Tính tích Q=(3+1) (3^2+1 ) ( 3^4+1)...(3^2^1997+1)
Những câu hỏi liên quan
Tính tích Q= (3+1)(3^2+1)(3^4+1)...(3^2^1997+1)
cac ban jup minh lam voi
Tính nhanh.(1-1/2)*(1-2/3)*(1-3/4)*....(1-1997/1998)*(1-2009/2010)
Tính \(E=\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2000}}{\frac{1999}{1}+\frac{1998}{2}+\frac{1997}{3}+...+\frac{1}{1999}}\)
Gọi 1/4 số a là 0,25 . Ta có :
a . 3 - a . 0,25 = 147,07
a . (3 - 0,25) = 147,07 ( 1 số nhân 1 hiệu )
a . 2,75 = 147,07
a = 147,07 : 2,75
a = 53,48
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tính
(1/2+1/3+1/4+...+1/2000)/(1999/1+1998/2+1997/3+...1/1999)
Tính
A=\(\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+.....+\frac{1}{2000}}{\frac{1999}{1}+\frac{1998}{2}+\frac{1997}{3}+......+\frac{1}{1999}}\)
Ai nhanh và đúng mình tick cho
\(A=\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2000}}{\frac{1999}{1}+\frac{1998}{2}+\frac{1997}{3}+....+\frac{1}{1999}}\)
\(=\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+....+\frac{1}{2000}}{1+\left(\frac{1998}{2}+1\right)+\left(\frac{1997}{3}+1\right)+....+\left(\frac{1}{1999}+1\right)}\)
\(=\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2000}}{\frac{2000}{2}+\frac{2000}{3}+\frac{2000}{4}+....+\frac{2000}{2000}}\)
\(=\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2000}}{2000\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2000}\right)}\)
\(=\frac{1}{2000}\)
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Bài 7 :Tính nhanh:
a) 2/3:5/7x5/7:2/3+1934
b) (30 : \(7\frac{1}{2}\)+0,5 x 3 -1,5 ) x (\(4\frac{1}{2}-\frac{9}{2}\)) : ( 14,5 x 1000 )
c) (1999 x 1998 + 1998 x 1997 ) x ( 1 + 1/2 : 1\(\frac{1}{2}\)-1\(\frac{1}{3}\))
b) \(\frac{1}{1000}+\frac{13}{1000}+\frac{25}{1000}+...+\frac{87}{1000}+\frac{99}{1000}\)
\(=\frac{1+13+25+...+85+97}{1000}=\frac{\left(97+1\right).\left[\left(97-1\right):12+1\right]:2}{1000}\)
\(=\frac{49.9}{1000}=\frac{441}{1000}.\) ( Đề bài sai nhé bạn tử số : 1; 13; 25; 37; 49 ; 61; 73; 85 ; 97. )
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tính hợp lý
A= ( 1999* 1998+ 1998* 1997) * (1+ 1/2 : 3/2- 4/3)
A = ( 1999 x 1998 + 1998 x 1997 ) x ( 1 + 1/2 : 3/2 - 4/3 )
A = ( 1999 x 1998 + 1998 x 1997 ) x ( 1 + 1/3 - 4/3 )
A = ( 1999 x 1998 + 1998 x 1997 ) x [ 1 + ( -1 ) ]
A = ( 1999 x 1998 + 1998 x 1997 ) x 0
A = 0
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tính tổng :
a, 2 + 4 + 6 + .............. + 2016
b, 5 + 9 + 13 + .................. + 1997 + 2001
c,1 . 2 + 2 . 3 + 3 . 4 + ............... + 99 . 100
d,1 . 2 + 2 . 3 + 3 . 4 + ............... + n . ( n + 1 )
a,(2016 + 2).1008:2=1017072
b,(2001+5).500:2=501500
c,
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TÍNH HỢP LÍa)frac{frac{4}{17}-frac{4}{49}-frac{4}{131}}{frac{-3}{17}+frac{3}{49}+frac{3}{131}}b)frac{-1}{2}+frac{3}{5}+frac{-1}{9}+frac{1}{27}+frac{7}{18}+frac{4}{35}+frac{2}{7}c)frac{3.8.15....9999}{4.9.16.....10000}d)frac{frac{1}{2}+frac{1}{3}+frac{1}{4}+...+frac{1}{2000}}{frac{1999}{1}+frac{1998}{2}+frac{1997}{3}+...+frac{1}{1999}}
Đọc tiếp
TÍNH HỢP LÍ
a)\(\frac{\frac{4}{17}-\frac{4}{49}-\frac{4}{131}}{\frac{-3}{17}+\frac{3}{49}+\frac{3}{131}}\)
b)\(\frac{-1}{2}+\frac{3}{5}+\frac{-1}{9}+\frac{1}{27}+\frac{7}{18}+\frac{4}{35}+\frac{2}{7}\)
c)\(\frac{3.8.15....9999}{4.9.16.....10000}\)
d)\(\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2000}}{\frac{1999}{1}+\frac{1998}{2}+\frac{1997}{3}+...+\frac{1}{1999}}\)