4-[3^3+3]=x+[13-5^2]

4-[27+3]=x+[13-25]

4-30=x+[-8]

-26=x+[-8]

[-26]+[-8]=x

-34=x

Vậy x=-34

4 - (3³ + 3) = x + (13 - 5²)

4 - 3³ - 3 = x + 13 - 5²

4 - 27 - 3 = x + 13 - 25

-26 = x - 12

-26 + 12 = x

-14 = x

=> x = -14

\(\left(x+\frac{4}{3}\right)\cdot\frac{7}{4}=5-\frac{7}{6}\)

\(\left(x+\frac{4}{3}\right)\cdot\frac{7}{4}=\frac{23}{6}\)

\(x+\frac{4}{3}=\frac{23}{6}:\frac{7}{4}=\frac{46}{21}\)

\(x=\frac{46}{21}-\frac{4}{3}\)

\(x=\frac{6}{7}\)

Vậy ....................................

\(6,\\ a,\\ 1,A=x^2+3x+7=\left(x+\dfrac{3}{2}\right)^2+\dfrac{19}{4}\ge\dfrac{19}{4}\)

Dấu \("="\Leftrightarrow x=-\dfrac{3}{2}\)

\(2,B=\left(x-2\right)\left(x-5\right)\left(x^2-7x+10\right)=\left(x-2\right)^2\left(x-5\right)^2\ge0\)

Dấu \("="\Leftrightarrow\left[{}\begin{matrix}x=2\\x=5\end{matrix}\right.\)

\(b,\\ 1,A=11-10x-x^2=-\left(x+5\right)^2+36\le36\)

Dấu \("="\Leftrightarrow x=-5\)

/2x+3/-2/2-x/=5 

=> x=2,5

/2x-3/-x=/2-x/

=> x=0,5

Bạn Chi Bùi ơi, bạn có thể giải rõ ra giúp mình với được không

Bạn lập bảng xét dấu đi! Rồi từ đó phá dấu GTTĐ.

=>\(\left(\frac{49}{9}+x-\frac{133}{18}\right):\frac{108}{7}=1\)

=>\(\frac{49}{9}+x-\frac{133}{18}=\frac{108}{7}\)

=>\(\frac{49}{9}+x=\frac{108}{7}+\frac{133}{18}\)

=>\(\frac{49}{9}+x=\frac{2875}{126}\)

=>\(x=\frac{2975}{126}-\frac{49}{9}\)

=>\(x=\frac{2189}{126}\)

2189/162

nhớ đưa 100000000000000000000000000000000000000000000000000000000k ok

a) \(\left(\frac{1}{7}x-\frac{2}{3}\right)\left(-\frac{1}{5}x+\frac{3}{5}\right)=0\)

\(\Rightarrow\orbr{\begin{cases}\frac{1}{7}x-\frac{2}{3}=0\\-\frac{1}{5}x+\frac{3}{5}=0\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}\frac{1}{7}x=\frac{2}{3}\\-\frac{1}{5}x=-\frac{3}{5}\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{14}{3}\\x=3\end{cases}}\)

b)\(\frac{1}{10}x-\frac{4}{5}x+1=0\)

\(\Leftrightarrow x.\left(\frac{1}{10}-\frac{4}{5}\right)+1=0\)

\(\Rightarrow-\frac{7}{10}x=-1\)

\(\Rightarrow x=\frac{10}{7}\)

c)\(\left(2x-\frac{1}{3}\right).\left(5x+\frac{2}{7}\right)=0\)

\(\Rightarrow\orbr{\begin{cases}2x-\frac{1}{3}=0\\5x+\frac{2}{7}=0\end{cases}\Rightarrow\orbr{\begin{cases}2x=\frac{1}{3}\\5x=-\frac{2}{7}\end{cases}}}\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{1}{6}\\x=-\frac{2}{35}\end{cases}}\)

a, (1/7 . x - 2/3) . (-1/5 . x + 3/5) = 0

Suy ra : 1/7 .x -2/3 = 0 hoặc -1/5 .x + 3/5 =0

Vậy : 1/7 .x = 2/3 hoặc -1/5 .x = 3/5

         x =2/3 : 1/7 hoặc x = 3/5 : (-1/5)

        x = 14/3 hoặc x = -3

b, 1/10 .x - 4/5 .x + 1 =0

   x . (1/10 - 4/5) + 1 = 0

   x . (-7/10) + 1 = 0

   x . -7/10 =0 +1 = 1

   x = 1 : (-7/10)

   x = -10/7

c, (2x - 1/3 ) . (5x +2/7) = 0

Suy ra : 2x - 1/3 = 0 hoặc 5x + 2/7 = 0

Vậy : 2x = 1/3 hoặc 5x = 2/7

         x = 1/3 : 2 hoặc x = 2/7 : 5

         x = 1/6 hoặc x = 2/35

cái chỗ x = -3 bạn sửa lại là 3 nha , mk nhấn nhầm

giúp mình với, đi mà T.T

Sao đến bài này là ko ai giúp mình vậy T.T

\(\dfrac{5}{4}\times x=\dfrac{3}{8}+\dfrac{5}{12}\)

\(\dfrac{5}{4}\times x=\dfrac{19}{24}\)

\(x=\dfrac{19}{24}:\dfrac{5}{4}\)

\(x=\dfrac{19}{30}\)

Giúp mình với nhé

34+25x=2960⇒25x=2960−34⇒25x=2960−3.1560⇒25x=29−4560⇒25x=−1660=−415⇒x=−415:25⇒x=−415.52⇒x=−23Vậyx=−23

Bài 1:

a) \(x.\dfrac{3}{4}=\dfrac{9}{14}\)

\(\Rightarrow x=\dfrac{9}{14}:\dfrac{3}{4}\)

\(\Rightarrow x=\dfrac{6}{7}\)

b) \(x:\dfrac{5}{9}=\dfrac{3}{10}\)

\(\Rightarrow x=\dfrac{3}{10}.\dfrac{5}{9}\)

\(\Rightarrow x=\dfrac{1}{6}\)

help me

Bài 2:

a) \(\dfrac{3}{10}+\dfrac{2}{5}:\dfrac{4}{15}=\dfrac{3}{10}+\dfrac{3}{2}=\dfrac{9}{5}\)

b) \(\dfrac{4}{7}.3+\dfrac{2}{3}.2=\dfrac{12}{7}+\dfrac{4}{3}=\dfrac{64}{21}\)