A=\(\frac{-41000}{973}\)

giup minh vs

Đặt : \(A=\frac{\left[13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right]\cdot230\frac{1}{25}+46\frac{3}{4}}{\left[1\frac{3}{10}+\frac{10}{3}\right]:\left[12\frac{1}{3}-14\frac{2}{7}\right]}\)

\(A=\frac{\left[\frac{53}{4}-\frac{59}{27}-\frac{65}{6}\right]\cdot\frac{5751}{25}+\frac{187}{4}}{\left[\frac{13}{10}+\frac{10}{3}\right]:\left[\frac{37}{3}-\frac{100}{7}\right]}\)

\(A=\frac{\left[\frac{1431}{108}-\frac{236}{108}-\frac{1170}{108}\right]\cdot\frac{5751}{25}+\frac{187}{4}}{\left[\frac{39}{30}+\frac{100}{30}\right]:\left[\frac{259}{21}-\frac{300}{21}\right]}\)

\(A=\frac{\frac{25}{108}\cdot\frac{5751}{25}+\frac{187}{4}}{\frac{139}{30}:\left[-\frac{41}{21}\right]}\)

\(A=\frac{\frac{5751}{108}+\frac{187}{4}}{\frac{139}{30}\cdot\left[-\frac{21}{41}\right]}\)

\(A=\frac{\frac{5751}{108}+\frac{5049}{108}}{-\frac{973}{410}}=\frac{100}{-\frac{973}{410}}=-\frac{41000}{973}\)

thank you huynh quang sang

\(\frac{\frac{25}{108}.\frac{1151}{5}+\frac{187}{4}}{\frac{139}{30}:\frac{-41}{21}}\)=\(\frac{\frac{5755}{108}+\frac{187}{4}}{\frac{-973}{410}}\)=\(\frac{\frac{8531}{84}}{\frac{-973}{410}}\)=-241,0180

\(\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right)\cdot230\frac{1}{5}+46\frac{3}{4}}{\left(1\frac{3}{10}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)

\(=\frac{\left(\frac{53}{4}-\frac{59}{27}-\frac{65}{6}\right)\cdot\frac{1151}{5}+\frac{187}{4}}{\frac{139}{30}:\left(-\frac{41}{21}\right)}\)

\(=\frac{\frac{25}{108}\cdot\frac{1151}{5}+\frac{187}{4}}{\frac{139}{30}\cdot\left(-\frac{21}{41}\right)}=\frac{\frac{2701}{27}}{-\frac{973}{410}}\)

Tính nốt vì số dữ quá , lần sau để số ít thôi

đoạn \(\frac{8531}{\frac{34}{\frac{-973}{410}}}\)là mình nhầm nha
nó phải là\(\frac{\frac{2701}{27}}{\frac{-973}{410}}\)=-237,405