1/30 + 1/42 + 1/56 + 1/72 +...+ 2/x(x+1)
x-1/12 x-1/20 x-1/30 x-1/42 x-1/56 x-1/72=224
tìm x biết 1/30 + 1/42+1/56+1/72+1/90+1/110+1/132 - x=2/3
Tìm x biết : 1/30 + 1/42 +1/56 +1/72 + 1/90 + 1/110 + 1/132 - x = 2/3
Tìm x biết 1/30+1/42+1/56+1/72+1/90+1/110+1/132 -x = 2/3
Ta có:
1/30+1/42+1/56+1/72+1/90+1/110+1/132 -x = 2/3
=>1/(5.6) + 1/(6.7) + 1/(7.8) + (1/8.9) + 1/(9.10) + 1/(10.11) + 1/(11.12) - x = 2/3
=>1/5-1/6+1/6-1/7+...+1/11-1/12 - x = 2/3
=>1/5-1/12 - x = 2/3
=>7/60 - x = 2/3
=> x = 7/60 - 2/3
=> x = -11/20
Ta có:
1/30+1/42+1/56+1/72+1/90+1/110+1/132 -x = 2/3
=>1/(5.6) + 1/(6.7) + 1/(7.8) + (1/8.9) + 1/(9.10) + 1/(10.11) + 1/(11.12) - x = 2/3
=>1/5-1/6+1/6-1/7+...+1/11-1/12 - x = 2/3
=>1/5-1/12 - x = 2/3
=>7/60 - x = 2/3
=> x = 7/60 - 2/3
=> x = -11/20
1/30+1/42+1/56+1/72+1/90+1/110+1/132=21/x
\(\Rightarrow\dfrac{1}{5\times6}+\dfrac{1}{6\times7}+\dfrac{1}{7\times8}+...+\dfrac{1}{11\times12}=\dfrac{21}{x}\\ \Rightarrow\dfrac{1}{5}-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{7}+...+\dfrac{1}{11}-\dfrac{1}{12}=\dfrac{21}{x}\\ \Rightarrow\dfrac{1}{5}-\dfrac{1}{12}=\dfrac{21}{x}\\ \Rightarrow\dfrac{21}{x}=\dfrac{7}{60}\Rightarrow x=\dfrac{21\cdot60}{7}=180\)
\(\dfrac{1}{30}+\dfrac{1}{42}+\dfrac{1}{56}+\dfrac{1}{72}+\dfrac{1}{90}+\dfrac{1}{110}+\dfrac{1}{132}=\dfrac{21}{x}\)
\(\dfrac{1}{5.6}+\dfrac{1}{6.7}+\dfrac{1}{7.8}+\dfrac{1}{8.9}+\dfrac{1}{9.10}+\dfrac{1}{10.11}+\dfrac{1}{11.12}=\dfrac{21}{x}\)
\(\dfrac{1}{5}-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{7}+\dfrac{1}{8}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{10}+\dfrac{1}{10}-\dfrac{1}{11}+\dfrac{1}{11}-\dfrac{1}{12}=\dfrac{21}{x}\)
\(\dfrac{1}{5}-\dfrac{1}{12}=\dfrac{21}{x}\)
Còn lại bạn tự tính
20/9-x=1/12+1/20+1/30+1/42+1/56+1/72
\(\frac{20}{9}-x=\frac{1}{12}+\frac{1}{20}+.........+\frac{1}{72}\)
\(\Rightarrow\frac{20}{9}-x=\frac{1}{3.4}+\frac{1}{4.5}+.......+\frac{1}{8.9}\)
\(\Rightarrow\frac{20}{9}-x=\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+........+\frac{1}{8}-\frac{1}{9}\)
\(\Rightarrow\frac{20}{9}-x=\frac{1}{3}-\frac{1}{9}\)
\(\Rightarrow\frac{20}{9}-x=\frac{2}{9}\)
\(\Rightarrow x=\frac{20}{9}-\frac{2}{9}\)
\(\Rightarrow x=\frac{18}{9}=2\)
20/9 -x= 1/3.4 +1/4.5+1/5.6+ 1/6.7+1/7.8+1/8.9
=1/3+1/4+1/4+1/5+1/5+1/6+1/6+1/7+1/7+1/8+1/8+1/9+1/9
20/9 -x= 1/3
x=20/9-1/3
x= 17/9
Nhớ tích (đúng) cho mình nha
20/9-x=1/12+1/20+1/30+1/42+1/56+1/72
20/9-x=1/3.4+1/4.5+1/5.6+.............+1/8.9
20/9-x=1/3-1/4+1/4-1/5+................+1/8-1/9
20/9-x=1/3-1/9
20/9-x=2/9
x=20/9-2/9
x=18/9
Chọn (k) đúng cho mình nha !!!!!!!!!!!
20/9.x=1/12+1/20+1/30+1/42+1/56+1/72
\(\frac{20}{9}x=\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}\)
\(\frac{20}{9}x=\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}\)
\(\frac{20}{9}x=\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-.....-\frac{1}{9}\)
\(\frac{20}{9}x=\frac{1}{3}-\frac{1}{9}=\frac{2}{9}\)
\(x=\frac{2}{9}:\frac{20}{9}=\frac{1}{10}\)
20/9 . x = 1/12 + 1/20 + 1/30 + 1/42 + 1/56 + 1/72
20/9 . x = 1/3.4 + 1/4.5 + 1/5.6 + 1/6.7 + 1/7.8 + 1/8.9
20/9 . x = 1/3 - 1/4 + 1/4 - 1/5 + ... + 1/8 - 1/9
20/9 . x = 1/3 - 1/9 = 2/9
x = 2/9 : 20/9 = 2/9 . 9/20 = 1/10
Vậy x = 1/10
Tìm x,biết
x-1/12+x-1/20+x-1/30+x-1/42+x-1/56+x-1/72+x-1/90=?
B= 1/3 - 1/12 - 1/20 - 1/30 - 1/42 - 1/56 - 1/72 - 1/90
2x - 3 = x + 1/2