\(\frac{3x-y}{x-y}=\frac{3}{4}\)

<=> 4(3x-y) = 3(x-y)

<=> 12x - 4y = 3x - 3y

<=> 9x = y

<=> \(\frac{x}{y}=9\)

3x - y/x+y = 3/4

=> 4(3x - y) = 3(x + y)

=> 12x - 4y = 3x + 3y

=> 12x - 3x = 3y + 4y

=> 9x = 7y

=> x/y = 7/9

\(\frac{3x-y}{x+y}=\frac{3}{4}\Rightarrow12x-4y=3x+3y\Leftrightarrow9x-7y=0\Leftrightarrow x=\frac{7y}{9}\)

Khi đó \(\frac{x}{y}=\frac{\frac{7}{9}y}{y}=\frac{7}{9}\)

nha bạn chúc bạn học tốt 

\(\frac{3x-y}{x+y}=\frac{3}{4}\Rightarrow12x-4y=3x+3y\)

\(\Leftrightarrow9x=7y\Leftrightarrow\frac{x}{y}=\frac{7}{9}\)

\(\frac{3x-y}{x+y}=\frac{3}{4}\Rightarrow\left(3x-y\right)4=3\left(x+y\right)\)

=>12x-4y=3x+3y

=>12x-4y=3x+3y

=>12x-3x=3y+4y

=>9x=7y

=>x/y=7/9

vậy x/y=7/9

Ta có: \(\frac{3x-y}{x+y}\)=\(\frac{3}{4}\)

\(\Leftrightarrow\)4(3x-y)=3(x+y)

\(\Leftrightarrow\)12x-4y=3x+3y

\(\Leftrightarrow\)12x-3x=4x+3y

\(\Leftrightarrow\)9x=7y

\(\Leftrightarrow\)\(\frac{x}{y}\)=\(\frac{7}{9}\)

\(\frac{3x-y}{x+y}=\frac{3}{4}\Leftrightarrow\frac{3x-y}{x+y}+1=\frac{3}{4}+1\Leftrightarrow\frac{4x}{x+y}=\frac{7}{4}.\) Ở vế trái chia cả tử và mẫu cho y , được:

\(\frac{4.\frac{x}{y}}{\frac{x}{y}+1}=\frac{7}{4}\)  Suy ra :  \(16.\frac{x}{y}=7\left(\frac{x}{y}+1\right)\) Vậy \(9.\frac{x}{y}=7\Leftrightarrow\frac{x}{y}=\frac{7}{9}\)

Ta có: \(\frac{3x-y}{x+y}=\frac{3}{4}\)

      \(\Rightarrow\frac{3x+3y-4y}{x+y}=\frac{3}{4}\)

      \(\Rightarrow3-\frac{4y}{x+y}=\frac{3}{4}\)

      \(\Rightarrow\frac{4y}{x+y}=3-\frac{3}{4}=\frac{9}{4}\)

       \(\Rightarrow4.4y=9.\left(x+y\right)\)

       \(\Rightarrow16y=9y+9x\)

       \(\Rightarrow9x=16y-9y=7y\)

       \(\Rightarrow\frac{x}{y}=\frac{7}{9}\)

Vậy tỉ số \(\frac{x}{y}=\frac{7}{9}\)

này thì mk chịu