(3,25\(-\frac{2}{3}x\))\(\div\)(\(\frac{-7}{4}\))=\(-3\)giúp mk vs ak
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Mấy bn ơi, giúp mk vs
Tìm x, biết:
\(x-0,27=\frac{\frac{73}{77}+\frac{73}{165}+\frac{73}{285}}{25\times\left(\frac{5}{84}+\frac{3}{180}+\frac{4}{285}\right)}\)
Tính P;
\(P=\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right)\times230\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{3}{7}+\frac{10}{3}\right)\div\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
Ai đúng mk tích, cảm ơn các bn
Tìm x :
x - 0,27 = \(\frac{73}{100}\)
x = \(\frac{73}{100}+0,27\)
x = 1
Cậu P khó quá mik chưa nghĩ ra cách tính nhanh nhất !
Cậu tự giải nhé !
Hok tốt
\(x-0,27=\frac{\frac{73}{77}+\frac{73}{165}+\frac{73}{285}}{25\times\left(\frac{5}{84}+\frac{3}{180}+\frac{4}{285}\right)}.\)
\(x-0,27=\frac{\frac{146}{105}+\frac{73}{285}}{25\times\left(\frac{8}{105}+\frac{4}{285}\right)}\)
\(x-0,27=\frac{\frac{219}{133}}{25\times\frac{12}{133}}\)
\(x-0,27=\frac{\frac{219}{133}}{\frac{300}{133}}\)
\(x-0,27=0,73\)
\(x=0,73+0,27\)
\(x=1\)
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Rút gọn rồi tính giá trị của biểu thứcsqrt{frac{sqrt{a}-1}{sqrt{b}+1}}divsqrt{frac{sqrt{b}-1}{sqrt{a}+1}}vớia7,25;b3,25 frac{a-b}{sqrt{atimesleft(a+2times bright)+b^2}}divsqrt{frac{left(a-bright)^2}{atimesleft(a+bright)}}vớiab0vàfrac{a}{b}frac{9}{7} frac{x-1}{sqrt{y}-1}timessqrt{frac{left(y-2timessqrt{y}+1right)^2}{left(x-1right)^4}}vớixfrac{-1}{2};y121; giúp mk vs
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Rút gọn rồi tính giá trị của biểu thức
\(\sqrt{\frac{\sqrt{a}-1}{\sqrt{b}+1}}\div\sqrt{\frac{\sqrt{b}-1}{\sqrt{a}+1}}vớia=7,25;b=3,25\)
\(\frac{a-b}{\sqrt{a\times\left(a+2\times b\right)+b^2}}\div\sqrt{\frac{\left(a-b\right)^2}{a\times\left(a+b\right)}}vớia>b>0và\frac{a}{b}=\frac{9}{7}\)
\(\frac{x-1}{\sqrt{y}-1}\times\sqrt{\frac{\left(y-2\times\sqrt{y}+1\right)^2}{\left(x-1\right)^4}}vớix=\frac{-1}{2};y=121\); giúp mk vs
a ) 4frac{5}{9}div(-frac{5}{7})+frac{4}{9}divfrac{left(-5right)}{7}b ) (-frac{3}{5}+frac{4}{9})divfrac{7}{11}+(frac{-2}{5}+frac{5}{9})divfrac{7}{11}c ) frac{6}{7}div(frac{3}{26}-frac{3}{13})+frac{6}{7}div(frac{1}{10}-frac{8}{5})d ) A(2+4+6+........+100)orbr{begin{cases}35end{cases}}div0,7+3(frac{-2}{7})]div(frac{1}{2}+frac{1}{4}+frac{1}{6}+......+frac{1}{100})Giải cụ thể hộ mk vs
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a ) 4\(\frac{5}{9}\)\(\div\)\((-\frac{5}{7})\)\(+\frac{4}{9}\div\frac{\left(-5\right)}{7}\)
b ) \((-\frac{3}{5}+\frac{4}{9})\div\frac{7}{11}+(\frac{-2}{5}+\frac{5}{9})\div\frac{7}{11}\)
c ) \(\frac{6}{7}\div(\frac{3}{26}-\frac{3}{13})+\frac{6}{7}\div(\frac{1}{10}-\frac{8}{5})\)
d ) \(A=(2+4+6+........+100)\orbr{\begin{cases}3\\5\end{cases}}\div0,7+3(\frac{-2}{7})]\div(\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+......+\frac{1}{100})\)
Giải cụ thể hộ mk vs
\(a,4\frac{5}{9}:\frac{\left(-5\right)}{7}+\frac{4}{9}:\frac{-5}{7}\)
\(=\frac{41}{9}.\frac{-7}{5}+\frac{4}{9}.\frac{-7}{5}\)
\(=\frac{-7}{5}.\left(\frac{41}{9}+\frac{4}{9}\right)\)
\(=-\frac{7}{9}.5\)
\(=-7\)
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a)Bn Kaito Kid làm rùi!
B)Không viết lại đề
\(=\frac{11}{7}\cdot\left(-\frac{3}{5}+\frac{4}{9}-\frac{2}{5}+\frac{5}{9}\right)=\frac{11}{7}\cdot0=0\)
c)Không viết lại đề
\(A=\left(2+4+...+100\right)\left(\frac{3}{5}\cdot\frac{10}{7}-\frac{6}{7}\right):\left(\frac{1}{2}+\frac{1}{4}+...+\frac{1}{100}\right)\)
\(=\left(2+4+6+...+100\right)\cdot0\cdot\left(\frac{1}{2}+\frac{1}{4}+...+\frac{1}{100}\right)=0\)
\(=\frac{7}{6}\cdot\left(\frac{3}{26}-\frac{3}{13}+\frac{1}{10}-\frac{8}{5}\right)=\frac{7}{6}\left(\frac{-3}{26}+\frac{-17}{10}\right)=\frac{7}{6}\cdot\frac{236}{130}=\frac{413}{195}\)
D)
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Dòng trên chữ D) là phần c)
Dưới phần c) là phần d) nha!(Lỗi đánh máy)
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.giúp mk tính từng bước vs ạ\(\frac{5}{7}.\left(\frac{1}{2}-\frac{1}{3}+\frac{4}{7}\right)+\left(\frac{1}{3}-\frac{1}{2}-\frac{4}{7}\right)-\frac{7}{5}\)
\(x.3\frac{1}{4}+\left(-\frac{7}{6}\right).x-1\frac{2}{3}=\frac{5}{12}\)
Giải hộ vs ak
kết quả bằng 1 nếu muốn giải cụ thể thì kết bạn
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=> x.13/4 + -7/6. x - 5/3 = 5/12
=> x. (13/4 + -7/6 - 5/3) = 5/12
=> x. 5/12 = 5/12
=> x = 5/12:5/12
=> x = 5/12.12/5
=> x = 1
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\(x\times3\frac{1}{4}+-\frac{7}{6}x-1\frac{2}{3}=\frac{5}{12}\)
\(\Leftrightarrow\left[3\frac{1}{4}+\left(-\frac{7}{6}\right)\right]x-1\frac{2}{3}=\frac{5}{12}\)
\(\Leftrightarrow\frac{25}{12}x=\frac{5}{12}+1\frac{2}{3}\)
\(\Leftrightarrow\frac{25}{12}x=\frac{25}{12}\)
\(\Rightarrow x=\frac{25}{12}\div\frac{25}{12}=1\). Vậy x = 1.
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a)\(\left(\frac{3}{4}x-\frac{9}{16}\right)\times\left(1,5+\frac{-3}{5}\div x\right)=0\)
Giải hộ mk vs mk đng cần gấp
\(\left(\frac{3}{4}x-\frac{9}{16}\right)\cdot\left(1,5+\frac{-3}{5}:x\right)=0\\ \Rightarrow\left[{}\begin{matrix}\frac{3}{4}x-\frac{9}{16}=0\\1,5+\frac{-3}{5}:x=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}\frac{3}{4}x=\frac{9}{16}\\\frac{-3}{5}:x=-1,5\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\frac{3}{4}\\x=\frac{2}{5}\end{matrix}\right.\)
Vậy \(x\in\left\{\frac{3}{4};\frac{2}{5}\right\}\)
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a.frac{x-6}{7}+frac{x-7}{8}+frac{x-8}{9}frac{x-9}{10}+frac{x-10}{11}+_{frac{x-11}{12}}b.frac{x-1}{2020}+frac{x-2}{2019}-frac{x-3}{2018}frac{x-4}{2017}c.left(frac{3}{4}x+3right)-left(frac{2}{3}x-4right)-left(frac{1}{6}x+1right)left(frac{1}{3}x+4right)-left(frac{1}{3}x-3right)giúp mk vs mk đg cần gấpThank you
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a.\(\frac{x-6}{7}+\frac{x-7}{8}+\frac{x-8}{9}=\frac{x-9}{10}+\frac{x-10}{11}+_{\frac{x-11}{12}}\)
b.\(\frac{x-1}{2020}+\frac{x-2}{2019}-\frac{x-3}{2018}=\frac{x-4}{2017}\)
c.\(\left(\frac{3}{4}x+3\right)-\left(\frac{2}{3}x-4\right)-\left(\frac{1}{6}x+1\right)=\left(\frac{1}{3}x+4\right)-\left(\frac{1}{3}x-3\right)\)
giúp mk vs mk đg cần gấp
Thank you
a) \(\frac{x-6}{7}+\frac{x-7}{8}+\frac{x-8}{9}=\frac{x-9}{10}+\frac{x-10}{11}+\frac{x-11}{12}\)
=> \(\left(\frac{x-6}{7}+1\right)+\left(\frac{x-7}{8}+1\right)+\left(\frac{x-8}{9}+1\right)=\left(\frac{x-9}{10}+1\right)+\left(\frac{x-10}{11}+1\right)+\left(\frac{x-11}{12}+1\right)\)
=> \(\frac{x+1}{7}+\frac{x+1}{8}+\frac{x+1}{9}-\frac{x+1}{10}-\frac{x+1}{11}+\frac{x+1}{12}=0\)
=> \(\left(x+1\right)\left(\frac{1}{7}+\frac{1}{8}+\frac{1}{9}-\frac{1}{10}-\frac{1}{11}-\frac{1}{12}\right)=0\)
=> x + 1 = 0
=> x = -1
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b) \(\frac{x-1}{2020}+\frac{x-2}{2019}-\frac{x-3}{2018}=\frac{x-4}{2017}\)
=> \(\left(\frac{x-1}{2020}-1\right)+\left(\frac{x-2}{2019}-1\right)-\left(\frac{x-3}{2018}-1\right)=\left(\frac{x-4}{2017}-1\right)\)
=> \(\frac{x-2021}{2020}+\frac{x-2021}{2019}-\frac{x-2021}{2018}=\frac{x-2021}{2017}\)
=> \(\left(x-2021\right)\left(\frac{1}{2020}+\frac{1}{2019}-\frac{1}{2018}-\frac{1}{2017}\right)=0\)
=> x - 2021 = 0
=> x = 2021
c) \(\left(\frac{3}{4}x+3\right)-\left(\frac{2}{3}x-4\right)-\left(\frac{1}{6}x+1\right)=\left(\frac{1}{3}x+4\right)-\left(\frac{1}{3}x-3\right)\)
=> \(\frac{3}{4}x+3-\frac{2}{3}x+4-\frac{1}{6}x-1=\frac{1}{3}x+4-\frac{1}{3}x+3\)
=> \(-\frac{1}{12}x+6=7\)
=> \(-\frac{1}{12}x=1\)
=> x = -12
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Tìm\(x\inℚ\)thỏa mãn:
\(\frac{x-1}{1}+\frac{x-1}{2}=\frac{x}{3}+\frac{x}{4}-\frac{7}{12}\)
Giúp mk vs
Cảm ơn nhiều ạ!!
\(\frac{x-1}{1}+\frac{x-1}{2}=\frac{x}{3}+\frac{x}{4}-\frac{7}{12}\)
\(\Leftrightarrow\frac{12x-12}{12}+\frac{6x-6}{12}=\frac{4x}{12}+\frac{3x}{12}-\frac{7}{12}\)
Khử mẫu : \(12x-12+6x-6=4x+3x-7\)
\(\Leftrightarrow18x-18=7x-7\Leftrightarrow11x=11\Leftrightarrow x=1\)
\(\frac{x-1}{1}+\frac{x-1}{2}=\frac{x}{3}+\frac{x}{4}-\frac{7}{12}\)
\(\Leftrightarrow\frac{12x-12}{12}+\frac{6x-6}{12}=\frac{4x}{12}+\frac{3x}{12}-\frac{7}{12}\)
\(\Leftrightarrow\frac{12x-12+6x-6}{12}=\frac{4x+3x-7}{12}\)
\(\Leftrightarrow18x-18=7x-7\)
\(\Leftrightarrow18x+7x=18+7\)
\(\Leftrightarrow25x=25\)
\(\Leftrightarrow x=1\)
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\([18\frac{1}{6}-\left(0.06:7\frac{1}{2}+3\frac{2}{5}.0.38\right)]:\left(19-2\frac{2}{3}.4\frac{3}{4}\right)\)
Giải giúp mk vs nha các bn