(x^2-3).(x^2+2x)
giai ho nha
Những câu hỏi liên quan
\(\sqrt{x+2+3\sqrt{2x-5}}+\sqrt{x-2-\sqrt{2x-5}}\)
giai pt tren ho minh nha
\(\sqrt{x+2+3\sqrt{2x-5}}+\sqrt{x-2-2\sqrt{2x-5}}=2\sqrt{2}\)
nhân 2 vế với căn 2 ta có
\(\sqrt{2x+4+6\sqrt{2x-5}}+\sqrt{2x-4-2\sqrt{2x-5}}=4\)
<=>\(\sqrt{\left(\sqrt{2x-5}+3\right)^2}+\sqrt{\left(\sqrt{2x-5}-1\right)^2}=4\)
<=>\(\left|\sqrt{2x-5}+3\right|+\left|\sqrt{2x-5}-1\right|=4\)
đến đây bạn tự giải nốt nhé
Đúng 0
Bình luận (0)
minh viet thieu nha :trên là VP ,VT=\(2\sqrt{2}\)
Đúng 0
Bình luận (0)
Rut gon:
A=(x-2)^2-(2x+1)^2
B=(x-2y)^2-(x-2y) .(2y+x)
C=(x+1)^3-(x-2)^3
D=(x-1)^2-2(x-1)(x+1)+(x+1)^2
E=(x+2y)^2+2(x+2y)(x-2y)+(2y-x)
G=(2x+1)^3-(2x-1)
Giai het ho minh nha! Minh dang can gap
\(A=\left(x-2\right)^2-\left(2x+1\right)^2=x^2-4x+4-4x^2-4x-1=-3x^2+3=-3\left(x^2-1\right)\)
\(=-3\left(x-1\right)\left(x+1\right)\)
\(B=\left(x-2y\right)^2-\left(x-2y\right)\left(x+2y\right)=\left(x-2y\right)\left(x-2y-x-2y\right)=-4y\left(x-2y\right)\)
\(C=\left(x+1\right)^3-\left(x-2\right)^3=\left(x^3+3x^2+3x+1\right)-\left(x^3-6x^2+12x-8\right)\)
\(=x^3+3x^2+3x+1-x^3+6x^2-12x+8=9x^2-9x+9=9\left(x^2-x+1\right)\)
\(D=\left(x-1\right)^2-2\left(x-1\right)\left(x+1\right)+\left(x+1\right)^2=\left(x-1-x-1\right)^2=-2^2=4\)
\(E=\left(x+2y\right)^2+2\left(x+2y\right)\left(x-2y\right)+2y-x=x^2+4xy+4y^2+2\left(x^2-4y^2\right)+2y-x\)
\(=x^2+4xy+4y^2+2x^2-8y^2+2y-x=3x^2-4y^2+4xy+2y-x\)
\(G=\left(2x+1\right)^3-\left(2x-1\right)=8x^3+12x^2+6x+1-2x+1=8x^3+12x^2+4x+2\)
\(=2\left(4x^3+6x^2+2x+1\right)=2\left(4x\left(x+1\right)^2+1\right)\)
Đúng 0
Bình luận (0)
\(2x-\frac{4-3x}{\frac{5}{15}}=7x-\frac{x-3}{\frac{2}{5}}-x+1\)
\(\frac{5x-1}{10}+\frac{2x+3}{6}=\frac{x-8}{15}-\frac{x}{30}\)
giai ho minh 2 bai nay nha
nhanh mik tk
\(\frac{5x-1}{10}+\frac{2x+3}{6}=\frac{x-8}{15}-\frac{x}{30}\)
\(\Rightarrow\frac{3\left(5x-1\right)}{30}+\frac{5\left(2x+3\right)}{30}=\frac{2\left(x-8\right)}{30}-\frac{x}{30}\)
\(\Rightarrow15x-3+10x+15=2x-16-x\)
\(\Rightarrow24x=-28\)
\(\Rightarrow x=-\frac{7}{6}\)
Đúng 0
Bình luận (0)
Giai PT nay ho mik vs
x+5/x - 2x-3/x^2-x = -2/x-1
Rut gon:
A=(x-2)^2-(2x+1)^2
B=(x-2y)^2-(x-2y) .(2y+x)
C=(x+1)^3-(x-2)^3
D=(x-1)^2-2(x-1)(x+1)+(x+1)^2
E=(x+2y)^2+2(x+2y)(x-2y)+(2y-x)
G=(2x+1)^3-(2x-1)
Giai het ho minh nha! Cừ từ từ mik rảnh lắm!!!!!
A = ( x - 2 )2 - ( 2x + 1 )2
A = x2 - 4x + 4 - 4x2 + 4x + 1
A = - 3x2 + 5
B = ( x - 2y )2 - ( x - 2y ) . ( 2y + x )
B = x2 - 4xy + 4y2 - ( 2xy + x2 - 4y2 - 2xy )
B = x2 - 4xy + 4y2 - 2xy - x2 + 4y2 + 2xy
B = 8y2 - 4xy
Đúng 0
Bình luận (0)
cos giai ho mink bai nau ko |x-5=|-3x+2|
b,|x-5|+|X^2-25|=0
c, |2x-3|+|2x+4|=7
giai ho minh nha
Tim x , y , z
|x-2/5|+|2y+3|+(z-2)2=0
Vì \(\left|x-\frac{2}{5}\right|\ge0;\left|2y+3\right|\ge0;\left(z-2\right)^2\ge0\)
=> \(\left|x-\frac{2}{5}\right|+\left|2y+3\right|+\left(z-2\right)^2\ge0\)
Mà theo đề bài: \(\left|x-\frac{2}{5}\right|+\left|2y+3\right|+\left(z-2\right)^2=0\)
=> \(\begin{cases}\left|x-\frac{2}{5}\right|=0\\\left|2y+3\right|=0\\\left(z-2\right)^2=0\end{cases}\)=> \(\begin{cases}x-\frac{2}{5}=0\\2y+3=0\\z-2=0\end{cases}\)=> \(\begin{cases}x=\frac{2}{5}\\2y=-3\\z=2\end{cases}\)=> \(\begin{cases}x=\frac{2}{5}\\y=-\frac{3}{2}\\z=2\end{cases}\)
Vậy \(x=\frac{2}{5};y=-\frac{3}{2};z=2\)
Đúng 0
Bình luận (0)
Ta có :
\(\left|x-\frac{2}{5}\right|+\left|2y+3\right|+\left(z-2\right)^2=0\)
Vì \(\begin{cases}\left|x-\frac{2}{5}\right|\ge0\\\left|2y+3\right|\ge0\\\left(z-2\right)^2\ge0\end{cases}\)\(\Rightarrow\begin{cases}x-\frac{2}{5}=0\\2y+3=0\\z-2=0\end{cases}\)\(\Rightarrow\begin{cases}x=\frac{2}{5}\\2y=-\frac{3}{2}\\z=2\end{cases}\)
Vậy .................
Đúng 0
Bình luận (0)
-2/3-1/3(2X-5)=3/2
Ban nao giai ho mink nha
1. a/x(x-3)-x^2=6
b/(x-2)^2 +x(3-x)=5
c/(x-2)(x+1)=x^2=6
d/(x-2)(x+2)-x(x+4)=5
e/(x-3)(x^2+3x+9)-x^3+x=7
f/x^2+3x+2=0
h/(x-1)(x-5)+(3-x)(1+2)=7
l/(x+2)^2-(x-1)^2=0
k/(x+3)(x-3)-(x-1)^2=6
Giup minh nha !! Hoi dai nhung giai dc phan nao thi giai !!
Dung viet ket qua luon nha !! Giai ra ho mk !!