2).3=60

       9x+2  = 20

           9x  = 18

             x  = 2

b) 71 + (26-3x) : 5 = 75

   (26 - 3x) : 5         = 4

    26 - 3x                = 20

          3x                  = 26 - 20

            x                 = 6 : 3

            x                  = 2

c) 2^x = 32

   2^x  = 2⁵

     x = 5

d) (x-6)² = 9

   (x-6)²  = 3²

      x - 6 = 3

         x =  9

bao đúng bn nhé

a,  1170 : x - 13 = 339 . 3 . 10 2

1170:(x - 13) = 339 - 3.100

1170:(x - 13) = 39

x - 13 = 1170:39 = 30 

x = 30+13 = 43

b,  3 x - 9 + 15 = 12 + 243 : 3 2

3(x - 9) + 15 = 12+243:9

3(x - 9)+15 = 12+27

3(x - 9)+15 = 39

3(x - 9) = 24

x  - 9 = 8

x = 17

a .   3 x = 9   ⇔ 3 x = 3 2 ⇔ x   =   2

b .   5 x = 5 3 ⇔ x = 3

c . 3 x + 1 = 3 2 ⇔ x + 1 = 2 ⇔ x = 1

a) Ta có: 3 x = 3 2  nên x = 2.

b) Ta có: 5 x = 5 3  nên x = 3.

c) Ta có:  3 x + 1   =   3 2 nên x +1 = 2, do đó x = 1.

TL :

\(12\left(x-81\right):3=4^3+2^3\)

\(12\left(x-81\right):3=64+8\)

\(12\left(x-81\right):3=72\)

\(12\left(x-81\right)=72.3\)

\(12\left(x-81\right)=216\)

\(x-81=216:12\)

\(x-81=18\)

\(\Rightarrow x=109\)

Câu b đang suy nghĩ. ( mik ngu vl )

\(3x-6-x-14=0\)

\(3x-6-1x=0+14\)

\(3x-6-x=14\)

\(\left(3-1\right)x-6=14\)

\(2x=14+6\)

\(2x=20\)

\(\Rightarrow x=10\)

Tks bạn nha

Bài 9: 

a) 15x + 40 = 15 + 20.8

    15x + 40 = 15 + 160

    15x + 40 = 175

             15x = 175 - 40 = 135

                 x = 135 / 15 = 9

b) ( x-1 )( 5-x ) = 0

  => x-1 = 0 hoặc 5-x = 0 

+) x-1 = 0         +) 5-x = 0 ( còn lại tự làm nhé ^^ )

c) x - 140 : 35 = 270

          x - 140 = 270 . 35 = 9450

                 x = 9450 + 140 = 9590

d) ( 14 - 3x ) + ( 6 + x ) = 0

    14 - 3x + 6 + x = 0

    ( 14 + 6 ) - ( 3x -x ) = 0

                  20 - 2x = 0

                         2x = 20

                           x = 10