Biết lên mạng mà ko biết vào máy tính ak

Biết lên mạng mà ko biết vào máy tính ak

\(\frac{38}{45}-\left(\frac{8}{45}-\frac{17}{51}-\frac{3}{11}\right)\)

\(=\left(\frac{38}{45}-\frac{8}{45}\right)-\left(\frac{17}{51}-\frac{3}{11}\right)\)

\(=\frac{2}{3}-\frac{2}{33}\)

\(=\frac{20}{33}\)

Học tốt # ^-<

bằng \(\frac{4831}{3960}\)

\(\frac{38}{48}-\left(\frac{8}{45}-\frac{17}{51}-\frac{3}{11}\right)\)

\(=\frac{38}{48}-\left(-\frac{212}{495}\right)\)

\(=\frac{4831}{3960}\)

\(A=\frac{38}{45}-\left(\frac{8}{45}-\frac{17}{51}-\frac{3}{11}\right)\)

\(A=\frac{38}{45}-\frac{8}{45}+\frac{17}{51}+\frac{3}{11}\)

\(A=\left(\frac{38}{45}-\frac{8}{45}\right)+\frac{1}{3}+\frac{3}{11}\)

\(A=\left(\frac{2}{3}+\frac{1}{3}\right)+\frac{3}{11}\)

\(A=1+\frac{3}{11}\)

\(A=\frac{11}{11}+\frac{3}{11}=\frac{14}{11}\)

\(B=\left(\frac{1}{2}+1\right).\left(\frac{1}{3}+1\right).\left(\frac{1}{4}+1\right)...\left(\frac{1}{99}+1\right)\)

\(B=\frac{3}{2}.\frac{4}{3}.\frac{5}{4}.\frac{6}{5}...\frac{100}{99}\)

\(B=\frac{3.4.5.6...100}{2.3.4.5...99}\)

\(B=\frac{100}{2}\)

\(B=50\)

a)

\(\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\left(\frac{79}{67}-\frac{28}{41}\right)\)

= \(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}-\frac{79}{67}+\frac{28}{41}\)

= \(\frac{1}{3}+\left(\frac{12}{67}-\frac{79}{67}\right)+\left(\frac{13}{41}+\frac{28}{41}\right)\)

= \(\frac{1}{3}+\left(-1\right)+1\)

= \(\frac{1}{3}+0=\frac{1}{3}\)

b)

\(\frac{38}{45}-\left(\frac{8}{45}-\frac{17}{51}-\frac{3}{11}\right)\)

= \(\frac{38}{45}-\frac{8}{45}+\frac{17}{51}+\frac{3}{11}\)

= \(\left(\frac{38}{45}-\frac{8}{45}\right)+\left(\frac{17}{51}+\frac{3}{11}\right)\)

= \(\frac{2}{3}+\frac{20}{33}\)

= \(\frac{14}{11}\)

Trả lời

b)(1/3+12/67+13/41)-(79/67-28/41)

=1/3+12/67+13/41-79/67+28/41

=1/3+(12/67-79/67)+(13/41+28/41)

=1/3+(-67/67)+41/41

=1/3+(-1)+1

=1/3+0

=1/3.

c)38/45-(8/45-17/51-3/11)

=38/45-8/45+17/51+3/11

=30/45+1/3+3/11

=2/3+1/3+3/11

=3/3+3/11

=1+3/11

=1 3/11.

d)(17/28+18/29-19/30-30/31).(-5/12+1/4+1/6)

=(17/28+18/29+19/30+30/31).(-5+3+2/12)

=(17/28+18/29+19/30+30/31).0

=0.

\(A=\frac{\left(1+2+...+100\right)\left(\frac{1}{2}^2-...-\frac{1}{5}\right)\left(2,4.42-21.4,8\right)}{1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{100}}\)

=> \(A=\frac{\left(1+2+...+100\right)\left(\frac{1}{2}-...-\frac{1}{5}\right).0}{1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{100}}\)=     0

D = \(\frac{9}{4}+\frac{1}{16}-\frac{1}{8}\)

D = \(\frac{35}{16}\)

\(D=\left(\frac{3}{2}\right)^2+\left(\frac{1}{4}\right)^2-\left(\frac{1}{2}\right)^3\)

\(D=\frac{9}{4}+\frac{1}{16}-\frac{1}{8}\)

\(D=\frac{37}{16}-\frac{1}{8}\)

\(D=\frac{35}{16}.\)

Chúc bạn học tốt!