1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+2+2+2+9+10=
Những câu hỏi liên quan
1+1/2+1/3+1/4+....+1/8+1/9+1/10
1/1*10+1/2*9+1/3*8+......+1/8*3+1/2*9+1/10*1
Tính A= 1 - 1/2 +1/3 -1/4 +...+ 1/9 - 1/10
B= (1 + 1/2 + 1/3 +...+1/10) - 2(1/2 + 1/4 +...+ 1/10)
C= 1/6 + 1/7 + 1/8 + 1/9 + 1/10
mik chịu mà bn thức khuya để học bài à ?? bn chăm thế !!
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23 tháng 3 2022 lúc 19:56
1+1+1+1+1+2+3+4+5+6+7+8+9+10 x 1+1+1+1+1+2+3+4+5+6+7+8+9+10 +1+1+1+1+1+2+3+4+5+6+7+8+9+10 - 10 x 9 - 9 + 45 +46 +47 =
Xem thêm câu trả lời
Cho A = 1/1 - 1/2 + 1/3 - 1/4 + ... + 1/9 - 1/10
B = ( 1/1 + 1/2 + 1/3 + ... + 1/10 ) - 2 ( 1/2 + 1/4 + ... + 1/10 )
1/ So sánh A và B
2/ Chứng minh: A = 1/6 + 1/7 + 1/8 +1/9 + 1/10
\(A=1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{9}-\frac{1}{10}\)
\(A=\left(1+\frac{1}{3}+...+\frac{1}{9}\right)-\left(\frac{1}{2}+\frac{1}{4}+...+\frac{1}{10}\right)\)
\(A=\left(1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{9}+\frac{1}{10}\right)-2.\left(\frac{1}{2}+\frac{1}{4}+...+\frac{1}{10}\right)\)
\(A=\left(1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{9}+\frac{1}{10}\right)-\left(1+\frac{1}{2}+...+\frac{1}{5}\right)\)
\(A=\frac{1}{6}+\frac{1}{7}+\frac{1}{8}+...+\frac{1}{10}\)
\(B=\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{10}\right)-2.\left(\frac{1}{2}+\frac{1}{4}+...+\frac{1}{10}\right)\)
\(B=\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{10}\right)-\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{5}\right)\)
Vậy A = B và A = 1/6 + 1/7 + 1/8 + 1/9 + 1/10
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1/ A= \(\left(\frac{1}{1.2}\right)+\left(\frac{1}{3.4}\right)+...+\left(\frac{1}{9.10}\right)\)
B=(1/1+1/2+1/3+...+1/10)- (1/1+1/2+...+1/5)
<=> B=1/6+1/7+1/8+1/9+1/10.
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cho A=1/1-1/2+1/2_1/4+...+1/9-1/10
B=(1/1+1/2+1/3+...+1/10)-2.(1/2+1/4+...+1/10)a, so sánh Avaf B
b, chứng minh: A=1/6+1/7+1/8+1/9+1/10
Số ?2 1 + ... 6 2 + ... 8 ...+ 3 10 8 + ....3 1 + ... 6 ...+ 3 8 4 + .... 10 ...+ 34 ...+ 1 7 1 + ... 9 ...+ 1 10 6 + ...4 2 + ... 7 ...+ 2 9 ...+ 3 10 ...+ 55 ...+ 1 7 4 + .... 9 7 +.... 10 10 + ...5 3 +.... 8 ...+ 1 9 5 + ... 10 0 + .....6 ...+ 1 8 6 + ... 10 ...+ 1 1 1 + ....
Đọc tiếp
Số ?
2 = 1 + ... 6 = 2 + ... 8 = ...+ 3 10 = 8 + ....
3 = 1 + ... 6 =...+ 3 8 = 4 + .... 10 = ...+ 3
4 = ...+ 1 7 = 1 + ... 9 = ...+ 1 10 = 6 + ...
4 = 2 + ... 7 = ...+ 2 9 = ...+ 3 10 = ...+ 5
5 = ...+ 1 7 = 4 + .... 9 = 7 +.... 10 = 10 + ...
5 = 3 +.... 8 = ...+ 1 9 = 5 + ... 10 = 0 + .....
6 = ...+ 1 8 = 6 + ... 10 = ...+ 1 1 = 1 + ....
2 = 1 + 1 6 = 2 + 4 8 = 5 + 3 10 = 8 + 2
3 = 1 + 2 6 = 3 + 3 8 = 4 + 4 10 = 7 + 3
4 = 3 + 1 7 = 1 + 6 9 = 8 + 1 10 = 6 + 4
4 = 2 + 2 7 = 5 + 2 9 = 6+ 3 10 = 5 + 5
5 = 4 + 1 7 = 4 + 3 9 = 7 + 2 10 = 10 + 0
5 = 3 + 2 8 = 7 + 1 9 = 5 + 4 10 = 0 + 10
6 = 5 + 1 8 = 6 + 2 10 = 9 + 1 1 = 1 + 0
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Tiếng việt khó .
Xem thêm câu trả lời
cho A = 1/1-1/2+1/3-1/4 +1/5-1/6+1/7-1/8+1/9-1/10, B = (1/1+1/2+1/3+1/4+...+1/10)-2(1/2+1/4+...+1/10. so sánh A và B
Bài làm:
Ta có: \(A=1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+\frac{1}{5}-\frac{1}{6}+\frac{1}{7}-\frac{1}{8}+\frac{1}{9}-\frac{1}{10}\)
\(A=\left(1+\frac{1}{3}+...+\frac{1}{9}\right)-\left(\frac{1}{2}+\frac{1}{4}+...+\frac{1}{10}\right)\)
\(A=\left[\left(1+\frac{1}{3}+...+\frac{1}{9}\right)+\left(\frac{1}{2}+\frac{1}{4}+...+\frac{1}{10}\right)\right]-\left[\left(\frac{1}{2}+\frac{1}{4}+...+\frac{1}{10}\right)+\left(\frac{1}{2}+\frac{1}{4}+...+\frac{1}{10}\right)\right]\)
\(A=\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{10}\right)-2\left(\frac{1}{2}+\frac{1}{4}+...+\frac{1}{10}\right)=B\)
Vậy A = B
CHO A=17+1/2+2/3+4/5+5/6+4/7+3/8+2/9+1/10 và
B=1/2+1/3+1/4+1/5+1/6+1/7+1/8+1/9+1/10
[9-(1/2+1/3+1/4+...1/10)]:(1/2+2/3+3/4+..+9/10)