\(A=\left(4^2\right)^{17}.\frac{64^{36}}{8^{35}.32^{34}}\)
Những câu hỏi liên quan
A=4 mũ 2 tất cả mũ 17 nhân 64 mũ 36 trên 8 mũ 35 nhân 32 mũ 34
\(A=\frac{\left(4^2\right)^{17}.64^{36}}{8^{35}.32^{34}}\)
\(A=\frac{\left(2^4\right)^{17}.\left(2^6\right)^{36}}{\left(2^3\right)^{35}.\left(2^5\right)^{34}}\)
\(A=\frac{2^{68}.2^{216}}{2^{105}.2^{170}}=\frac{2^{284}}{2^{275}}=2^9=512\)
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Rút gọn biểu thức sau A = (42)17 x 6436/ 835 x 3234
Tìm các chữ số x,y thỏa mãn \(\overline{94x34y}\) chia hết cho 36
rút gọn biểu thức A : \(\dfrac{\left(4^2\right)^{17}64^{36}}{8^{19}.32^{38}}\)
So sánh A=6411.1613 và B= 3217.819
\(A=64^{11}\cdot16^{13}=2^{66}\cdot2^{52}=2^{118}\)
\(B=32^{17}\cdot8^{19}=2^{85}\cdot2^{57}=2^{142}\)
Do đó: A<B
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BT2: Tính nhanh
7)\(\dfrac{-19}{34}\left(\dfrac{17}{19}+\dfrac{49}{18}\right)+\dfrac{49}{18}\left(\dfrac{19}{34}-\dfrac{18}{7}\right)\)
8)\(\dfrac{29}{32}\left(\dfrac{41}{36}-\dfrac{32}{58}\right)-\dfrac{41}{36}\left(\dfrac{29}{32}+\dfrac{18}{41}\right)\)
7)\(\dfrac{-19}{34}\left(\dfrac{17}{19}+\dfrac{49}{18}\right)+\dfrac{49}{18}\left(\dfrac{19}{34}-\dfrac{18}{7}\right)\)
=\(\dfrac{-19}{34}.\dfrac{17}{19}+\dfrac{49}{18}.\dfrac{-19}{34}+\dfrac{49}{18}.\dfrac{19}{34}-\dfrac{18}{7}.\dfrac{49}{18}\)
=\(\dfrac{1}{2}+\left(\dfrac{49}{18}.\dfrac{-19}{34}+\dfrac{49}{18}.\dfrac{19}{34}\right)-7\)
=\(\dfrac{1}{2}+\left[\dfrac{49}{18}\left(\dfrac{-19}{34}+\dfrac{19}{34}\right)\right]-7\)
=\(\dfrac{1}{2}+0-7=\dfrac{-13}{2}\)
8)\(\dfrac{29}{32}\left(\dfrac{41}{36}-\dfrac{32}{58}\right)-\dfrac{41}{36}\left(\dfrac{29}{32}+\dfrac{18}{41}\right)\)
=\(\dfrac{29}{32}.\dfrac{41}{36}-\dfrac{29}{32}.\dfrac{32}{58}-\dfrac{41}{36}.\dfrac{29}{32}+\dfrac{18}{41}.\dfrac{41}{36}\)
=\(\left(\dfrac{29}{32}.\dfrac{41}{36}-\dfrac{41}{36}\dfrac{29}{32}\right)-\dfrac{29}{32}.\dfrac{32}{58}+\dfrac{18}{41}.\dfrac{41}{36}\)
=\(0-\dfrac{1}{2}+\dfrac{1}{2}=0\)
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Tính
A) \(\frac{15}{34}+\frac{7}{21}+\frac{19}{34}-1\frac{15}{17}+\frac{2}{3}\)
B) \(\left(-2\right)^3\times\left(\frac{3}{4}-0,25\right):\left(2\frac{1}{4}-1\frac{1}{6}\right)\)
Tìm x
A) \(4\frac{1}{3}:\frac{\chi}{4}=6:0,3\)
B) \(\left(2^3:4\right)\times2^{\left(\chi+1\right)}=64\)
Tính:
b) \(\left(-2\right)^3.\left(\frac{3}{4}-0,25\right):\left(2\frac{1}{4}-1\frac{1}{6}\right)\)
\(=\left(-2\right)^3.\left(\frac{3}{4}-\frac{1}{4}\right):\left(\frac{9}{4}-\frac{7}{6}\right)\)
\(=\left(-8\right).\frac{1}{2}:\frac{13}{12}\)
\(=\left(-4\right):\frac{13}{12}\)
\(=-\frac{48}{13}.\)
Tìm x
a) \(4\frac{1}{3}:\frac{x}{4}=6:0,3\)
⇒ \(\frac{13}{3}:\frac{x}{4}=20\)
⇒ \(\frac{x}{4}=\frac{13}{3}:20\)
⇒ \(\frac{x}{4}=\frac{13}{60}\)
⇒ \(x.60=4.13\)
⇒ \(x.60=52\)
⇒ \(x=52:60\)
⇒ \(x=\frac{13}{15}\)
Vậy \(x=\frac{13}{15}.\)
b) \(\left(2^3:4\right).2^{x+1}=64\)
⇒ \(\left(8:4\right).2^{x+1}=64\)
⇒ \(2.2^{x+1}=64\)
⇒ \(2^{x+1}=64:2\)
⇒ \(2^{x+1}=32\)
⇒ \(2^{x+1}=2^5\)
⇒ \(x+1=5\)
⇒ \(x=5-1\)
⇒ \(x=4\)
Vậy \(x=4.\)
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4.Tinha,frac{4^{30}.3^{43}}{2^{53}.27^{15}} b,frac{left(-27right)^{10}.16^{25}}{6^{30}.left(-32right)^{15}}c,left(frac{-2}{17}right)^3.left(frac{-17}{35}right)^3.left(frac{35}{3}right)^3d,frac{3^{31}.25^8-9^{14}.5^{15}}{27^{10}.5^{15}-3^{30}.5^{17}}e,2^{^2}+4^{^2}+6^2+..........+24^2left(1^2+2^2+3^2+....+12^2650right)
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4.Tinh
a,\(\frac{4^{30}.3^{43}}{2^{53}.27^{15}}\)
b,\(\frac{\left(-27\right)^{10}.16^{25}}{6^{30}.\left(-32\right)^{15}}\)
c,\(\left(\frac{-2}{17}\right)^3.\left(\frac{-17}{35}\right)^3.\left(\frac{35}{3}\right)^3\)
d,\(\frac{3^{31}.25^8-9^{14}.5^{15}}{27^{10}.5^{15}-3^{30}.5^{17}}\)
e,\(2^{^2}+4^{^2}+6^2+..........+24^2\left(1^2+2^2+3^2+....+12^2=650\right)\)
Thực hiện các phép tính sau
Afrac{1}{2}-frac{3}{4}+frac{5}{6}-frac{7}{12}|
B-3-frac{2}{3}+frac{3}{5}left(-frac{10}{9}-frac{25}{3}right)-frac{5}{6}
Cleft(frac{12}{35}-frac{6}{7}+frac{18}{14}right):frac{6}{-7}-frac{-2}{5}-1
Dleft[frac{-54}{64}-left(frac{1}{9}:frac{8}{27}right):frac{-1}{3}right]:frac{-81}{128}
Eleft[frac{193}{-17}left(frac{2}{193}-frac{3}{386}right)+frac{11}{34}right]:left[left(frac{7}{1931}+frac{11}{3862}right)frac{1931}{25}+frac{9}{2}right]
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Thực hiện các phép tính sau
\(A=\frac{1}{2}-\frac{3}{4}+\frac{5}{6}-\frac{7}{12}\)|
\(B=-3-\frac{2}{3}+\frac{3}{5}\left(-\frac{10}{9}-\frac{25}{3}\right)-\frac{5}{6}\)
\(C=\left(\frac{12}{35}-\frac{6}{7}+\frac{18}{14}\right):\frac{6}{-7}-\frac{-2}{5}-1\)
\(D=\left[\frac{-54}{64}-\left(\frac{1}{9}:\frac{8}{27}\right):\frac{-1}{3}\right]:\frac{-81}{128}\)
\(E=\left[\frac{193}{-17}\left(\frac{2}{193}-\frac{3}{386}\right)+\frac{11}{34}\right]:\left[\left(\frac{7}{1931}+\frac{11}{3862}\right)\frac{1931}{25}+\frac{9}{2}\right]\)
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A = \(\frac{1}{2}-\frac{3}{4}+\frac{5}{6}-\frac{7}{12}\)
A = \(\left(-\frac{1}{4}\right)+\frac{5}{6}-\frac{7}{12}\)
A = \(\frac{7}{12}-\frac{7}{12}\)
A = \(0\).
Mình làm câu A thôi nhé.
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a, 35. 34+ 35. 36+ 66. 75+ 66. 45
b, 3. 25. 8+ 4. 37. 6+ 2. 38. 12
c, 36. 28+ 36. 82+ 64. 69+ 64. 41
d, 39. 8+ 60. 2+21.8
1)Tính nhanh giá trị biểu thức
A=\(\frac{1}{3}-\frac{3}{4}-\left(\frac{-3}{5}\right)+\frac{1}{64}-\frac{2}{9}-\frac{1}{36}+\frac{1}{15}\)
B=\(\left(\frac{-1}{2}\right)-\left(\frac{-3}{5}\right)+\left(\frac{-1}{9}\right)+\frac{1}{131}-\left(\frac{-2}{7}\right)+\frac{4}{35}-\frac{7}{18}\)
Câu a) bạn tham khảo tại đây nhé: Câu hỏi của Hằng Thanh.
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