\(x-\frac{x}{2}=\frac{32}{15}:\frac{-16}{5}\)
Tính:\(\frac{1}{x}+\frac{1}{x+1}+\frac{2}{1+x^2}+\frac{4}{1+x^4}+\frac{8}{1+x^8}+\frac{16}{1+x^{16}}+\frac{32}{1+x^{32}}\)
Thực hiện phép tính :
\(\frac{2}{1-x^2}+\frac{2}{1+x^2}+\frac{4}{1+x^4}+\frac{8}{1+x^8}+\frac{16}{1+x^{16}}+\frac{32}{1+x^{32}}\)
khó quá làm sao mà trả lời đc
tự đầu mình vắt óc mà suy nghĩ
16, giải phương trình.
1, \(\frac{x+5}{65}+\frac{x+10}{60}=\frac{x+15}{55}+\frac{x+20}{50}\)
2, \(\frac{x+91}{81}+\frac{x+92}{82}+\frac{x+93}{83}=3\)
3, \(\frac{59-x}{19}+\frac{58-x}{18}=\frac{57-x}{17}+\frac{56-x}{16}\)
4, \(\frac{x}{15}+\frac{x+1}{16}+\frac{x+2}{17}+\frac{x+3}{18}+\frac{x+4}{19}=5\)
1Tính
.\(\frac{18,4.0,3.7,5.4,8}{2,5.4,6.9,6.0,9}\)
2.Tĩm x,y,z
\(\frac{x}{13}=\frac{-15}{39}=\frac{20}{y}\)
b.\(\frac{-7}{x}=\frac{14}{16}=\frac{y}{32}\)
c.\(\frac{24}{x}=\frac{y}{32}=\frac{-6}{z}=\frac{3}{2}\)
d.\(\frac{-10}{15}=\frac{x}{-9}=\frac{-8}{y}=\frac{z}{-21}\)
3.Tìm x, biết:
\(\frac{x+1}{6}=\frac{8}{3}\)
Mong các bạn giúp mình!
\(\text{3 Giải}\)
\(\frac{x+1}{6}=\frac{8}{3}=\frac{16}{6}\Rightarrow x+1=16\Rightarrow x=15.\text{Vậy: x=15}\)
16,giải phương trình sau.
1, \(\frac{\frac{x-3}{5}+1}{4}=\frac{\frac{2x}{3}-\frac{1}{2}}{6}\)
2, \(\frac{5x+\frac{x+2}{2}}{9}-x=\frac{\frac{x+3}{5}+15}{12}-2\)
3, 5x+\(\frac{\frac{x+2}{2}}{9}-x=\frac{\frac{x+3}{5}+15}{12}-2\)
\(\Leftrightarrow\frac{\frac{x-3+5}{5}}{4}=\frac{\frac{4x-3}{6}}{6}\Leftrightarrow\frac{x+2}{20}=\frac{4x-3}{36}\Leftrightarrow36x+72=80x-60\Leftrightarrow44x=132\Rightarrow x=2\)
\(\Leftrightarrow\frac{\frac{10x+x+2}{2}}{9}-\frac{\frac{x+3+75}{5}}{12}=x-2\)\(\Leftrightarrow\frac{11x+2}{18}-\frac{x+78}{60}=x-2\)\(\Leftrightarrow\left(\frac{11}{18}-\frac{1}{60}-1\right)x+\left(\frac{2}{18}-\frac{78}{60}+2\right)=0\).Giải típ nha, ko có Casio nên mk ko bấm
\(\Leftrightarrow5x+\frac{x+2}{18}-x-\frac{x+3+75}{60}+2=0\Leftrightarrow\left(5+\frac{1}{18}-1-\frac{1}{60}\right)x+\left(\frac{2}{18}-\frac{78}{60}+2\right)=0\).Giải típ nha
bài 1 : tính phân số:
a) \(\frac{5}{7}+\frac{4}{9}=?;\frac{4}{5}-\frac{2}{3}=?;\frac{9}{11}+\frac{3}{8}=?;\frac{16}{25}-\frac{2}{5}=?\)=?
b)\(5+\frac{3}{5}=?;10-\frac{9}{16}=?;\frac{2}{3}-\left(\frac{1}{6}+\frac{1}{8}\right)=?\)
c)\(\frac{5}{7}+\frac{7}{6}=?;\frac{7}{12}+\frac{17}{18}=?;\frac{9}{8}+\frac{15}{32}=?;4+\frac{35}{45}=?\)
d)\(\frac{11}{4}-\frac{15}{16}=?;\frac{5}{6}-\frac{5}{8}=?;\frac{196}{64}-2=?;3-\frac{13}{9}=?\)
e)\(\frac{8}{5}+\frac{7}{6}+\frac{5}{9}-2=?;3-\frac{5}{6}-\frac{4}{9}+\frac{32}{24}=?\)
a)\(\dfrac{5}{7}+\dfrac{4}{9}=\dfrac{45}{63}+\dfrac{28}{63}=\dfrac{73}{63}\) ; \(\dfrac{9}{11}+\dfrac{3}{8}=\dfrac{72}{88}+\dfrac{33}{88}=\dfrac{105}{88}\)
\(\dfrac{4}{5}-\dfrac{2}{3}=\dfrac{12}{15}-\dfrac{10}{15}=\dfrac{2}{15}\); \(\dfrac{16}{25}-\dfrac{2}{5}=\dfrac{16}{25}-\dfrac{10}{25}=\dfrac{6}{25}\)
Tớ đố các cậu tìm được x của các câu trên (với điều kiện x thuộc Z)
a)\(\frac{15}{41}+\frac{-138}{41}< x< \frac{1}{2}+\frac{1}{3}+\frac{1}{6}\)
b)\(\frac{x}{5}=\frac{15}{2}-\frac{51}{10}\)
c)\(\frac{2x}{3}-\frac{1}{9}=\frac{59}{36}+\frac{1}{4}\)
d)\(\frac{11}{5}x=\frac{32}{15}-x\)
e)\(\frac{x}{2}=\frac{8}{x}\)
f)\(\frac{x-5}{3}=\frac{34}{15}-\frac{-2}{5}\)
Chúc các cậu hoàn thành tốt bài trên.
\(\frac{15}{41}+\frac{-138}{41}< x< \frac{1}{2}+\frac{1}{3}+\frac{1}{6}\)
\(\Leftrightarrow\frac{-123}{41}< x< \frac{1.3+1.2+1}{6}\)
\(\Leftrightarrow-3< x< 1\)
\(\Rightarrow x\in\left\{-2;-1;0\right\}\)
\(\frac{x}{5}=\frac{15}{2}-\frac{51}{10}\)
\(\frac{x}{5}=\frac{15.5-51}{10}\)
\(\frac{x}{5}=\frac{24}{10}\)
\(\frac{x}{5}=\frac{12}{5}\)
\(x=12\)
\(\frac{2x}{3}-\frac{1}{9}=\frac{59}{36}+\frac{1}{4}\)
\(\frac{2x}{3}-\frac{1}{9}=\frac{59+9}{36}\)
\(\frac{2x}{3}-\frac{1}{9}=\frac{68}{36}\)
\(\frac{2x}{3}=\frac{68}{36}+\frac{1}{9}\)
\(\frac{2x}{3}=\frac{68}{36}+\frac{4}{36}\)
\(\frac{2x}{3}=2\)
\(\Rightarrow2x=6\)
\(\Rightarrow x=3\)
a)\(\frac{2,1}{x}=\frac{1,4}{-5}\) b)\(\frac{2}{x-1}=\frac{16}{15}\) c)\(\frac{20}{x}=\frac{x}{5}\)
Bạn nhân chéo lại nhé
A, 2.1.(-5)=1.4.x (bạn tự tính nhé)
B, x-1.16=15.2
C, x.x=20.5
=x mũ 2=100
x=5mũ 2
a) \(\frac{2,1}{x}=\frac{1,4}{-5}\)
\(\Rightarrow2,1.\left(-5\right)=x.1,4\)
\(\Rightarrow-10,5=x.1,4\)
\(\Rightarrow x=\left(-10,5\right):1,4\)
\(\Rightarrow x=-7,5\)
Vậy \(x=-7,5.\)
b) \(\frac{2}{x-1}=\frac{16}{15}\)
\(\Rightarrow2.15=\left(x-1\right).16\)
\(\Rightarrow30=16x-16\)
\(\Rightarrow16x=30+16\)
\(\Rightarrow16x=46\)
\(\Rightarrow x=46:16\)
\(\Rightarrow x=\frac{23}{8}\)
Vậy \(x=\frac{23}{8}.\)
c) \(\frac{20}{x}=\frac{x}{5}\)
\(\Rightarrow20.5=x.x\)
\(\Rightarrow100=x^2\)
\(\Rightarrow x^2=100\)
\(\Rightarrow\left[{}\begin{matrix}x=10\\x=-10\end{matrix}\right.\)
Vậy \(x\in\left\{10;-10\right\}.\)
Chúc bạn học tốt!
Tìm x
a, \(\frac{13x-16}{15}+\frac{x-32}{35}< \frac{x-6}{21}\)
b, \(\frac{5x+12}{14}+\frac{11x+28}{3}>\frac{4x+9}{17}\)
c, \(\left(2x-5\right).\left(x^2+4\right)< 0\)
trình bày cách làm nữa nha . lm dc 1 câu cx lm giúp mk nha
\(a.\)\(\frac{13x-16}{15}+\frac{x-32}{35}< \frac{x-6}{21}\)\(MC:105\)
\(\Leftrightarrow\frac{7\left(13x-16\right)}{105}+\frac{3\left(x-2\right)}{105}< \frac{5\left(x-6\right)}{105}\)
\(\text{Khử mẫu ta dc pt tương đương vs pt:}\)
\(\Leftrightarrow7\left(13x-16\right)+3\left(x-2\right)< 5\left(x-6\right)\)
\(\Leftrightarrow91x-112+3x-6< 5x-30\)
\(\Leftrightarrow94x-118< 5x-30\)
\(\Leftrightarrow94x-5x< 118-30\)
\(\Leftrightarrow89x< 88\)
\(\Leftrightarrow x< \frac{88}{89}\)
.\(b.\)\(\frac{5x+12}{14}+\frac{11x+28}{3}>\frac{4x+9}{17}\)\(MC:714\)
\(\text{Khi khử mẫu pt ta dc pt tương đương}:\):
\(\Leftrightarrow51\left(5x+12\right)+238\left(11x+28\right)>42\left(4x+9\right)\)
\(\Leftrightarrow255x+612+2618x+6664>168x+378\)
\(\Leftrightarrow2873x+7276>168x+378\)
\(\Leftrightarrow2873x-168x>-7276+378\)
\(\Leftrightarrow2705x>-6898\)
\(\Leftrightarrow x>-\frac{6898}{2705}\)