a) \(\frac{11}{10,5}=\frac{6,32}{-x}\)

\(6,32:\frac{11}{10,5}=x\)

\(\frac{1659}{275}=x\)

b) \(\frac{x-1}{x+5}=\frac{6}{7}\)

\(\Rightarrow7x-7=6x+30\)

\(7x-6x=30+7\)

\(x=37\)

c) \(\frac{x^2}{6}=\frac{24}{25}\)

\(x^2=\frac{144}{25}\)

\(x=\frac{12}{5}\)

d) \(x:0,16=9:x\)

\(\frac{x}{0,16}=\frac{9}{x}\)

\(x^2=1,44\)

\(x=1,2\)

\(\frac{11}{10,5}=\frac{6,32}{x}\)

\(\Rightarrow11x=10,5\times6,32\)

\(\Rightarrow11x=66,36\)

\(\Rightarrow x=6,0327\)

\(\frac{11}{10,5}=\frac{6,32}{x}\)\(\Rightarrow\) 11x = 10,5 . 6,32

                              11x = 66,36

                                  x = 6,032(72)

11*6,32=10,5*x=69,52

x=69,52/10,5=6,6

a) Ta có: \(\frac{x}{9}=\frac{-12}{27}\)

=> \(27.x=-12.9\)

=> \(27x=-108\)

=> \(x=108:27\)

=>\(x=4\)

\(\frac{x+2}{10^{10}}+\frac{x+2}{11^{11}}=\frac{x+2}{12^{12}}\frac{x+2}{13^{13}}\)

=> x + 2 = 0

=> x       = 0 - 2

=> x       = -2

chuyển vế rồi phân phối, có 1/10^10+...-1/13^13 khác 0

nên x+2=0

rồi tìm x

Tìm x thuộc Z, biết

( 3x+ 4) :( x-3)

x+1 là ước của 2^2+7

Trình bày ra nhé!!

Đỗ Lê Tú Linh giúp mình đi, mình tick cho!!

\(\left|\frac{5}{11}-0,5\right|-\frac{7}{3}:x=\frac{4}{11}.\frac{3}{8}\)

\(\frac{1}{22}-\frac{7}{3}:x=\frac{3}{22}\)

\(\frac{7}{3}:x=\frac{1}{22}-\frac{3}{22}\)

\(\frac{7}{3}:x=\frac{-1}{11}\)

\(x=\frac{7}{3}:\frac{-1}{11}\)

\(x=\frac{-77}{3}\)

a) \(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)

\(\Leftrightarrow\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}-\frac{x+1}{13}-\frac{x+1}{14}\)

\(\Leftrightarrow\left(x+1\right)\left(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}-\frac{1}{14}\right)=0\)

Vì \(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}-\frac{1}{14}\ne=\)

Nên x + 1 = 0 => x = -1

b) \(\frac{x+1}{14}+\frac{x+2}{13}=\frac{x+3}{12}+\frac{x+4}{11}\)

\(\Leftrightarrow\frac{x+1}{14}+1+\frac{x+2}{13}+1=\frac{x+3}{12}+1+\frac{x+4}{11}+1\)

\(\Leftrightarrow\frac{x+15}{14}+\frac{x+15}{13}=\frac{x+15}{12}+\frac{x+15}{11}\)

\(\Leftrightarrow\frac{x+15}{14}+\frac{x+15}{13}-\frac{x+15}{12}-\frac{x+15}{11}=0\)

\(\Leftrightarrow\left(x+15\right)\left(\frac{1}{14}+\frac{1}{13}-\frac{1}{12}-\frac{1}{11}\right)=0\)

Vì \(\frac{1}{14}+\frac{1}{13}-\frac{1}{12}-\frac{1}{11}\ne0\)

Nên x  +15 = 0 => x = -15

a,\(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)

\(\Rightarrow\left(x+1\right).\left(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}\right)=\left(x+1\right).\left(\frac{1}{13}+\frac{1}{14}\right)\)

\(\Rightarrow\left(x+1\right).\left(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}\right)-\left(x+1\right).\left(\frac{1}{13}+\frac{1}{14}\right)=0\)

\(\Rightarrow\left(x+1\right).\left(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}-\frac{1}{14}\right)=0\)

Vì \(\frac{1}{10}>\frac{1}{13};\frac{1}{11}>\frac{1}{14}\Rightarrow\frac{1}{10}+\frac{1}{11}>\frac{1}{13}+\frac{1}{14}\Rightarrow\frac{1}{10}+\frac{1}{11}+\frac{1}{12}>\frac{1}{13}+\frac{1}{14}\)

\(\Rightarrow\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}-\frac{1}{14}>0\)

\(\Rightarrow x+1=0\Rightarrow x=-1\)

b, Bạn cộng thêm 1 vào \(\frac{x+1}{14};\frac{x+1}{13};\frac{x+1}{12};\frac{x+1}{11}\)Mội bên phân số 1 đơn vị rồi áp dụng như bài 1

\(a)\) \(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)

\(\Leftrightarrow\)\(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}-\frac{x+1}{13}-\frac{x+1}{14}=0\)

\(\Leftrightarrow\)\(\left(x+1\right)\left(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}-\frac{1}{14}\right)=0\)

Vì \(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}-\frac{1}{14}\ne0\)

Nên \(x+1=0\)

\(\Rightarrow\)\(x=-1\)

Vậy \(x=-1\)

Chúc bạn học tốt ~