Mọi người giải bài này giúp mik với:
B=\(\frac{2,5-4.\left(\frac{5}{2}-1,2\right)+\frac{3}{8}}{4.\left(\frac{5}{2}-1,2\right)-\frac{3}{5}:\frac{2}{5}}-\frac{55}{148}\)
\(B=\frac{2,5-4\left(\frac{5}{2}-1,2\right)+\frac{3}{8}}{4\left(\frac{5}{2}-1,2\right)-\frac{3}{5}:\frac{2}{5}}-\frac{55}{148}\)
\(B=\frac{2,5-4.\left(\frac{5}{2}-1,2\right)+\frac{3}{8}}{4.\left(\frac{5}{2}-1,2\right)-\frac{3}{5}:\frac{2}{5}}-\frac{55}{148}\)
\(B=\frac{\frac{5}{2}-4.\left(\frac{25}{10}-\frac{12}{10}\right)+\frac{3}{8}}{4.\left(\frac{25}{10}-\frac{12}{10}\right)-\frac{3}{5}.\frac{5}{2}}-\frac{55}{148}\)
\(B=\frac{\frac{5}{2}-4.\frac{13}{10}+\frac{3}{8}}{4.\frac{13}{10}-\frac{3}{2}}-\frac{55}{148}\)
\(B=\frac{\frac{5}{2}-\frac{26}{5}+\frac{3}{8}}{\frac{26}{5}-\frac{3}{2}}-\frac{55}{148}\)
\(B=\frac{\frac{100}{40}-\frac{208}{40}+\frac{15}{40}}{\frac{52}{10}-\frac{15}{10}}-\frac{55}{148}\)
\(B=\frac{-\frac{93}{40}}{\frac{37}{10}}-\frac{55}{148}\)
\(B=\frac{93}{148}-\frac{55}{148}\)
\(B=\frac{19}{74}\)
Tính
\(A=\frac{2,5-4\left(\frac{5}{2}-1,2\right)+\frac{3}{8}}{4\times\left(\frac{5}{2}-1,2\right)-\frac{3}{5}:\frac{2}{5}}-\frac{55}{148}\)
\(A=\frac{2,5-4.\left(\frac{5}{2}-1,2\right)+\frac{3}{8}}{4.\left(\frac{5}{2}-1,2\right)-\frac{3}{5}:\frac{2}{5}}-\frac{55}{148}\)
\(A=\frac{\frac{5}{2}-4.\left(\frac{25}{10}-\frac{12}{10}\right)+\frac{3}{8}}{4.\left(\frac{25}{10}-\frac{12}{10}\right)-\frac{3}{5}.\frac{5}{2}}-\frac{55}{148}\)
\(A=\frac{\frac{5}{2}-4.\frac{13}{10}+\frac{3}{8}}{4.\frac{13}{10}-\frac{3}{2}}-\frac{55}{148}\)
\(A=\frac{\frac{5}{2}-\frac{26}{5}+\frac{3}{8}}{\frac{26}{5}-\frac{3}{2}}-\frac{55}{148}\)
\(A=\frac{\frac{100}{40}-\frac{208}{40}+\frac{15}{40}}{\frac{52}{10}-\frac{15}{10}}-\frac{55}{148}\)
\(A=\frac{-\frac{93}{40}}{\frac{37}{10}}-\frac{55}{148}\)
\(A=\frac{93}{148}-\frac{55}{148}\)
\(A=\frac{19}{74}\)
Tính : \(A=\frac{2,5-4\left(\frac{5}{2}-1,2\right)+\frac{3}{8}}{4\left(\frac{5}{2}-1,2\right)-\frac{3}{5}:\frac{2}{5}}-\frac{55}{148}\)
Rút gọn \(B=\frac{3^9-2^3.3^7+2^{10}.3^2-2^{13}}{3^{10}-2^2.3^7+2^{10}.3^3-2^{12}}\)
( Bài hơi dài , mong mọi người giúp ạ ! )
\(\text{Tính P :}\)
\(P=\frac{0,8:\left(\frac{4}{5}\times1,25\right)}{0,64-\frac{1}{25}}+\frac{\left(1,08-\frac{2}{25}\right):\frac{4}{7}}{\left(6\frac{5}{9}-3\frac{1}{4}\right)\times2\frac{2}{17}}+\left(1,2\times0,5\right):\frac{4}{5}\)
Tìm x, biết:
b)3/x+4/-/2x+1/-5/x+3/+/x-9/=5
c)\(\left|\frac{11}{5}-x\right|+\left|x-\frac{1}{5}\right|+\frac{41}{5}=1,2\)
d)\(2\left|x+\frac{7}{2}\right|+\left|x\right|-\frac{7}{2}=\left|\frac{11}{5}-x\right|\)
CÁC BẠN GIÚP GIÚP MIK GIẢI BÀI NÀY VỚI, MI ĐANG GẤP LẮM!!!
MIK SẼ TICK CHO...PLEASE!!!
Giúp mình làm bài này trước 8h
Bài 1 : Thực hiện phép tính(nếu có thể )
a)\(\left(31\frac{6}{13}+5\frac{9}{41}\right)-36\frac{6}{13}\)
b) \(\frac{5}{3}+\left(\frac{-2}{7}\right)-\left(-1,2\right)-\left|1,4-0,2\right|\)
c) \(0,25+\frac{3}{5}-\left(\frac{1}{8}-\frac{2}{5}+1\frac{1}{4}\right)+\left|-\frac{3}{5}\right|\)
Bài 2 : Tìm x, biết
a) \(-\frac{3}{5}-x=0,75\)
b)\(x+\frac{1}{3}=\frac{2}{5}-\left(-\frac{1}{3}\right)\)
c)\(\left|2x-4\right|+1=5\)
1.a) \(\left(31\frac{6}{13}+5\frac{9}{41}\right)-36\frac{6}{13}=\left(31+\frac{6}{13}+5+\frac{9}{41}\right)-\left(36+\frac{6}{13}\right)\)
\(=\left(36+\frac{6}{13}-\frac{9}{41}\right)-\left(36+\frac{6}{13}\right)=\left(36+\frac{6}{13}\right)-\left(36+\frac{6}{13}\right)-\frac{9}{41}=-\frac{9}{41}\)
b) \(\frac{5}{3}+\left(-\frac{2}{7}\right)-\left(-1,2\right)-\left|1.4-0,2\right|\)
\(=\frac{5}{3}-\frac{2}{7}+1,2-1,2=\frac{29}{21}\)
c) \(0,25+\frac{3}{5}-\left(\frac{1}{8}-\frac{2}{5}+1\frac{1}{4}\right)+\left|\frac{3}{5}\right|\)
\(=\frac{1}{4}+\frac{3}{5}-\frac{1}{8}+\frac{2}{5}-1-\frac{1}{4}+\frac{3}{5}\)
\(=\left(\frac{1}{4}-\frac{1}{4}\right)+\left(\frac{3}{5}+\frac{2}{5}-1\right)+\frac{3}{5}-\frac{1}{8}=\frac{19}{40}\)
2) \(-\frac{3}{5}-x=0,75\)
=> \(-\frac{3}{5}-x=\frac{3}{4}\)
=> \(x=-\frac{3}{5}-\frac{3}{4}=\frac{-27}{20}\)
b) \(x+\frac{1}{3}=\frac{2}{5}-\left(-\frac{1}{3}\right)\)
=> \(x+\frac{1}{3}=\frac{2}{5}+\frac{1}{3}\)
=> \(x=\frac{2}{5}\)
c) |2x - 4| + 1 = 5
=> |2x - 4| = 4
<=> \(\orbr{\begin{cases}2x-4=4\\2x-4=-4\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=4\\x=0\end{cases}}\)
Giúp mình với nha cả nhả :<
Cả nhà làm vài ý thui cx được ạ :<
bài 1 mọi người làm ơn giúp mình
a,\(\left(\frac{-2}{5}+\frac{1}{3}\right).\frac{30}{7}-\left(\frac{-1}{2}\right)^2\)
b,\(\left(\frac{-1}{2}-\frac{2}{3}\right)^2.\frac{72}{5}+\left(\frac{-4}{5}\right)^2.\frac{25}{16}\)
c,\(\left(1\frac{2}{3}+50\%\right):\frac{3}{12}-\left(\frac{-3}{7}\right)^2:\frac{-3}{7}\)
d,\(\left|\frac{-1}{2}\right|.\frac{4}{3}-1,2:\left(\frac{-6}{5}\right)^2\)
Tìm x, biết:
b)3/x+4/-/2x+1/-5/x+3/+/x-9/=5
c)\(\left|\frac{11}{5}-x\right|+\left|x-\frac{1}{5}\right|+\frac{41}{5}=1,2\)
d)\(2\left|x+\frac{7}{2}\right|+\left|x\right|-\frac{7}{2}=\left|\frac{11}{5}-x\right|\)
CÁC BẠN GIÚP MIK VỚI!!!
\(\frac{0,8:\left(\frac{4}{5}\cdot1,25\right)}{0,64-\frac{1}{25}}+\left(1,2\cdot0,5\right):\frac{3}{5}\)
giúp mik giải mới cách làm luôn nha
\(\frac{0,8\div\left(\frac{4}{5}\cdot1,25\right)}{0,64-\frac{1}{25}}+\left(1,2\cdot0,5\right)\div\frac{3}{5}\)
\(=\frac{0,8\div\left(0,8\cdot1,25\right)}{0,64-0,04}+\left(1,2\cdot0,5\right)\div0,6\)
\(=\frac{0,8\div1}{0,6}+0,6\div0,6\)
\(=\frac{0,8}{0,6}+1\)
\(=\frac{4}{3}+1=\frac{7}{3}\)
\(\frac{0,8\div\left(\frac{4}{5}\cdot1,25\right)}{0,64-\frac{1}{25}}+\left(1,2\cdot0,5\right)\div\frac{3}{5}\)
\(=\frac{0,8\div\left(0,8.1,25\right)}{0,64-0,04}+\left(1,2.0,5\right)\div0,6\)
\(=\frac{0,8\div1}{0,6}+0,6\div0,6\)
\(=\frac{4}{3}+1\)
\(=\frac{7}{3}\)