a,(1-1/2).(1-1/3).(1-1/4).........(1-1/n)
b,(1+1/2).(1+1/3).(1+1/4)..........(1+1/n)
c,(1-1/2^2).(1-1/3^2).(1-1/4^2)..........(1-1/n^2)
d,(1+1/1.3).(1+1/2.4).......(1+1/99.101)
Những câu hỏi liên quan
B1:Tính nhanh:
a)M= -1/3 . 141/17 - 39/3 . -1/17
b)N= -9/16 . 13/3 - (-3/4)^2 . 19/3
c)P=(1+1/1.3) (1+1/2.4) (1+1/3.5)......(1+1/99.101)
B2:Tìm x,biết
a)1/2+3/2:x=1/4
b)3/4+1/4.x=7
c)1/2.4 + 1/4.6 +.........+1/(2x-2).2x = 11/48
B3:Tìm x,biết
a)(x-1/2)^2=1/81
b)x+x(1+1/x)+x(1+2/x)=1/3
c)2/x+4=3/x+5
Tính
A=(1-1/2).(1-1/3).(1-1/4).....(1-1/100)
B= (1+1/1.3).(1+1/2.4).(1+1/3.5).....(1+1/99.101)
B1:Tính nhanh:
a)M -1/3 . 141/17 - 39/3 . -1/17
b)N -9/16 . 13/3 - (-3/4)^2 . 19/3
c)P(1+1/1.3) (1+1/2.4) (1+1/3.5)......(1+1/99.101)
B2:Tìm x,biết
a)1/2+3/2:x1/4
b)3/4+1/4.x7
c)1/2.4 + 1/4.6 +.........+1/(2x-2).2x 11/48
B3:Tìm x,biết
a)(x-1/2)^21/81
b)x+x(1+1/x)+x(1+2/x)1/3
c)2/x+43/x+5
Giải gấp hộ mk cái mấy bn ơi
Đọc tiếp
B1:Tính nhanh:
a)M= -1/3 . 141/17 - 39/3 . -1/17
b)N= -9/16 . 13/3 - (-3/4)^2 . 19/3
c)P=(1+1/1.3) (1+1/2.4) (1+1/3.5)......(1+1/99.101)
B2:Tìm x,biết
a)1/2+3/2:x=1/4
b)3/4+1/4.x=7
c)1/2.4 + 1/4.6 +.........+1/(2x-2).2x = 11/48
B3:Tìm x,biết
a)(x-1/2)^2=1/81
b)x+x(1+1/x)+x(1+2/x)=1/3
c)2/x+4=3/x+5
Giải gấp hộ mk cái mấy bn ơi
1. a, M = -\(\dfrac{1}{3}.\dfrac{141}{17}-\dfrac{39}{3}.\left(-\dfrac{1}{17}\right)\)
= -\(\dfrac{1}{17}.\dfrac{141}{3}-\dfrac{39}{3}.\left(-\dfrac{1}{17}\right)\)
= -\(\dfrac{1}{17}\left(\dfrac{141}{3}-\dfrac{39}{3}\right)\)
= -\(\dfrac{1}{17}.34\)
= -2
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1. b, \(\dfrac{3}{4}+\dfrac{1}{4}x=7\)
<=> \(\dfrac{1}{4}x=\dfrac{25}{4}\)
<=> x = 25
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1. b, N = -\(\dfrac{9}{16}.\dfrac{13}{3}-\left(-\dfrac{3}{4}\right)^2.\dfrac{19}{3}\)
= -\(\dfrac{9}{16}.\dfrac{13}{3}+\dfrac{9}{16}.\dfrac{19}{3}\)
= \(\dfrac{9}{16}\left(-\dfrac{13}{3}+\dfrac{19}{3}\right)\)
= \(\dfrac{9}{16}.2\)
= \(\dfrac{9}{8}\)
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Bài 3 : (1+1/1.3)(1+1/2.4)(1+1/3.5)...(1+1/99.101)
bài 4:
(x-3)(x+5)/(x-2)^2 <0
\(\left(1+\frac{1}{1.3}\right)\left(1+\frac{1}{2.4}\right).....\left(1+\frac{1}{99.101}\right)\)
\(=\frac{2.2}{1.3}\frac{3.3}{2.4}.....\frac{100.100}{99.101}\)
\(=\frac{\left(2.3.4.....100\right).\left(2.3.4.....100\right)}{\left(1.2.3.....99\right).\left(3.4.5.....101\right)}\)
\(=\frac{100.2}{101}=\frac{200}{101}\)
\(\frac{\left(x-3\right)\left(x+5\right)}{\left(x-2\right)^2}< 0\)
\(\Rightarrow\frac{\left(x-3\right)\left(x+5\right)}{\left(x-2\right).\left(x-2\right)}< 0\)
=> ( x - 3 ) . ( x - 5 ) và ( x - 2 ) . ( x - 2 ) trái dấu
Mà ( x - 2 )2 = ( x - 2 ) . ( x - 2 ) ≥ 0 ∀ x
\(\Rightarrow\hept{\begin{cases}\left(x−3\right).\left(x+5\right)< 0\\\left(x−2\right).\left(x−2\right)>0\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}x< −5;−5< x< 3\\x>2\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}x< −5\\2< x< 3\end{cases}}\)
Tính
A=13/21.2/11+13/21.9/11+8/21.
B=(1-1/5).(1-2/5).(1-3/5)...(1-9/5)
C= (1-1/2).(1-1/3).(1-1/4)...(1-1/50)
D= 2²/1.3 . 3²/2.4 . 4²/3.5 . 5²/4.6 . 6²/5.7
A = 13/21.2/11 + 13/21.9/11 + 8/21
= (13/21) + (13/21) + (8/21)
= (13 + 13 + 8)/21
= 34/21
B = (1 - 1/5)(1 - 2/5)(1 - 3/5)...(1 - 9/5)
= (4/5)(3/5)(2/5)(1/5)(0/5)(-1/5)(-2/5)(-3/5)(-4/5)
= 0
C = (1 - 1/2)(1 - 1/3)(1 - 1/4)...(1 - 1/50)
= (1/2)(2/3)(3/4)(4/5)...(49/50)
= 1/50
D = (2^2/1.3) * (3^2/2.4) * (4^2/3.5) * (5^2/4.6) * (6^2/5.7)
= (4/3) * (9/8) * (16/15) * (25/23) * (36/35)
= 0.979
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A= 1+2+2^2+...+2^2018
B= 3+3^2+3^3+...+3^2017
C= 1+5^2+5^4+...+5^2018
D= 1.3+2.4+3.5+...+99.101
\(A=1+2+2^2+...+2^{2018}\)
\(2A=2+2^2+...+2^{2019}\)
\(2A-A=\left[2+2^2+...+2^{2019}\right]-\left[1+2+2^2+...+2^{2018}\right]\)
\(A=2^{2019}-1\)
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#)Giải :
\(A=1+2+2^2+2^3+...+2^{2018}\)
\(2A=2+2^2+2^3+2^4+...+2^{2019}\)
\(2A-A=\left(2+2^2+2^3+2^4+...+2^{2019}\right)-\left(1+2+2^2+2^3+...+2^{2018}\right)\)
\(A=2^{2019}-1\)
\(B=3+3^2+3^3+...+3^{2017}\)
\(3B=3^2+3^3+3^4+...+3^{2018}\)
\(3B-B=\left(3^2+3^3+3^4+...+3^{2018}\right)-\left(3+3^2+3^3+...+3^{2017}\right)\)
\(2B=3^{2018}-3\)
\(B=\frac{3^{2018}-3}{2}\)
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\(C=1+5^2+5^4+...+5^{2018}\)
\(5^2C=5^2+5^4+...+5^{2020}\)
\(5^2C-C=\left[5^2+5^4+...+5^{2020}\right]-\left[1+5^2+5^4+...+5^{2018}\right]\)
\(24C=5^{2020}-1\)
\(C=\frac{5^{2020}-1}{24}\)
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Xem thêm câu trả lời
Tính hợp lý:
a)A=1.2.3+2.4.6+3.6.9+5.10.15/ 1.3.5+2.6.14+3.9.21+5.25.35
b)B=(1+1/1.3)+(1+1/2.4+)+....+(1+1/99.101)
c)C=1+(1+2)+(1+2+3)+...+(1+2+3+4+....+99+100)/1.100+ 2.99+ 3.98+....+100.1
Bạn nào làm hết và đúng, nhanh mik sẽ tick nhé =))
thuc hien phep cac phep tinh sau:
a, (1-1/2).(1-1/3).(1-1/4)...(1-1/100)
b, (1+1/1.3).(1+1/2.4).(1+1/3.5)...(1+1/99.101)
Bài 1 : Tính tổng
1+2+3+4+....+n
Bài 2 : Tính A = 1.2+2.3+3.4+....+(n-1).n
Bài 3 Tính A = 1.3+2.4+3.5+.....+(n-1).(n+1)
câu 1
Câu hỏi của Ngọc Hà - Toán lớp 6 - Học toán với OnlineMath
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