Có: \(^{9^{36}}\)=\(^{\left(3^2\right)^{36}}\)=\(3^{72}\)

       \(27^{10}\)=\(\left(3^3\right)^{10}\)=\(3^{30}\)

Vì 3 mũ 72 > 3 mũ 30 suy ra 9 mũ 36 > 27 mũ 10

27 mũ 11 và 81 mũ 8

625 mũ 5 và 125 mũ 7

5 mũ 36 và 11 mũ 24 

5 mũ 23 và 6,5 mũ 22

7.2 mũ 13 và 2 mũ 16

\(\left(\dfrac{1}{81}\right)\) mũ mấy em

Ta có:

\(\left(\dfrac{1}{27}\right)^{10}=\left(\dfrac{1}{3^3}\right)^{10}=\left(\dfrac{1}{3}\right)^{30}\)

\(\left(\dfrac{1}{81}\right)^7=\left(\dfrac{1}{3^5}\right)^7=\left(\dfrac{1}{3}\right)^{35}\)

Vì \(\left(\dfrac{1}{3}\right)^{30}< \left(\dfrac{1}{3}\right)^{35}\)

⇒\(\left(\dfrac{1}{27}\right)^{10}< \left(\dfrac{1}{81}\right)^7\)

\(\left(\dfrac{1}{27}\right)^{10}=\dfrac{1}{27^{10}}=\dfrac{1}{\left(3^3\right)^{10}}=\dfrac{1}{3^{30}}\)

\(\left(\dfrac{1}{81}\right)^7=\dfrac{1}{81^7}=\dfrac{1}{\left(3^4\right)^7}=\dfrac{1}{3^{28}}\)

Do \(3^{30}>3^{28}\Leftrightarrow\dfrac{1}{3^{30}}< \dfrac{1}{3^{28}}\)

\(\Leftrightarrow\left(\dfrac{1}{27}\right)^{10}< \left(\dfrac{1}{81}\right)^7\)

Ta có:

\(\left(\dfrac{1}{27}\right)^{10}=\left(\dfrac{1}{3^3}\right)^{10}=\left(\dfrac{1}{3}\right)^{30}\)

\(\left(\dfrac{1}{81}\right)^7=\left(\dfrac{1}{3^5}\right)^7=\left(\dfrac{1}{3}\right)^{35}\)

Vì \(\left(\dfrac{1}{3}\right)^{35}>\left(\dfrac{1}{3}\right)^{30}\)

⇒\(\left(\dfrac{1}{27}\right)^{10}< \left(\dfrac{1}{81}\right)^7\)

2^(10 : 64 x 16) = 2^[(10 x 16) : 64] = 2^(160 : 64) = 2^25

2^(10 x 8) = 2^80     3^(5 : 27) = 3^(5/27)     5^(2 x 125) = 5^250     6^(6 : 36) = 6^(1/6)

a)243⁷=(3⁵)⁷=3³⁵ ; 9¹⁰.27⁵=3³⁰.3¹⁵=3⁴⁵.

Vì 35 < 45 => 3³⁵<3⁴⁵=>243⁷<9¹⁰.27⁵.

b) 15¹¹=3¹¹.5¹¹;81³.125⁵=3¹².5¹⁵.

Vì 3¹¹<3¹² và 5¹¹<5¹⁵ => 3¹¹.5¹¹<3¹².5¹⁵ => 15¹¹ < 81³.125^5​

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