Tìm x biết : (4x+3)(4x-3)-(4x-5)^2=46
Những câu hỏi liên quan
Tìm x biết :
a)\((x+3)^2-\left(2x+1\right).\left(2x-1\right)=22\)
b)\(\left(4x+3\right).\left(4x-3\right)-\left(4x-5\right)^2=46\)
a) \(\left(x+3\right)^2-\left(2x+1\right).\left(2x-1\right)=22\)
\(\Leftrightarrow x^2+6x+9-\left(4x^2-1\right)=22\)
\(\Leftrightarrow x^2+6x+9-4x^2+1=22\)
\(\Leftrightarrow-3x^2+6x-12=0\)
\(\Leftrightarrow x^2-2x+4=0\)
\(\Leftrightarrow\left(x^2-2x+1\right)+3=0\)
\(\Leftrightarrow\left(x-1\right)^2+3=0\)(vô lý)
b) \(\left(4x+3\right)\left(4x-3\right)-\left(4x-5\right)^2=46\)
\(\Leftrightarrow16x^2-9-\left(16x^2-40x+25\right)=46\)
\(\Leftrightarrow16x^2-9-16x^2+40x-25-46=0\)
\(\Leftrightarrow40x-80=0\)
\(\Leftrightarrow x=2\)
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Bài 1: Tìm x
(2x-5)2 - 4(2x-5) + 4 =0
Bài 2: Tính nhẩm:
a) 812
b)992
c)28.3.2
bài 3: Tìm x, biết:
(4x+3).(4x-3) - (4x-5)2 = 46
Bài 1:
\(\left(2x-5\right)^2-4\left(2x-5\right)+4=0\)
\(\left(2x-5\right)^2-2\left(2x-5\right)\left(2\right)+2^2=0\)
\(\left(2x-5-2\right)^2=0\)
\(2x-5-2=0\)
\(2x-7=0\)
\(2x=0+7\)
\(2x=7\)
\(x=\frac{7}{2}\)
Bài 3:
\(\left(4x+3\right)\left(4x-3\right)-\left(4x-5\right)^2=46\)
\(\left(4x\right)^2-3^2-16x^2+40x-25=46\)
\(4^2x^2-3^2-16x^2+40x-25=46\)
\(16x^2-9-16x^2+40x-25=46\)
\(-34+40x=46\)
\(40x-34=46\)
\(40x=46+34\)
\(40x=80\)
\(x=2\)
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bài 2:
a) \(81^2=\left(80+1\right)^2=80^2+2.80+1=6400+160+1=6561\)
b) \(99^2=\left(100-1\right)^2=100^2-2.100+1=10000-200+1=8801\)
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Tìm x, biết:
a) (2x + 3)3 - (2x + 1) . (2x - 1) = 22
b) (4x + 3) . (4x - 3) - (4x - 5)2 = 46
c) (3x + 4)2 + (5x - 2)2 - 2x. (17x - 1) = 10
d) (4x -1)2 - (4x + 3)2 - (x - 3) = 4
tìm x
1,(2x+3)^2+(2x+1)(2x-1)=22
2,(4x+3)(4x-3)=46+(4x-5)^2
3,(2x-1)^3-4x^2(2x-3)=5
4,(x+4)^2-(x-1)(x+1)=16
5,(2x-1)^2+(x+3)^2=5(x+7)(x-7)+325
6,(x^2+1)^2-(x^4+x^2+1)(x^2-1)=0
(4x+3)(4x-3) - (4x-5)2 =46
\(\left(4x+3\right)\left(4x-3\right)-\left(4x-5\right)^2=46\)
\(\Leftrightarrow\)\(16x^2-9-\left(16x^2-40x+25\right)=46\)
\(\Leftrightarrow\)\(40x-34=46\)
\(\Leftrightarrow\)\(40x=80\)
\(\Leftrightarrow\)\(x=2\)
Vậy...
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Tìm x biết:
(4x - 3)( 4x + 2) + (4x + 5)(1 - 4x) =2.52
(4x-3).(4x+2) + (4x+5).(1-4x) = 2.52
16x2 + 8x - 12x - 6 + 4x - 16x2 + 5 - 20x = 50
(16x2 - 16x2) + ( 8x-12x+4x-20x) - (6-5) = 50
-20x = 50
x = -5/2
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Tìm x biết a) (x^2-4x+5)_(x^2-2x+1)=3 lớp 7
b)(4x^3-5X^2+3x-1)+(3-5x+5x^2-4x^3)=2
c)(3x-2)-(5x+4)=(x-3)-(X+5)
a, \(-4x+5+2x-1=3\Leftrightarrow-2x=-1\Leftrightarrow x=\dfrac{1}{2}\)
b, \(-2x+2=2\Leftrightarrow x=0\)
c, \(-2x-6=-8\Leftrightarrow x=1\)
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TÌM X biết:
a. (5x - 2)(5x + 2) - (5x + 3)(5x - 4) = 8
b. (4x - 3)( 4x + 2) + (4x + 5)(1 - 4x) =2.52
a) \(\left(5x-2\right)\left(5x+2\right)-\left(5x+3\right)\left(5x-4\right)=0\)
\(\Leftrightarrow5x+8=8\)
\(\Leftrightarrow5x=8-8\)
\(\Leftrightarrow x=5.0\)
\(\Leftrightarrow x=0\)
b)
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\(\left(4x-3\right)\left(4x+2\right)+\left(4x+5\right)\left(1-4x\right)=2.5^2\)
\(16x^2+8x-12x-6+4x-16x^2+5-20x=50\)
\(-20x-1=50\)
\(-20x=51\)
\(x=\frac{-51}{20}\)
Vậy \(x=\frac{-51}{20}\)
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Tìm x biết
(6-3x)^2-2(3x-6)=0(2x+5)^3-(2x+5)=0(6-4x)^3-(6-4x)=0(5-4x)^2-(4x+5)=0