\(a,\left(\frac{3}{7}+\frac{1}{2}\right)^2\)
\(b,\left(\frac{3}{4}-\frac{5}{6}\right)^2\)
\(c,\frac{5^4.20^4}{25^5.4^5}\)
Tính:
a) \(\left(\frac{3}{7}+\frac{1}{2}\right)^2\)
b) \(\left(\frac{3}{4}-\frac{5}{6}\right)^2\)
c) \(\frac{5^4.20^4}{25^5.4^5}\)
d) \(\left(\frac{-10}{3}\right)^5.\left(\frac{-6}{5}\right)^4\)
e) \(\left(1+\frac{2}{3}-\frac{1}{4}\right).\left(\frac{4}{5}-\frac{3}{4}\right)^2\)
f) \(2:\left(\frac{1}{2}-\frac{2}{3}\right)^3\)
a) \(\left(\frac{3}{7}+\frac{1}{2}\right)^2=\left(\frac{6}{14}+\frac{7}{14}\right)^2=\left(\frac{13}{14}\right)^2=\frac{169}{196}\)
b) \(\left(\frac{3}{4}-\frac{5}{6}\right)^2=\left(\frac{9}{12}-\frac{10}{12}\right)^2=\left(-\frac{1}{2}\right)^2=\frac{1}{4}\)
d) \(\left(-\frac{10}{3}\right)^5.\left(-\frac{6}{5}\right)^4=-\frac{2560}{3}\)
e) \(\left(1+\frac{2}{3}-\frac{1}{4}\right).\left(\frac{4}{5}-\frac{3}{4}\right)^2=\frac{17}{12}.\left(\frac{1}{20}\right)^2=\frac{17}{12}.\frac{1}{400}=\frac{17}{4800}\)
f) \(2:\left(\frac{1}{2}-\frac{2}{3}\right)^3=2:\left(-\frac{1}{6}\right)^3=2:-\frac{1}{216}=-432\)
so sánh :
C=\(\frac{5^4.20^4}{25^5.4^5}\) và D=\(\left(\frac{-10}{3}\right)^5.\left(\frac{-6}{5}\right)^4\)
E=\(\left(1+\frac{2}{3}-\frac{1}{4}\right).\left(\frac{4}{5}-\frac{3}{4}\right)^2\)và F=\(2:\left(\frac{1}{2}-\frac{2}{3}\right)^3\)
I=\(\frac{2}{3}+\frac{1}{3}:\left(\frac{-8}{25}\right)\)và H=\(\frac{5}{11}.\frac{4}{11}+\frac{7}{11}.\frac{5}{11}-\frac{2}{3}\)
Tính:
a) \(\left(\frac{3}{7}+\frac{1}{2}\right)^2\)
b) \(\left(\frac{3}{4}-\frac{5}{6}\right)^2\)
c) \(\frac{5^4.20^4}{25^5.4^5}\)
d) \(\left(\frac{-10}{3}\right)^5.\left(\frac{-6}{5}\right)^4\)
a, \(\frac{169}{196}\)
b, \(\frac{1}{144}\)
c, \(\frac{1}{100}\)
d, \(\frac{-2560}{3}\)
a) \(\left(\frac{3}{7}+\frac{1}{2}\right)^2\)
b) \(\left(\frac{3}{4}-\frac{5}{6}\right)^2\)
c) \(\frac{5^4.20^4}{25^5.4^5}\)
d) \(\left(\frac{-10}{3}\right)^5.\left(\frac{-6}{5}\right)^4\)
\(\left(\frac{3}{7}+\frac{1}{2}\right)^2=\left(\frac{13}{14}\right)^2=\frac{169}{196}\)
\(\left(\frac{3}{4}-\frac{5}{6}\right)^2=\left(-\frac{1}{12}\right)^2=\frac{1}{144}\)
\(\frac{5^4.20^4}{25^5.4^5}=\frac{5^8.2^8}{5^{10}.42^{10}}=\frac{1}{100}\)
\(\left(-\frac{10}{3}\right)^5.\left(-\frac{6}{5}\right)^4=\left[\left(-\frac{10}{3}\right).\left(-\frac{6}{5}\right)\right]^4.\left(-\frac{10}{3}\right)=4^4.\left(-\frac{10}{3}\right)=-\frac{2560}{3}\)
a. \(\left(\frac{3}{7}+\frac{1}{2}\right)^2=\left(\frac{6+7}{14}\right)^2=\left(\frac{13}{14}\right)^2=\frac{13^2}{14^2}=\frac{169}{196}\)
b. \(\left(\frac{3}{4}-\frac{5}{6}\right)^2=\left(\frac{9-10}{12}\right)^2=\left(-\frac{1}{12}\right)^2=\frac{\left(-1\right)^2}{12^2}=\frac{1}{144}\)
c. \(\frac{5^4.20^4}{25^5.4^5}=\frac{\left(5.20\right)^4}{\left(25.4\right)^5}=\frac{100^4}{100^5}=\frac{1}{100}\)
d.\(\left(-\frac{10}{3}\right)^5.\left(-\frac{6}{5}\right)^4=\frac{\left(-10\right)^5}{3^5}.\frac{\left(-6\right)^4}{5^4}=\frac{\left(-2.5\right)^5.\left(-2.3\right)^4}{3^5.5^4}=\frac{\left(-2\right)^5.5^5.\left(-2\right)^4.3^4}{3^5.5^4}=\frac{\left(-2\right)^9.5}{3}=\frac{-512.5}{3}=-\frac{2560}{3}\)
tính
a) \(\left(\frac{3}{7}+\frac{1}{2}\right)^2\)
b)\(\left(\frac{3}{4}-\frac{5}{6}\right)^2\)
c)\(\frac{5^4.20^4}{25^5.4^5}\)
d)\(\left(\frac{10}{3}\right)^5.\left(\frac{-6}{5}\right)^4\)
a, \(\left(\frac{3}{7}+\frac{1}{2}\right)^2=\left(\frac{6}{14}+\frac{7}{14}\right)^2=\left(\frac{13}{14}\right)^2=\frac{169}{196}\)
b, \(\left(\frac{3}{4}-\frac{5}{6}\right)^2=\left(\frac{9}{12}-\frac{10}{12}\right)^2=\left(-\frac{1}{12}\right)^2=\frac{1}{144}\)
c, \(\frac{5^4.20^4}{25^5.4^5}=\frac{\left(5.20\right)^4}{\left(25.4\right)^5}=\frac{100^4}{100^5}=\frac{100^4}{100^4.100}=\frac{1}{100}\)
d, \(\left(\frac{10}{3}\right)^5.\left(-\frac{6}{5}\right)^4=\left(\frac{10}{3}\right)^4.\frac{10}{3}.\left(-\frac{6}{5}\right)^4=\left(\frac{10}{3}.-\frac{6}{5}\right)^4.\frac{10}{3}=\left(-4\right)^4.\frac{10}{3}=256.\frac{10}{3}=853\frac{1}{3}\)
Tính:
a) \(\left(\frac{3}{7}+\frac{1}{2}\right)^2\)
b) \(\left(\frac{3}{4}-\frac{5}{6}\right)^2\)
c) \(\frac{5^4.20^4}{25^5.4^5}\)
d) \(\left(\frac{-10}{3}\right)^5\) . \(\left(\frac{-6}{5}\right)^4\)
BN NÀO GIÚP MK, MK SẼ TICK.
tính
a) \(\frac{5^4.20^4}{25^5.4^5}\)
b) \(\left(\frac{-10}{3}\right)^5.\left(\frac{-6}{5}\right)^4\)
bài 1 :tính bằng cách hợp lí nhất : a) \(\frac{4}{5}\left(\frac{7}{2}+\frac{1}{4}\right)^2\)
b) \(\frac{5^4.20^4}{25^5.4^5}\)
bài 2 : tìm x và y biết x:2 = y: (-5) và x-y =10
bài 3 tìm x,y,z biết \(\left(x-\frac{1}{5}\right)^{2004}+\left(y+0,4\right)^{100}+\left(z-3\right)^{678}=0\)
Bài 1:
a)Ta có:
\(\frac{4}{5}\left(\frac{7}{2}+\frac{1}{4}\right)^2=\frac{4}{5}\left(\frac{15}{4}\right)^2=\frac{4}{5}.\frac{15}{4}.\frac{15}{4}=\frac{45}{4}\)
b)Ta có:
\(\frac{5^4.20^4}{25^5.4^5}=\frac{\left(5.20\right)^4}{\left(25.4\right)^5}=\frac{100^4}{100^5}=\frac{1}{100}\)
Bài 2:
Ta có:
\(\frac{x}{2}=\frac{y}{-5}=\frac{x-y}{2-\left(-5\right)}=\frac{10}{7}\)
\(\Rightarrow\left\{{}\begin{matrix}x=\frac{20}{7}\\y=\frac{-50}{7}\end{matrix}\right.\)
Bài 3:
Ta có:
\(\left\{{}\begin{matrix}\left(x-\frac{1}{5}\right)^{2004}\ge0\\\left(y+0,4\right)^{100}\ge0\\\left(z-3\right)^{678}\ge0\\\left(x-\frac{1}{5}\right)^{2004}+\left(y+0,4\right)^{100}+\left(z-3\right)^{678}=0\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}\left(x-\frac{1}{5}\right)^{2004}=0\\\left(y+0,4\right)^{100}=0\\\left(z-3\right)^{678}=0\\\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}\left(x-\frac{1}{5}\right)=0\\\left(y+0,4\right)=0\\\left(z-3\right)=0\\\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x=\frac{1}{5}\\y=-0,4\\z=3\\\end{matrix}\right.\)
tính:
a)\(\left(\frac{3}{7}+\frac{1}{2}\right)^2\)
b)\(\left(\frac{3}{4}-\frac{5}{6}\right)^2\)
c)\(\frac{5^4.20^4}{25^5.45}\)
giải hết giùm mình nhé
a) Ta có :
\(\left(\frac{3}{7}+\frac{1}{2}\right)^2\)
= \(\left(\frac{6}{14}+\frac{7}{14}\right)^2\)
= \(\left(\frac{13}{14}\right)^2\)
= \(\frac{169}{196}\)
b)
\(\left(\frac{3}{4}-\frac{5}{6}\right)^2\)
= \(\left(\frac{18}{24}-\frac{20}{24}\right)^2\)
= \(\left(\frac{-1}{12}\right)^2\)
= \(\frac{1}{144}\)