phan tich da thuc thanh nhan tu
a)x^4+x^2y^2+y^4
b)x^3+3x-4
c)x^2+9x+8
d)x^2+x-42
e)y^2-13y+12
f)x^2-x-30
g)2x^2+xy-y^2
h)y^2-y-12
i)x^2+x-2
j)x^3+3x^2-2
k)x^3-6x^2+16
l)x^3+3x+4
m)x^4+6x^3-12x^2-8x
minh can gap lam, chiu nay la minh hoc roi
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phan tich da thuc thanh nhan tu
a)x^4+x^2y^2+y^4
b)x^3+3x-4
c)x^2+9x+8
d)x^2+x-42
e)y^2-13y+12
f)x^2-x-30
g)2x^2+xy-y^2
h)y^2-y-12
i)x^2+x-2
j)x^3+3x^2-2
k)x^3-6x^2+16
l)x^3+3x+4
m)x^4+6x^3-12x^2-8x
a. x4 + x2y2 + y4 = (x4 + 2x2y2 + y4) - x2y2
= (x2 + y2)2 – (xy)2
= [(x2 + y2) + xy] [(x2 + y2) – xy]
= (x2 + xy + y2)(x2 –xy + y2)
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h, \(y^2-y-12\)
\(=y^2-4x+3y-12\)
\(=\left(y-4\right)\left(y+3\right)\)
\(i,x^2+x-2\)
\(=x^2+2x-x-2\)
\(=\left(x+2\right)\left(x-1\right)\)
\(j,x^3+3x^2-2\)
\(=x^3+2x^2+x^2-2x+2x-2\)
\(=x^2\left(x+1\right)+2x\left(x+1\right)-2\left(x+1\right)\)
\(=\left(x+1\right)\left(x^2+2x-2\right)\)
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phan tich cac da thuc sau thanh nhan tu theo mau:
2x^3-x
5x^2(x-1)-15x(x-1)
3x^2y^2+12x^2y-15x-y^2
3x(x-2y)+6y(2y-x)
phan tich cac da thuc sau thanh nhan tu theo mau:
a)\(2x^3-x\)
\(=x\left(2x^2-1\right)\)
\(=x\left(\left(\sqrt{2}x\right)^2-1^2\right)\)\
\(=x\left(\sqrt{2}x-1\right)\left(\sqrt{2}x+1\right)\)
b)\(5x^2\left(x-1\right)-15x\left(x-1\right)\)
\(=\left(5x^2-15x\right)\left(x-1\right)\)
\(=5x\left(x-3\right)\left(x-1\right)\)
d)\(3x\left(x-2y\right)+6y\left(2y-x\right)\)
\(=3x\left(x-2y\right)-6y\left(x-2y\right)\)
\(=\left(3x-6y\right)\left(x-2y\right)\)
\(=3\left(x-2y\right)\left(x-2y\right)\)
\(=3\left(x-2y\right)^2\)
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1. phan tich da thuc thanh nhan tu
a. x^2+3x-5 b. 4x^2-16x+7 c. 5x^2-6x-7 d.x^4+2x^3-4x-4
2. tim x,y bt: x^2+y^2+z^2=xy+yz+zx va x^2012+y^2012+z^2012= 3^2013
3. tim x: a. x^2-4x=21 b. x^2-4x+4=0 c.x^2-6x=2x=11 d. 4^x-12.2^x+32=0
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Phan tich da thuc thanh nhan tu
1) (2x+1)^2 - (x-1)^2
2) 9(x+3)^2 - 4(x-2)^2
3) 25(2x - y) ^2 - 16(x+2y)^2
4) x^4 + x^3 +x + 1
5) x^3 + 3x^2 + 3x + 1 -8y^3
phan tich da thuc thanh nhan tu:
a,x^4-2x^3-12x^2+12x+36
b,x^4+x^3+6x^2+5x+5
c,x^8y^8+x^4y^4+1
d,x^5-x^4+x^3-X^2+x-1
e,x^5+x^4-X63+x62-x+2
g,x(Y^2-z^2)+y(z^2-x^2)+z(x^2-y^2)
Phan tich da thuc thanh nhan tu :
a) (3x - 2)(5x - 4) - 2(x - 1)(4x - 3) - (2 - 3x)2
b)(9x - 8)3 - (x - x)(x2 + 2x + 1) - (8 - 9x)2
c) (x2y - 4)2 + 4(x2 + y)2
Phan tich da thuc thanh nhan tu:
x^3 - x + 3x^2y + 3xy^2 + y^3 - y
x^2 + 5x - 6
x^3 - x + 3x^2y + 3xy^2 + y^3 - y
=x3+y3+3x2y+3xy2-x-y
=(x+y)(x2-xy+y2)+3xy(x+y)-(x+y)
=(x+y)(x2-xy+y2+3xy-1)
=(x+y)(x2+2xy+y2-1)
=(x+y)[(x+y)2-1]
=(x+y)(x+y-1)(x+y+1)
x^2 + 5x - 6
=x2-x+6x-6
=x.(x-1)+6.(x-1)
=(x-1)(x+6)
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Phan tich da thuc sau thanh nhan tu ( giup minh voi cac ban oi : )
1/ x3 + 2x + x2
2/ 2x3 + 4x2 + 2x
3/ -3x3 - 5x2 + 8x
4/ x2 + 4x - 5
5/ 6x2 - 3x - 3
6/ 3x2 - 2x -5
7/ 3x2 - 2x -5
8/ x2 - 2x - 4y2 - 4y
9/ x3 + 2x2y + xy2 - 9x
10/ x2 - y2 + 6x +9
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Phan tich da thuc sau thanh nhan tu ( giup minh voi cac ban oi :<< )
1/ x3 + 2x + x2
2/ 2x3 + 4x2 + 2x
3/ -3x3 - 5x2 + 8x
4/ x2 + 4x - 5
5/ 6x2 - 3x - 3
6/ 3x2 - 2x -5
7/ 3x2 - 2x -5
8/ x2 - 2x - 4y2 - 4y
9/ x3 + 2x2y + xy2 - 9x
10/ x2 - y2 + 6x +9
\(1.x^3+2x+x^2=x\left(x^2+x+2\right)\)
\(2.2x^3+4x^2+2x=2x\left(x^2+2x+1\right)=2x\left(x+1\right)^2\)
\(3.-3x^3-5x^2+8x=-3x^3+3x^2-8x^2+8x\)
\(=-3x^2\left(x-1\right)-8x\left(x-1\right)=\left(3x^2+8x\right)\left(1-x\right)\)
\(=x\left(3x+8\right)\left(1-x\right)\)
\(4.x^2+4x-5=x^2-x+5x-5=\left(x-1\right)\left(x+5\right)\)
\(5.6x^2-3x-3=6x^2-6x+3x-3=3\left(x-1\right)\left(2x+1\right)\)
\(6.3x^2-2x-5=3x^2+3x-5x-5=\left(x+1\right)\left(3x-5\right)\)
\(8.x^2-2x-4y^2-4y=\left(x-2y\right)\left(x+2y\right)-2\left(x+2y\right)\)\(=\left(x+2y\right)\left(x-y-2\right)\)
\(9.x^3+2x^2y+xy^2-9x=x\left(x^2+2xy+y^2-9\right)\)
\(=x\left(x+y-3\right)\left(x+y+3\right)\)
\(10.x^2-y^2+6x+9=\left(x+3-y\right)\left(x+3+y\right)\)
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phan tich da thuc sau thanh nhan tu:
a) (3x-2)(4x-3)-(2-3x)(x-1)-2(3x-2)(x+1)
b) x^2(y-z)+y^2(z-x)+z^2(x-y)