2^xx4=128

2^x = 128 : 4

2^x = 32

2^x = 2⁵

=> x = 5 

Vậy: x = 5

2^x x 4 = 128

2^x = 128 : 4

2^x = 32

2^x = 2⁵

\(\Rightarrow\)x = 5

2^x.4=128

<=>2^x = 32

<=>x=5

128 – 3(x + 4) = 23
3.(x + 4) = 128 – 23
3.(x + 4) = 105
x + 4 = 105 : 3
x + 4 = 35
x = 35 – 4
x = 31

`128-3(x+4)=23`

`3(x+4)=128-23`

`3(x+4)=105`

`x+4=105:3=35`

`x=35-4=31`

3 x (x + 4) = 128 - 23

3 x (x + 4) = 105

x + 4 = 105 : 3

x+4=35

x=35-4

x=31

128 - 3 ( x + 4 ) = 23

  3( x + 4 ) = 128 - 23 = 105

 x + 4        = 105 : 3 = 35

   x            = 35 - 4 = 31

128-3.(x+4)=23

=> 3.(x+4)=128-23

=> 3.(x+4)=105

=> x+4=105:3

=> x+4=35

=> x=35-4

=> x=31

          128 - 3(x + 4) = 23

\(\Leftrightarrow\)3(x + 4) = 128 - 23 = 105

\(\Leftrightarrow\)x + 4 = 105 : 3 = 35

\(\Leftrightarrow\)x = 35 - 4 = 31

Vậy x = 31

128-3.(x+4)=23

3.(x+4)=128-23

3.(x+4)=105

x+4=105:3

x+4=35

x=35-4

x=31

128-3.(x+4)=23

3.(x+4)=128-23

3.(x+4)=105

x+4=105:3

x+4=35

x=35-4

x=31

OK k mk nha 

128 - 3. ( x + 4 ) = 23

3 . ( x + 4 ) =128 - 23

3 . ( x + 4 ) = 105

x + 4 = 105 : 3

x + 4 = 35

x = 35 - 4

x = 31

128 - 3 . ( x + 4 ) = 23 

3 . ( x + 4 )         = 128 - 23 

3 . ( x + 4 )         = 105

x + 4                  = 105 : 3

x + 4                 = 35

x                       = 35 - 4 

x                       = 31 

kick mk đi mk kick lại

128-3.[x+4] bằng 23

     3.[x+4] bằng 128-23

     3.[x+4] bằng 105

        [x+4] bằng 105:3

         x+4  bằng 35

           x    bằng 35-4

           x    bằng 31

     Vậy x bằng 31

128 - 3 . ( x + 4 ) = 23

=> 3 . (x + 4) = 105

=> x + 4 = 35

=> x = 31